*[hackerrank]Cut the tree
https://www.hackerrank.com/contests/w2/challenges/cut-the-tree
树分成两部分,求两部分差最小。一开始想多了,后来其实求一下总和,求一下分部的和就行了。
#include <cstdlib>
#include <climits>
#include <algorithm>
#include <iostream>
#include <vector>
using namespace std; vector<vector<int>> tree;
vector<bool> visited;
vector<int> val;
int totalVal; int subSum(int root, int& minCut) {
int sum = 0;
visited[root] = true;
for (int i = 0; i < tree[root].size(); i++) {
int sub = tree[root][i];
if (visited[sub])
continue;
int x = subSum(sub, minCut);
sum += x;
}
sum += val[root];
minCut = min(minCut, abs(totalVal - 2 * sum));
return sum;
}
int main() {
int N;
cin >> N;
tree.resize(N + 1);
visited.resize(N + 1);
val.resize(N + 1);
totalVal = 0;
for (int i = 1; i <= N; i++) {
cin >> val[i];
totalVal += val[i];
}
for (int i = 0; i < N - 1; i++) {
int a, b;
cin >> a >> b;
tree[a].push_back(b);
tree[b].push_back(a);
}
int minCut = INT_MAX;
// pick 1 as root
subSum(1, minCut);
cout << minCut << endl;
return 0;
}
*[hackerrank]Cut the tree的更多相关文章
- 【HackerRank】Cut the tree
题目链接:Cut the tree 题解:题目要求求一条边,去掉这条边后得到的两棵树的节点和差的绝对值最小. 暴力求解会超时. 如果我们可以求出以每个节点为根的子树的节点之和,那么当我们去掉一条边(a ...
- HackerRank "Self Balancing Tree"
Something to learn: Rotation ops in AVL tree does not require recursion. https://github.com/andreima ...
- 【HackerRank】Utopian tree
The Utopian tree goes through 2 cycles of growth every year. The first growth cycle of the tree occu ...
- HackerRank "Kundu and Tree" !!
Learnt from here: http://www.cnblogs.com/lautsie/p/3798165.html Idea is: we union all pure black edg ...
- the apple tree
the apple tree A long time ago, there was a huge apple tree. A little boy loved to come and lay arou ...
- Factoextra R Package: Easy Multivariate Data Analyses and Elegant Visualization
factoextra is an R package making easy to extract and visualize the output of exploratory multivaria ...
- knowledge, Experience & Creativity
In a training session, the trainer asked the audience "knowledge is power, how many of you agre ...
- 【原创】大数据基础之Hive(5)性能调优Performance Tuning
1 compress & mr hive默认的execution engine是mr hive> set hive.execution.engine;hive.execution.eng ...
- [游记] HEOI2018酱油记
Day -1 在机房颓颓颓颓颓,晚上得知这次考试题本来是要给 ZJOI2018 用的,结果没用上..可想而知考试的难度.. 但愿不爆零 Day 0 坐了一上午火车,顺便找茁神犇拷了个 COD,然后接着 ...
随机推荐
- WindowsMediaPlayer控件批量添加文件至播放列表
思路: 1.读取批定路径的目录文件. 2.用List存放. 3.循环List列表添加到播放列表. public void VidieoPlay() { //WindowsMediaPlayer1.ui ...
- 【Qt】QWidget、QDialog、QMainWindow的异同点【转】
简述 在分享所有基础知识之前,很有必要在这里介绍下常用的窗口-QWidget.QDialog.QMainWindow. 熟悉Qt的同学都应该知道,在新建Qt Widgets项目进行类信息选择时会碰到它 ...
- AngularJS(12)-BootStrap集成
AngularJS 的首选样式表是 Bootstrap, Bootstrap 是目前最受欢迎的前端框架. <!DOCTYPE html> <html lang="en&qu ...
- php保存base64数据
php保存base64数据 if(isset($param['cover_pic']) && !empty($param['cover_pic'])) { if (preg_matc ...
- Hadoop上路-04_HBase0.98.0入门
以下操作在Hadoop分布式集群基础上进行. 一.分布式环境搭建 下载:)验证 3)修改%HBASE%/conf/hbase-env.sh 4)修改$HBASE_HOME/conf/hbase-sit ...
- mybatis的一对多映射
延续mybatis的一对一问题,如果一个用户有多个作品怎么办?这就涉及到了一对多的问题.同样的,mybatis一对多依然可以分为两种方式来解决. 一.使用内嵌的ResultMap实现一对多映射 1)实 ...
- openerp学习笔记 视图更新时删除已存在的菜单或其他对象
删除菜单示例: <delete id="base.menu_module_updates" model="ir.ui.menu"/><dele ...
- java dom4j解析xml用到的几个方法
1. 读取并解析XML文档: SAXReader reader = new SAXReader(); Document document = reader.read(new File(fileName ...
- 无法打开物理文件xxx.mdf 操作系统错误 5:“5(拒绝访问。)” (Microsoft SQL Server,错误: 5120) 的解决方法
问题描述:在附加数据库到sql server时,附加不上,出现如下图所示的错误 解决方法:找到xxx.mdf和xxx_log.ldf文件, 点击“右键”->“属性”->"安全&q ...
- EF中使用Select new 方法中字段值替换的问题
前提需要替换查询得到的List当中的某个字段的值,替换规则有一个mapping关系 尝试代码 有问题 无法获取任何数据 /// <summary> /// 获取Treegrid的List ...