Luogu5055 【模板】可持久化文艺平衡树（fhq-treap）

　　注意下传标记时也需要新建节点。空间开的尽量大。

#include<iostream>
#include<cstdio>
#include<cmath>
#include<cstdlib>
#include<cstring>
#include<algorithm>
using namespace std;
#define ll long long
#define N 200010
#define inf 2147483647
#define pii pair<int,int>
#define lson tree[k].ch[0]
#define rson tree[k].ch[1]
char getc(){char c=getchar();while ((c<'A'||c>'Z')&&(c<'a'||c>'z')&&(c<''||c>'')) c=getchar();return c;}
int gcd(int n,int m){return m==?n:gcd(m,n%m);}
int read()
{
    int x=,f=;char c=getchar();
    while (c<''||c>'') {if (c=='-') f=-;c=getchar();}
    while (c>=''&&c<='') x=(x<<)+(x<<)+(c^),c=getchar();
    return x*f;
}
int m,root[N],cnt;
ll lastans;
struct data{int ch[],size,x,p,rev;ll sum;
}tree[N*];
void up(int k)
{
    tree[k].size=tree[lson].size+tree[rson].size+;
    tree[k].sum=tree[lson].sum+tree[rson].sum+tree[k].x;
}
void rev(int &k){if (k) tree[++cnt]=tree[k],k=cnt,swap(lson,rson),tree[k].rev^=;}
void down(int k){if (tree[k].rev) rev(lson),rev(rson),tree[k].rev=;}
pii split(int k,int x)
{
    if (!k) return make_pair(,);
    int u=++cnt;tree[u]=tree[k];
    down(u);int t=tree[u].ch[];
    if (tree[tree[u].ch[]].size==x) return tree[u].ch[]=,up(u),make_pair(t,u);
    if (tree[tree[u].ch[]].size>x)
    {
        pii v=split(tree[u].ch[],x);
        return tree[u].ch[]=v.second,up(u),make_pair(v.first,u);
    }
    else
    {
        pii v=split(tree[u].ch[],x-tree[tree[u].ch[]].size-);
        return tree[u].ch[]=v.first,up(u),make_pair(u,v.second);
    }
}
int merge(int x,int y)
{
    if (!x||!y) return x|y;
    int k=++cnt;
    if (tree[x].p>tree[y].p)
    {
        tree[k]=tree[x];down(k);
        rson=merge(rson,y);
    }
    else
    {
        tree[k]=tree[y];down(k);
        lson=merge(x,lson);
    }
    up(k);
    return k;
}
int newpoint(int x)
{
    int k=++cnt;tree[k].x=tree[k].sum=x,tree[k].size=,tree[k].rev=lson=rson=,tree[k].p=rand();
    return k;
}
int main()
{
#ifndef ONLINE_JUDGE
    freopen("splay.in","r",stdin);
    freopen("splay.out","w",stdout);
    const char LL[]="%I64d\n";
#else
    const char LL[]="%lld\n";
#endif
    srand();
    m=read();
    for (int i=;i<=m;i++)
    {
        int last=read(),op=read();
        root[i]=root[last];
        switch (op)
        {
            case :
            {
                int p=read()^lastans,x=read()^lastans;
                pii u=split(root[i],p);int v=newpoint(x);
                root[i]=merge(merge(u.first,v),u.second);
                break;
            }
            case :
            {
                int p=read()^lastans;
                pii u=split(root[i],p-),v=split(u.second,);
                root[i]=merge(u.first,v.second);
                break;
            }
            case :
            {
                int l=read()^lastans,r=read()^lastans;
                pii u=split(root[i],l-),v=split(u.second,r-l+);
                rev(v.first);
                root[i]=merge(merge(u.first,v.first),v.second);
                break;
            }
            case :
            {
                int l=read()^lastans,r=read()^lastans;
                pii u=split(root[i],l-),v=split(u.second,r-l+);
                printf(LL,lastans=tree[v.first].sum);
                root[i]=merge(merge(u.first,v.first),v.second);
                break;
            }
        }
        //for (int j=1;j<=m;j++) cout<<root[j]<<' ';cout<<endl;
        //for (int j=1;j<=cnt;j++) cout<<tree[j].x<<' '<<tree[j].size<<' '<<tree[j].sum<<' '<<tree[j].ch[0]<<' '<<tree[j].ch[1]<<' '<<tree[j].rev<<endl;
        //cout<<endl;
    }
    return ;
}