简单DFS。

#include<iostream>
#include<cstring>
#include<cmath>
#include<algorithm>
#include<cstdio>
#include<vector>
using namespace std; const int maxn=+;
vector<int>g[maxn];
int n,m;
int ans[maxn];
int root;
int Deep; void dfs(int x,int deep)
{
Deep=max(Deep,deep);
if(g[x].size()==)
{
ans[deep]++;
return ;
}
for(int i=;i<g[x].size();i++)
dfs(g[x][i],deep+);
} int main()
{
scanf("%d%d",&n,&m);
for(int i=;i<=n;i++) g[i].clear();
for(int i=;i<=m;i++)
{
int id; scanf("%d",&id);
int k; scanf("%d",&k);
while(k--)
{
int id2; scanf("%d",&id2);
g[id].push_back(id2);
}
}
memset(ans,,sizeof ans);
root=; Deep=;
dfs(root,);
for(int i=;i<=Deep;i++)
{
printf("%d",ans[i]);
if(i<Deep) printf(" ");
else printf("\n");
}
return ;
}

PAT (Advanced Level) 1004. Counting Leaves (30)的更多相关文章

  1. PAT 解题报告 1004. Counting Leaves (30)

    1004. Counting Leaves (30) A family hierarchy is usually presented by a pedigree tree. Your job is t ...

  2. PTA (Advanced Level) 1004 Counting Leaves

    Counting Leaves A family hierarchy is usually presented by a pedigree tree. Your job is to count tho ...

  3. PAT (Advanced Level) 1049. Counting Ones (30)

    数位DP.dp[i][j]表示i位,最高位为j的情况下总共有多少1. #include<iostream> #include<cstring> #include<cmat ...

  4. 【PAT甲级】1004 Counting Leaves (30 分)(BFS)

    题意:给出一棵树的点数N,输入M行,每行输入父亲节点An,儿子个数n,和a1,a2,...,an(儿子结点编号),从根节点层级向下依次输出当前层级叶子结点个数,用空格隔开.(0<N<100 ...

  5. PAT 1004 Counting Leaves (30分)

    1004 Counting Leaves (30分) A family hierarchy is usually presented by a pedigree tree. Your job is t ...

  6. 1004. Counting Leaves (30)

    1004. Counting Leaves (30)   A family hierarchy is usually presented by a pedigree tree. Your job is ...

  7. PTA 1004 Counting Leaves (30)(30 分)(dfs或者bfs)

    1004 Counting Leaves (30)(30 分) A family hierarchy is usually presented by a pedigree tree. Your job ...

  8. 1004 Counting Leaves (30分) DFS

    1004 Counting Leaves (30分)   A family hierarchy is usually presented by a pedigree tree. Your job is ...

  9. 【PAT Advanced Level】1004. Counting Leaves (30)

    利用广度优先搜索,找出每层的叶子节点的个数. #include <iostream> #include <vector> #include <queue> #inc ...

随机推荐

  1. Django CRM学员系统项目

    项目需求: 1.分讲师\学员\课程顾问角色,2.学员可以属于多个班级,学员成绩按课程分别统计3.每个班级至少包含一个或多个讲师4.一个学员要有状态转化的过程 ,比如未报名前,报名后,毕业老学员5.客户 ...

  2. STM32F407的硬件I2C

    源:STM32F407的硬件I2C 我使用的是STM32的固件库. 硬件模块使用之前必须配置其参数,I2C的配置如下: void IIC_Config(void) { GPIO_InitTypeDef ...

  3. Dreamweaver使用过程的小技巧

    在用Dreamweaver中制作网站的过程中,经常会遇到这样的问题,我们要修改一些属性类的标签,如<a href="abc/def.html">,如果我们要把href= ...

  4. 【贪心】 poj 1032 和为n的若干数最大乘积

    给出n,把n分解为若干不相同数之和,使之乘积最大.贪心,Discuss里面的思路:把n分解为从2开始的连续整数,如果有多,则从高位开始依次加1.如26,我们得到2+3+4+5+6,此时还剩余6(26- ...

  5. 如何使用Android中的OpenGL ES媒体效果

    引自:http://www.2cto.com/kf/201506/404366.html Android的媒体效果框架允许开发者可以很容易的应用多种令人印象深刻的视觉效果到照片或视频之上.作为这个媒体 ...

  6. UITabBarController相关之tabBar文字不显示

    1.在用tabBarController管理控制器的时候,出现了下面的问题 对应的代码: JingHuaController *jinghuaVC = [[JingHuaController allo ...

  7. THOUGHTS: programming in linux... with third_party open sources... methods

    Actually I do not have experiences in programming with open sources/third party libs.. in linux.. I ...

  8. 在Activity之间使用Intent传值和Bundle传值的区别和方式

    两者本质上没有任何区别.Bundle只是一个信息的载体 将内部的内容以键值对组织 Intent负责Activity之间的交互 自己是带有一个Bundle的Intent.putExtras(Bundle ...

  9. Java成员变量默认值

    Java中明确规定:1.如果是引用型的,比如:String,还有类对象,他们的默认值都是:null:2.而如果是值类型:double,int,long,float,char等等,他们都是:0:还有一个 ...

  10. Python 文件Hash(MD5,SHA1)

    import hashlib import os,sys   def CalcSha1(filepath):     with open(filepath,'rb') as f:         sh ...