参考:http://cs231n.github.io/assignment1/

Q1: k-Nearest Neighbor classifier (30 points)

 import numpy as np
from matplotlib.cbook import todate class KNearestNeighbor:
""" a kNN classifier with L2 distance """ def __init__(self):
pass def train(self, X, y):
"""
Train the classifier. For k-nearest neighbors this is just
memorizing the training data. Input:
X - A num_train x dimension array where each row is a training point.
y - A vector of length num_train, where y[i] is the label for X[i, :]
"""
self.X_train = X
self.y_train = y def predict(self, X, k=1, num_loops=0):
"""
Predict labels for test data using this classifier. Input:
X - A num_test x dimension array where each row is a test point.
k - The number of nearest neighbors that vote for predicted label
num_loops - Determines which method to use to compute distances
between training points and test points. Output:
y - A vector of length num_test, where y[i] is the predicted label for the
test point X[i, :].
"""
if num_loops == 0:
dists = self.compute_distances_no_loops(X)
elif num_loops == 1:
dists = self.compute_distances_one_loop(X)
elif num_loops == 2:
dists = self.compute_distances_two_loops(X)
else:
raise ValueError('Invalid value %d for num_loops' % num_loops) return self.predict_labels(dists, k=k) def compute_distances_two_loops(self, X):
"""
Compute the distance between each test point in X and each training point
in self.X_train using a nested loop over both the training data and the
test data. Input:
X - An num_test x dimension array where each row is a test point. Output:
dists - A num_test x num_train array where dists[i, j] is the distance
between the ith test point and the jth training point.
"""
num_test = X.shape[0]
num_train = self.X_train.shape[0]
dists = np.zeros((num_test, num_train))
for i in xrange(num_test):
for j in xrange(num_train):
#####################################################################
# TODO: #
# Compute the l2 distance between the ith test point and the jth #
# training point, and store the result in dists[i, j] #
#####################################################################
dists[i,j] = np.sqrt(np.sum(np.square(X[i,:] - self.X_train[j,:])))
#####################################################################
# END OF YOUR CODE #
#####################################################################
return dists def compute_distances_one_loop(self, X):
"""
Compute the distance between each test point in X and each training point
in self.X_train using a single loop over the test data. Input / Output: Same as compute_distances_two_loops
"""
num_test = X.shape[0]
num_train = self.X_train.shape[0]
dists = np.zeros((num_test, num_train))
for i in xrange(num_test):
#######################################################################
# TODO: #
# Compute the l2 distance between the ith test point and all training #
# points, and store the result in dists[i, :]. #
#######################################################################
dists[i, :] = np.sqrt(np.sum(np.square(self.X_train - X[i,:]), axis=1))
#######################################################################
# END OF YOUR CODE #
#######################################################################
return dists def compute_distances_no_loops(self, X):
"""
Compute the distance between each test point in X and each training point
in self.X_train using no explicit loops. Input / Output: Same as compute_distances_two_loops
"""
num_test = X.shape[0]
num_train = self.X_train.shape[0]
dists = np.zeros((num_test, num_train))
#########################################################################
# TODO: #
# Compute the l2 distance between all test points and all training #
# points without using any explicit loops, and store the result in #
# dists. #
# HINT: Try to formulate the l2 distance using matrix multiplication #
# and two broadcast sums. #
#########################################################################
tDot = np.multiply(np.dot(X, self.X_train.T), -2)
t1 = np.sum(np.square(X), axis=1, keepdims=True)
t2 = np.sum(np.square(self.X_train), axis=1)
tDot = np.add(t1, tDot)
tDot = np.add(tDot, t2)
dists = np.sqrt(tDot)
#########################################################################
# END OF YOUR CODE #
#########################################################################
return dists def predict_labels(self, dists, k=1):
"""
Given a matrix of distances between test points and training points,
predict a label for each test point. Input:
dists - A num_test x num_train array where dists[i, j] gives the distance
between the ith test point and the jth training point. Output:
y - A vector of length num_test where y[i] is the predicted label for the
ith test point.
"""
num_test = dists.shape[0]
y_pred = np.zeros(num_test)
for i in xrange(num_test):
# A list of length k storing the labels of the k nearest neighbors to
# the ith test point.
closest_y = []
#########################################################################
# TODO: #
# Use the distance matrix to find the k nearest neighbors of the ith #
# training point, and use self.y_train to find the labels of these #
# neighbors. Store these labels in closest_y. #
# Hint: Look up the function numpy.argsort. #
#########################################################################
# pass
closest_y = self.y_train[np.argsort(dists[i, :])[:k]]
#########################################################################
# TODO: #
# Now that you have found the labels of the k nearest neighbors, you #
# need to find the most common label in the list closest_y of labels. #
# Store this label in y_pred[i]. Break ties by choosing the smaller #
# label. #
######################################################################### y_pred[i] = np.argmax(np.bincount(closest_y))
#########################################################################
# END OF YOUR CODE #
######################################################################### return y_pred

输出:

Two loop version took 55.817642 seconds
One loop version took 49.692089 seconds
No loop version took 1.267753 seconds

CNN for Visual Recognition (assignment1_Q1)的更多相关文章

  1. CNN for Visual Recognition (01)

    CS231n: Convolutional Neural Networks for Visual Recognitionhttp://vision.stanford.edu/teaching/cs23 ...

