latex · markdown | 如何写矩阵和大公式

1

\left[\begin{array}{c}
	a & b \\
	c & d
\end{array}\right]

效果：

\[\left[\begin{array}{c}
a & b \\
c & d
\end{array}\right]
\]

2

\min_{T_t^{set}}J=\lim_{N\rarr\infin}E\bigg\{\sum_{t=0}^{N-1}\Delta t\cdot P_t(T_t^{set},T_t^{sup})\bigg\}
\\
s.t.\left\{\begin{array}{c}
	[\boldsymbol  T^{out}, T^{sup}]_{t+1}
	=
	f([\boldsymbol  T^{out}, T^{sup}]_{t}, \boldsymbol H_{t}^{ite}, T_{t}^{set} )
	\\
	T^{out}_{min} \le T^{out} \le T^{out}_{max} \\
	0 \le H_{t}^{ite} \le 1
\end{array}\right.
\tag 4

效果：

\[\min_{T_t^{set}}J=\lim_{N\rightarrow\infty}E\bigg\{\sum_{t=0}^{N-1}\Delta t\cdot P_t(T_t^{set},T_t^{sup})\bigg\}
\]

\[s.t.\left\{\begin{array}{c}
[\boldsymbol T^{out}, T^{sup}]_{t+1}
=
f([\boldsymbol T^{out}, T^{sup}]_{t}, \boldsymbol H_{t}^{ite}, T_{t}^{set} )
\\
T^{out}_{min} \le T^{out} \le T^{out}_{max} \\
0 \le H_{t}^{ite} \le 1
\end{array}\right.
\tag 4
\]