leetcode-数组的相对排序

Python解法：

def relativeSortArray(arr1, arr2):
    arr = [0 for _ in range(110)]
    new = []
    for a in range(len(arr1)):
        arr[arr1[a]] += 1
    for b in range(len(arr2)):
        while arr[arr2[b]] > 0:
            new.append(arr2[b])
            arr[arr2[b]] -= 1
    for c in range(len(arr)):
        while arr[c] > 0:
            new.append(c)
            arr[c] -= 1
    return new

print(relativeSortArray([2,3,1,3,2,4,6,7,9,2,19], [2,1,4,3,9,6]))

res = []
for i in arr2:
    while i in arr1:
        res.append(i)
        arr1.remove(i)
return res + sorted(arr1)