https://www.luogu.org/problem/show?pid=2866

题目描述

Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self-conscious about her messy hairstyle, FJ wants to count the number of other cows that can see the top of other cows' heads.

Each cow i has a specified height hi (1 ≤ hi ≤ 1,000,000,000) and is standing in a line of cows all facing east (to the right in our diagrams). Therefore, cow i can see the tops of the heads of cows in front of her (namely cows i+1, i+2, and so on), for as long as these cows are strictly shorter than cow i.

Consider this example:

=

=       =

=   -   =         Cows facing right -->

=   =   =

= - = = =

= = = = = =

1 2 3 4 5 6 Cow#1 can see the hairstyle of cows #2, 3, 4

Cow#2 can see no cow's hairstyle

Cow#3 can see the hairstyle of cow #4

Cow#4 can see no cow's hairstyle

Cow#5 can see the hairstyle of cow 6

Cow#6 can see no cows at all!

Let ci denote the number of cows whose hairstyle is visible from cow i; please compute the sum of c1 through cN.For this example, the desired is answer 3 + 0 + 1 + 0 + 1 + 0 = 5.

农民约翰的某N(1 < N < 80000)头奶牛正在过乱头发节!由于每头牛都意识到自己凌乱不堪 的发型,约翰希望统计出能够看到其他牛的头发的牛的数量.

每一头牛i有一个高度所有N头牛面向东方排成一排,牛N在最前面,而 牛1在最后面.第i头牛可以看到她前面的那些牛的头,只要那些牛的高度严格小于她的高度,而且 中间没有比hi高或相等的奶牛阻隔.

让N表示第i头牛可以看到发型的牛的数量;请输出Ci的总和

输入输出格式

输入格式:

Line 1: The number of cows, N.

Lines 2..N+1: Line i+1 contains a single integer that is the height of cow i.

输出格式:

Line 1: A single integer that is the sum of c1 through cN.

输入输出样例

输入样例#1:

6
10
3
7
4
12
2
输出样例#1:

5
 #include <algorithm>
#include <iostream>
#define maxn 1000005 using namespace std; long long n,ans,top,x;
long long stack[maxn]; int main()
{
cin>>n;
for(int i=;i<=n;i++)
{
cin>>x;
while(top&&stack[top]<x)
top--;
ans+=top;
stack[++top]=x;
}
cout<<ans;
return ;
}

熟悉栈

洛谷——P2866 [USACO06NOV]糟糕的一天Bad Hair Day的更多相关文章

  1. 洛谷P2866 [USACO06NOV]糟糕的一天Bad Hair Day

    P2866 [USACO06NOV]糟糕的一天Bad Hair Day 75通过 153提交 题目提供者洛谷OnlineJudge 标签USACO2006云端 难度普及/提高- 时空限制1s / 12 ...

  2. 洛谷P2866 [USACO06NOV]糟糕的一天Bad Hair Day(单调栈)

    题目描述 Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self ...

  3. 洛谷 P2866 [USACO06NOV]糟糕的一天Bad Hair Day

    题目描述 Some of Farmer John's N cows (1 ≤ N ≤ 80,000) are having a bad hair day! Since each cow is self ...

  4. 洛谷 P2866 [USACO06NOV]糟糕的一天Bad Hair Day 牛客假日团队赛5 A (单调栈)

    链接:https://ac.nowcoder.com/acm/contest/984/A 来源:牛客网 题目描述 Some of Farmer John's N cows (1 ≤ N ≤ 80,00 ...

  5. 单调栈 && 洛谷 P2866 [USACO06NOV]糟糕的一天Bad Hair Day(单调栈)

    传送门 这是一道典型的单调栈. 题意理解 先来理解一下题意(原文翻译得有点问题). 其实就是求对于序列中的每一个数i,求出i到它右边第一个大于i的数之间的数字个数c[i].最后求出和. 首先可以暴力求 ...

  6. 洛谷 2866 [USACO06NOV]糟糕的一天Bad Hair Day

    [题意概述] 给出一个长度为n的序列a,求有多少对[i,j]满足i<j且a[i]>max(a[i+1],a[i+2],...,a[j]). [题解] 单调栈. 倒着处理序列的元素,维护一个 ...

  7. 洛谷P2866 [USACO06NOV]Bad Hair Day S (单调栈)

    看到这道题很容易想到单调栈,但我一开始想的是从后往前扫,但发现会有问题(因为这样会对后面牛的答案造成影响),所以这时我们要及时换一个思路,从前往后扫. 维护一个单调递减的栈,插入h[i]时,小等于它的 ...

  8. P2866 [USACO06NOV]糟糕的一天Bad Hair Day--单调栈

    P2866 [USACO06NOV]糟糕的一天Bad Hair Day 题意翻译 农夫约翰有N (N \leq 80000)N(N≤80000)头奶牛正在过乱头发节.每一头牛都站在同一排面朝东方,而且 ...

  9. bzoj1660 / P2866 [USACO06NOV]糟糕的一天Bad Hair Day

    P2866 [USACO06NOV]糟糕的一天Bad Hair Day 奶牛题里好多单调栈..... 维护一个单调递减栈,存每只牛的高度和位置,顺便统计一下答案. #include<iostre ...

随机推荐

  1. js拿到焦点所在的标签对象

    通过 document.activeElement 此时是js对象,如果要调用jQuery的API那么就转换成jquery对象 $(document.activeElement)

  2. [ SDOI 2010 ] 古代猪文

    \(\\\) Description 一句话题意: 设 \(x=\sum_{d|n} C_n^d\),求 \(G^x\pmod {999911659}\) . 从原题面大段语文中其实不难推出所求. \ ...

  3. 块级元素的text-align对行内元素和果冻元素(inline-block)的作用

    块级元素社设置了text-align:center以后,对其直接行内元素/果冻元素.继承行内元素/果冻元素都会产生“居中效应”. <style> .test4{ text-align: c ...

  4. JS中的逻辑运算符&&、||,位运算符|,&

    1.JS中的||符号: 运算方法: 只要“||”前面为false,不管“||”后面是true还是false,都返回“||”后面的值. 只要“||”前面为true,不管“||”后面是true还是fals ...

  5. Scala基础篇-04 try表达式

    1.try表达式 定义 try{} catch{} finally{} //例子 try{ Integer.parseInt("dog") }catch { }finally { ...

  6. fatal: Authentication failed for 问题解决

    执行以下code git config --system --unset credential.helper 参考地址: https://www.jianshu.com/p/8a7f257e07b8

  7. PPTP的搭建

    一.准备 1.检查是否支持pptp modprobe ppp-compress-18 && echo yes yes支持 2.是否开启tun cat /dev/net/tun 返回ca ...

  8. CREATE OPERATOR CLASS - 定义一个新的操作符类

    SYNOPSIS CREATE OPERATOR CLASS name [ DEFAULT ] FOR TYPE data_type USING index_method AS { OPERATOR ...

  9. Java集合(二)--Iterator和Iterable

    Iterable: public interface Iterable<T> { Iterator<T> iterator(); } 上面是Iterable源码,只有一个ite ...

  10. Parker Gear Pump - Gear Pump Seal Is More O-Ring: Role

    Parker Gear Pump    introduction Gear pump lip seal is mainly used in reciprocating dynamic seals. C ...