CASE

,D.[Score] B_Score
,'Distince'=
CASE
WHEN C.Score > D.Score THEN C.[Score] - D.[Score]
WHEN C.Score < D.Score THEN D.[Score] - C.[Score]
ELSE 0
END
FROM [tbiz_AssScoreAction] C
INNER JOIN [tbiz_AssScoreAction] D
ON C.QuestionID =D.QuestionID AND (C.RelationID -30) = D.RelationID
WHERE C.RelationID=30 AND C.ProjectID=65 AND C.PersonID=2430
--等价语法
,D.[Score] - C.Score Ta_Zi
,CASE
WHEN C.[Score] > D.[Score] THEN C.[Score] - D.[Score]
WHEN C.[Score] < D.[Score] THEN D.[Score] - C.[Score]
ELSE 0
END AS Distince

CASE 判断 NULL的情况

CASE WHEN [ReadState] IS NULL OR [ReadState]=0  THEN '未读' ELSE '已读'  END AS ReadStateName
SELECT CASE Type_No
WHEN 2 THEN Customer_No
WHEN 4 THEN Customer_No
WHEN 10 THEN Customer_No
WHEN 11 THEN Customer_No
WHEN 3 THEN Organization_Name
WHEN 5 THEN Organization_Name
END AS Customer_No
FROM [Lx_Finance_Transfer_ForNC]

SELECT
A.TESTID,
A.SCALEID,
B.NAME,
B.COUNT,
B.ASSTIME,
A.STATE,
CASE
WHEN A.MATCH IS NULL THEN
0 ELSE CAST (A.MATCH AS NUMERIC ( 26, 2 ))
END AS MATCH
FROM
TD_TEST_INFO A
JOIN ASS_SCALE B ON A.SCALEID= B.SCALEID

JOIN

SELECT T.Id,T.pingZhengNum FROM Lx_Finance_Transfer_ForNC T
LEFT JOIN Lx_Finance_Flow_ForNC F ON T.Id=F.PingZhengId

LEFT JOIN

解读:尽管主档表T只有1条记录,但是在分档表中有2条记录与之关联,所以SELECT结果集有2条.

SELECT T.Id T_Id,T.pingZhengNum,F.* FROM Lx_Finance_Transfer_ForNC T
INNER JOIN Lx_Finance_Flow_ForNC F ON T.Id=F.PingZhengId
-- 效果和LEFT JOIN 一样

RIGHT JOIN

解读:T表从RIGHT链接F表,SQL引擎会保留F表中所有记录

自连接

SELECT  A.* ,
B.RelationName ,
B.Score T_Score ,
B.ID T_ID
FROM [tbiz_AssScoreWeidu] A
INNER JOIN [tbiz_AssScoreWeidu] B
ON A.WeiduNo = B.WeiduNo AND A.RelationID = B.RelationID + 30
WHERE A.ProjectID = 65
AND A.PersonID = 2430
AND ( A.RelationID = 30 OR B.RelationID = 0 )
AND A.WeiduNo = 'C211-13'

自链接+WHERE条件

SELECT  A.DictItemID ,
B.ItemName ParentItemName ,
A.ItemType ,
A.ItemName ,
A.ItemCode ,
A.CreatedBy ,
A.IsDelete
FROM tcfg_DictItem A
LEFT JOIN tcfg_DictItem B ON B.DictItemID = A.ParentID
WHERE A.ParentID != 0

一对多关系JOIN一行

SELECT *
FROM (
SELECT A.Id
,A.PingZhengNum
,A.CRT_Date
,A.[Enabled]
,B.Id FlowId
,B.Type_No_Name
,B.VouchType
,ROW_NUMBER() OVER
(
PARTITION BY A.Id
ORDER BY B.CRT_Date
)
AS rn
FROM [Lx_Finance_Transfer_ForNC] A LEFT OUTER JOIN dbo.Lx_Finance_Flow_ForNC B
ON A.Id=B.PingZhengId
) m
WHERE rn=1

解读:主档表记录多,分档表记录少,参考

方案二

SELECT A.Id
,A.PingZhengNum
,A.CRT_Date
,A.[Enabled]
,B.Id FlowId
,B.Type_No_Name
,B.VouchType
FROM [Lx_Finance_Transfer_ForNC] A
OUTER APPLY
(
SELECT TOP 1 *
FROM Lx_Finance_Flow_ForNC C
WHERE PingZhengId = A.Id
ORDER BY CRT_Date DESC
) B

ROW_NUMBER() OVER(....) AS Xxx

SELECT  [PersonID] ,
ROW_NUMBER() OVER
(
ORDER BY A.Id
) AS RowID
FROM [tbiz_AssScore] A

简单的说row_number()从1开始,为每一条"分组"记录返回一个数字,分组对应关键词PARTITION BY XXX,为可选关键词

当出现GROUP BY 子句时,GROUP BY会影响到ROW_NUMBER()中的字段,如下面的第5行

 SELECT  [PersonID] ,
AVG([Score]) AVG_Score,
ROW_NUMBER() OVER
(
ORDER BY A.PersonID
) AS RowID
FROM [tbiz_AssScore] A
GROUP BY PersonID
ORDER BY AVG_Score

PARTITION BY 子句 + ROW_NUMBER() OVER(....) AS rn

PARTITION BY 理解成"分组"

SELECT * FROM(
SELECT C.[ID]
,D.ID BID
,C.[ProjectID]
,C.[PersonID]
,C.[QuestionID]
,C.[QuestionName]
,C.[WeiduNo]
,C.[WeiduNAME]
,C.[RelationID]
,C.[RelationName]
,C.[Score]
,D.RelationName B_RelationName
,D.[Score] B_Score
,D.[Score] - C.Score Ta_Zi
,ROW_NUMBER() OVER
(
PARTITION BY D.ID,C.[ProjectID],C.[PersonID],C.[QuestionID]
ORDER BY C.[ID]
)
AS rn
FROM [tbiz_AssScoreAction] C
INNER JOIN [tbiz_AssScoreAction] D
ON C.QuestionID = D.QuestionID AND (C.RelationID -30) = D.RelationID
WHERE C.RelationID=30 AND C.ProjectID=65 AND C.PersonID=2430
) m WHERE rn = 1 ORDER BY Ta_Zi

DECLARE

DECLARE @MedicalInstitutionID VARCHAR(max) SET @MedicalInstitutionID='SYS20130228000000012'
DECLARE @ResidentCardID VARCHAR(max) SET @ResidentCardID=NULL
DECLARE @Name VARCHAR(max) SET @Name=NULL
DECLARE @InDateLeft DATETIME SET @InDateLeft=NULL
DECLARE @InDateRight DATETIME SET @InDateRight=NULL
DECLARE @AcceptsOperatorID VARCHAR(max) SET @AcceptsOperatorID=NULL
DECLARE @AcceptsOperatorName VARCHAR(max) SET @AcceptsOperatorName=NULL
DECLARE @IsPrint INT SET @IsPrint=null

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