  2. CNN for Visual Recognition (02)

    图像分类 参考:http://cs231n.github.io/classification/ 图像分类(Image Classification),是给输入图像赋予一个已知类别标签.图像分类是计算机 ...

  3. 论文笔记之: Bilinear CNN Models for Fine-grained Visual Recognition

    Bilinear CNN Models for Fine-grained Visual Recognition CVPR 2015 本文提出了一种双线性模型( bilinear models),一种识 ...

  4. 大规模视觉识别挑战赛ILSVRC2015各团队结果和方法 Large Scale Visual Recognition Challenge 2015

    Large Scale Visual Recognition Challenge 2015 (ILSVRC2015) Legend: Yellow background = winner in thi ...

  5. 【论文阅读】Deep Mixture of Diverse Experts for Large-Scale Visual Recognition

    导读: 本文为论文<Deep Mixture of Diverse Experts for Large-Scale Visual Recognition>的阅读总结.目的是做大规模图像分类 ...

  6. 目标检测--Spatial pyramid pooling in deep convolutional networks for visual recognition(PAMI, 2015)

    Spatial pyramid pooling in deep convolutional networks for visual recognition 作者: Kaiming He, Xiangy ...

  7. Spatial Pyramid Pooling in Deep Convolutional Networks for Visual Recognition

    Spatial Pyramid Pooling in Deep Convolutional Networks for Visual Recognition Kaiming He, Xiangyu Zh ...

  8. Convolutional Neural Networks for Visual Recognition 1

    Introduction 这是斯坦福计算机视觉大牛李菲菲最新开设的一门关于deep learning在计算机视觉领域的相关应用的课程.这个课程重点介绍了deep learning里的一种比较流行的模型 ...

  9. 【CV论文阅读】+【搬运工】LocNet: Improving Localization Accuracy for Object Detection + A Theoretical analysis of feature pooling in Visual Recognition

    论文的关注点在于如何提高bounding box的定位,使用的是概率的预测形式,模型的基础是region proposal.论文提出一个locNet的深度网络,不在依赖于回归方程.论文中提到locne ...

随机推荐

  1. csu 1503: 点弧之间的距离-湖南省第十届大学生计算机程序设计大赛

    这是--比量p并用交点连接中心不上弧.在于:它至p距离.是不是p与端点之间的最短距离 #include<iostream> #include<map> #include< ...

  2. .net EF 事物 订单流水号的生成 (一)

    首先需要 添加 System.Transactions 程序集 数据表: create table SalesOrder ( ID ,) primary key not null, OrderNo ) ...

  3. C#中实现WebBrowser控件的HTML源代码读写

    原文:C#中实现WebBrowser控件的HTML源代码读写 C#中实现WebBrowser控件的HTML源代码读写http://www.blogcn.com/user8/flier_lu/index ...

  4. 动画云创始人胥克谦&amp;课程格子创始人李天放分享创业经历

    原文地址:http://student.csdn.net/mcd/topic/163587/955044 2014年10月18日在北京科技大学成功举办了CSDN高校俱乐部全国巡讲,现场參会学生有一百余 ...

  5. poj 3273 Monthly Expense (二分)

    //最大值最小 //天数的a[i]值是固定的 不能改变顺序 # include <algorithm> # include <string.h> # include <s ...

  6. hdu149850 years, 50 colors (多个最小顶点覆盖)

    50 years, 50 colors Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others) ...

  7. 第1章1节《MonkeyRunner源码剖析》概述:前言(原创)

    天地会珠海分舵注:本来这一系列是准备出一本书的,详情请见早前博文“寻求合作伙伴编写<深入理解 MonkeyRunner>书籍“.但因为诸多原因,没有如愿.所以这里把草稿分享出来,所以错误在 ...

  8. How to:如何在调用外部文件时调试文件路径(常见于使用LaunchAppAndWait和LaunchApp函数)

    原文:How to:如何在调用外部文件时调试文件路径(常见于使用LaunchAppAndWait和LaunchApp函数) IS里调用外部文件的时候,一般都是用LaunchAppAndWait函数,比 ...

  9. C# Winform 界面线程的Invoke死锁,以及Application.DoEvent的问题

    1.对于非界面线程来说,Invoke是把一个操作丢到界面线程的队列里,然后阻塞,等到这个操作被界面线程完成后,才继续后续操作.也就是说,Invoke是同步的. 问题来了,如果界面线程此时正在等待这个非 ...

  10. apache启动报错:the requested operation has failed解决办法

    原因一:80端口占用 例如IIS,另外就是迅雷.我的apache服务器就是被迅雷害得无法启用! 原因二:软件冲突 装了某些软件会使apache无法启动如Dr.com 你打开网络连接->TcpIp ...