7-15 Square Destroyer 破坏正方形 uva1603

先是处理所有的正方形 从边长为1开始 将其边存好 满边存好

然后不断扫描正方形  并且进行拆除  直到拆完或者 步数小于等于9（启发方程  因为n小于等于5  九次足以将所有的拆完）

代码实施有很多细节  lrj的代码非常巧妙  ！

#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<algorithm>
using namespace std;

const int maxs = ; // number of squares: 25+16+9+4+1=55
const int maxm = ; // number of matches: 2*5*(5+1)=60

int n, exists[maxm]; // matches
int s, size[maxs], fullsize[maxs], contains[maxs][maxm]; // squares
int best;

inline int row_match(int x, int y) {
  return (*n+)*x+y;
}

inline int col_match(int x, int y) {
  return (*n+)*x+n+y;
}

// number of matches in a full n*n grid
inline int match_count(int n) {
  return *n*(n+);
}

void init() {
  int m, v;
  scanf("%d%d", &n, &m);
  for(int i = ; i < match_count(n); ++i) exists[i] = ;
  while(m--) {
    scanf("%d", &v);
    exists[v-] = ;
  }

  // collect full squares
  s = ;
  memset(contains, , sizeof(contains));
  for(int i = ; i <= n; i++) // side length
    for(int x = ; x <= n-i; x++)
      for(int y = ; y <= n-i; y++) {
        size[s] = ;
        fullsize[s] = *i; // number of matches in a complete square
        for(int j = ; j < i; j++) {
          int a = row_match(x, y+j); // up
          int b = row_match(x+i, y+j); // down
          int c = col_match(x+j, y); // left
          int d = col_match(x+j, y+i); // right
          contains[s][a] = ;
          contains[s][b] = ;
          contains[s][c] = ;
          contains[s][d] = ;
          size[s] += exists[a] + exists[b] + exists[c] + exists[d]; // number of matches now
        }
        ++s;
      }
}

int find_square() {
  for(int i = ; i < s; i++)
    if(size[i] == fullsize[i]) return i;
  return -;
}

void dfs(int dep) {
  if(dep >= best) return;

  int k = find_square();
  if(k == -) {
    best = dep;
    return;
  }

  // remove a match in that square
  for(int i = ; i < match_count(n); i++)
    if(contains[k][i]) {
      for(int j = ; j < s; j++)
        if(contains[j][i]) size[j]--;
      dfs(dep + );
      for(int j = ; j < s; j++) //dfs切记改变了要变回来
        if(contains[j][i]) size[j]++;
    }
}

int main() {
  int T;
  scanf("%d", &T);
  while(T--) {
    init();
    best = n*n;
    dfs();
    printf("%d\n", best);
  }
  return ;
}