poj 1887 Testing the CATCHER_最长上升子序列

题意：题目太长没看，直接看输入输出猜出是最长下降子序列

用了以前的代码直接a了，做法类似贪心，把最小的顺序数存在数组里面，每次二分更新数组得出最长上升子序列

#include<iostream>
#include<cstdio>
using namespace std;
int main()
{
	int dp[40002],a[40002],n,t,i,low,up,top,mid,max,tmp,k,b[40002],cas=1;
	while(1)
	{
		scanf("%d",&tmp);
		if(tmp==-1)
			break;
		k=1;
		b[k++]=tmp;
		while(scanf("%d",&tmp)){
			if(tmp==-1)
				break;
			b[k++]=tmp;

		}
		k--;
		for(i=1;i<=k;i++)
			a[i]=b[k-i+1];
		top=1;
		dp[1]=a[1];
		max=0;
		for(i=1;i<=k;i++)
		{
			low=1;
			up=top;
			while(low<=up)
			{
				mid=(low+up)/2;
				if(dp[mid]>=a[i])
					up=mid-1;
				else
					low=mid+1;
			}
			dp[low]=a[i];
			if(low>top)
				top++;
		}
		printf("Test #%d:\n",cas++);
		printf("  maximum possible interceptions: %d\n\n",top);
	}
	return 0;
}