在 Swift 语言中更好的处理 JSON 数据：SwiftyJSON

SwiftyJSON能够让在Swift语言中更加简便处理JSON数据。

With SwiftyJSON all you have to do is:

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let json = JSONValue(dataFromNetworking) if let userName = json[0]["user"]["name"].string{   //Now you got your value }

And don't worry about the Optional Wrapping thing, it's done for you automatically

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let json = JSONValue(dataFromNetworking) if let userName = json[999999]["wrong_key"]["wrong_name"].string{   //Calm down, take it easy, the ".string" property still produces the correct Optional String type with safety }

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let json = JSONValue(jsonObject) switch json["user_id"]{ case .JString(let stringValue):     let id = stringValue.toInt() case .JNumber(let numberValue):     let id = numberValue.integerValue default:     println("ooops!!! JSON Data is Unexpected or Broken")

Error Handling

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let json = JSONValue(dataFromNetworking)["some_key"]["some_wrong_key"]["wrong_name"] if json{   //JSONValue it self confirm to Protocol "LogicValue", with JSONValue.JInvalid produce false and others produce true }else{   println(json)   //> JSON Keypath Error: Incorrect Keypath "some_wrong_key/wrong_name"   //It always tells you where your key starts went wrong   switch json{   case .JInvalid(let error):     //An NSError containing detailed error information   } }

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