最短路--Dijkstra&&Floyed&&SPFA

最短路径是一个很常见的问题，这里有3种方法，可供参考。

一.Dijkstra
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
using namespace std;
int a[][];
double c[];
bool b[];
double f[][];
int n,i,j,k,x,y,m,s,e;
double minl;
double maxx = 1e30;
int main()
{
    cin >> n;
    for (i = ; i <= n; i++)
        cin >> a[i][] >> a[i][];
    for (i = ; i <= n; i++)
        for(j = ; j <= n; j++)
            f[i][j] = maxx;
    cin >> m;
    for (i = ; i <= m; i++)
    {
        cin >> x >> y;
        f[x][y] = f[y][x] = sqrt(pow(double(a[x][]-a[y][]),)+pow(double(a[x][]-a[y][]),));
    }
    cin>>s>>e;
    for(int i = ;i <= n;i++)
    {
        c[i] = f[s][i];
    }
    memset(b,false,sizeof(b));
    b[s] = true;
    c[s] = ;
    for(int i = ;i <= n;i++)
    {
        minl = maxx;
        k = ;
        for(int j = ;j <= n;j++)
        {
            if(b[j] == false && c[j] < minl)//没走过的路程最小的点
            {
                minl = c[j];
                k = j;
            }
        }
        if(k == )
        break;
        b[k] = true;
        for(int j = ;j <= n;j++)  //将所以能变的点最小路程全变了
        {
            if(c[k] + f[k][j] < c[j])
            c[j] = c[k] + f[k][j];
        }
    }
    printf("%.2lf",c[e]);
    return ;
}

二.Floyed
#include<iostream>
#include<cstdio>
#include<cstring>
#include<cmath>
using namespace std;
double f[][];
int a[][];
int m,n,x,y,r,s,e;
int main()
{
    memset(f,,sizeof(f));
    cin>>n;
    for(int i = ;i <= n;i++)
    {
        cin>>a[i][]>>a[i][];
    }
    cin>>m;
    for(int i = ;i <= m;i++)
    {
        cin>>x>>y;
        f[y][x] = f[x][y] = sqrt(pow(double(a[x][]-a[y][]),)+pow(double(a[x][]-a[y][]),));
    }
    cin>>s>>e;
    for(int k = ;k <= n;k++)
    {
        for(int i = ;i <= n;i++)
        {
            for(int j = ;j <= n;j++)
            {
                if(f[i][j] > f[i][k] + f[k][j] && i != j && i != k && j != k)
                f[i][j] = f[i][k] + f[k][j];
            }
        }
    }
    printf("%.2lf",f[s][e]);
    return ;
}
/*
5
0 0
2 0
2 2
0 2
3 1
5
1 2
1 3
1 4
2 5
3 5
1 5
*/

三.SPFA
#include<iostream>
#include<cstdio>
#include<cstring>
#include<queue>
using namespace std;
int n,p,c,i,j,x,y,t,min1,head,tail,tot,u;
int a[][],b[],dis[],num[],w[][];
queue <int> team;
bool exist[];
int main()
{
    cin>>n>>p>>c;
    for(i=;i<=p;i++)
    {
        b[i]=;
        num[i]=;
        for(j=;j<=p;j++)
            w[i][j]=0x7fffffff/;
    }
    for(i = ;i <= n;i++)
        cin>>b[i];
    for(i=;i<=c;i++)                                      //邻接矩阵存储
    {
        cin>>x>>y>>t;
        w[x][y] = t;
        a[x][++num[x]] = y;
        a[y][++num[y]] = x;
        w[y][x] = w[x][y];
    }
    min1=0x7fffffff/;
    for(i=;i<=p;i++)
    {
        for(j=;j<=p;j++) dis[j]=0x7fffffff/;                      //队列数组初始化
        memset(exist,false,sizeof(exist));                   //exist标志初始化
        dis[i]=;
        exist[i]=true;
        team.push(i);
        while(!team.empty())
        {
            u = team.front();
            team.pop();
            exist[u] = true;
            for(int j = ;j <= num[u];j++)
            {
                if(dis[a[u][j]] > dis[u] + w[u][a[u][j]])
                {
                    dis[a[u][j]] = dis[u] + w[u][a[u][j]];
                    if(!exist[a[u][j]])
                    {
                        team.push(a[u][j]);
                        a[u][j] = true;
                    }
                }
            }
        }
        tot=;
        for(j=;j<=n;j++)
        tot+=dis[b[j]];
        if (tot<min1) min1=tot;
    }
    cout<<min1;
    return ;
}