Thursday, March 14, 2013

How to Jam an Arrangement_2 into a General_polygon_set_2

I spent about three hours yesterday tracking down a weird bug in CGAL - I have code that builds a general polygon set out of an
 arrangement, exports the polygons, and weirdly the polygons had duplicate points.  This is an impossibility for a valid arrangement.

昨天我花了近3个小时追踪一个怪异的CGAL的bug——我写那个程序是为了从arrangement中构建出多边形的集合,然后导出这些多边形,而奇怪的多边形

会有反复点。但在有效的arrangement里这是不可能的。

To my annoyance, I discovered today as I went to write the bug up that I knew about this bug...over three
years ago
. :-(  I get annoyed when I search for the answer to an obscure OpenGL problem and find my own post (e.g. I'm not going to find anything I didn't already know), but it's even more annoying to waste hours on the bug and then have that happen.
让我气愤只是的是,我今天去记录这个问题是发现我事实上在三年前就遇到过了。:-(当我搜索明显的OpengGL问题然后发现了自己的博文(我不会找到不论什么我不知道的)。可是更令人火大的是我居然花了数小时调代码并产生这个错误。
Basically if you are going to build a general polygon set by providing a pre-built arrangement, there are two things you must do:

  • Remove redundant edges - the GPS code assumes that the arrangement doesn't have needless edges (which will screw up traversal).  Fortunately, the GPS code has a utility to do this, which I just call.
  • Then you have to ensure that the direction of the underlying curves along the various edges are consistent - that is, for a given counter-clockwise boundary, every underlying curve goes either with or against the edge.

(After redundant edge removal, the arrangement will contain no antennas, so it will always be possible to get consistency on both sides of a CCB.)
基本上,假设你要从一个预先构建的arrangement中拿出通用多边形集合。有两件事必须做:

         移除冗余边——GPS代码默认arrangement不须要的边(它们会搞乱遍历过程)幸运的是GPS码有一个辅助函数供我调用帮助完毕这一工作。
         然后你必须确保作为各边基线的曲线的方向是连续的——即给定顺时针方向的边界,每个基础曲线都顺着或逆向于该边界。

I wrote code to enforce this second condition by flipping the curve of any halfedge where (1) the curve goes against the halfedge and (2) the halfedge is adjacent to the "contained" side of the map.

With this, polygon set operations work on arbitrary map input.

Why Did You Try This?

Forcing pre-made arrangements into polygon sets requires sub-classing the general polygon set template instantiation to get direect access to things like the arrangement, and it's not particularly safe. 
It also requires your arrangement to have the containment flag on the face data mixed in.  Why go to the trouble?  I did this for two reasons:
  • Sometimes the polygonal set data I want to process came from an arrangement, and that arrangement is fairly huge.  Having to construct the arrangement out of polygons the normal way requires geometry tests - topology data would be lost and rediscovered. 
    For big maps this is really performance-painful.
  • I have some operations that work on arrangements that are precursors to boolean sets. For example, the airport surface area data are fundamentally polygon sets (e.g. in the set is the airport surface area) but some of the constructive processing (e.g. simplifying
    the contour) run on arrangements.

When an arrangement is turned into a polygon set, one of the results is a rather drastic map cleaning.  Since the polygon set cares only about containment (what points are in, what are out), random features like roads tend to get blown away.

Posted by Benjamin Supnik at 12:20
PM
 

怎样将Arranged_2压入General_Polygon_set_2中的更多相关文章

  1. 面试 16:栈的压入压出队列(剑指 Offer 第 22 题)

    我们今天继续来看看周五留下的习题: 面试题:输入两个整数序列,第一个序列表示栈的压入顺序,请判断二个序列是否为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如:压入序列为{1,2,3,4,5},那{ ...

  2. 剑指offer(21)栈的压入、弹出序列

    题目描述 输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1,2,3,4,5是某栈的压入顺序,序列4,5,3,2,1是该压栈序 ...

  3. 《剑指offer》-栈的压入、弹出序列

    输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1,2,3,4,5是某栈的压入顺序,序列4,5,3,2,1是该压栈序列对应的一 ...

  4. 剑指offer-第四章解决面试题的思路(栈的压入和弹出序列)

    题目:输入两个整数序列,第一个序列表示栈的压入序列,请判断第二个序列是否为弹出序列. 思路:定义两个指针sPush和sPop分别指向两个整数序列的开头,借助一个辅助的栈,将第一个序列的数据依次压入栈中 ...

  5. 【剑指Offer】21、栈的压入、弹出序列

      题目描述:   输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否可能为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1,2,3,4,5是某栈的压入顺序,序列4,5,3,2 ...

  6. 剑指Offer-21.栈的压入、弹出序列(C++/Java)

    题目: 输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否可能为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1,2,3,4,5是某栈的压入顺序,序列4,5,3,2,1是该压栈 ...

  7. 剑指offer31----栈的压入、弹出序列

    题目:输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1,2,3,4,5是某栈的压入顺序,序列4,5,3,2,1是该压栈序列对 ...

  8. 剑指Offer面试题:20.栈的压入、弹出序列

    一.题目:栈的压入.弹出序列 题目:输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1.2.3.4.5是某栈的压栈序列,序列4 ...

  9. 剑指Offer:面试题22——栈的压入,弹出序列(java实现)

    题目描述: 输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否为该栈的弹出顺序.假设压入栈的所有数字均不相等.例如序列1,2,3,4,5是某栈的压入顺序,序列4,5,3,2,1是该压栈 ...

随机推荐

  1. 用c++封装linux系统调用

    #include <pthread.h> #include <cstdlib> #include <ctime> #include <iostream> ...

  2. svn提示out of date

    你需要先update一下,应该会有一个冲突标志,你查看一下历史日志,找到是谁在你之前进行了提交,和他商议一下如何合并你们两个人的修改,然后在你本地处理后,标记“冲突已解决”,最后再次commit

  3. arduino知识

    如果你买过Adafruit, Sparkfun, Seeedstudio和Arduino Store的Kit,不难发现Arduino官方的无论从包装和印刷上都是最具艺术气质的,其次是Sparkfun, ...

  4. sql 更新字段

    UPDATE YpeopleSET power='0'WHERE power='1'; UPDATE Ypeople SET power='1' WHERE power='0' and pid='22 ...

  5. Yii2发送邮箱总结

    修改配置文件,普通版在(config/web.php).高级版默认配置在/common/config/main-local.php 'components' => [ 'mailer' => ...

  6. Python3创建RIDE桌面快捷方式的另一种方法

    今天尝试了一下Python3下安装Robot Framework,但是原来的Python2下创建ride快捷方式的方法都不奏效,启动不了ride.于是,转为VBS脚本的方式来间接创建快捷方式.毕竟,每 ...

  7. iOS开发之--MVC 架构模式

    随着项目开发时间的增加,从刚开始那种很随意的代码风格,逐渐会改变,现在就介绍下MVC的架构模式,MVC的架构模式,从字面意思上讲,即:MVC 即 Modal View Controller(模型 视图 ...

  8. iOS 7 新特性:视图控制器切换API

    本文转载至 http://blog.jobbole.com/51588/ 本文由 伯乐在线 - studentdeng 翻译自 Chris Eidhof.欢迎加入技术翻译小组.转载请参见文章末尾处的要 ...

  9. poj_3259 负权和环

    题目大意 N个点,M条双向路径,W条单向路径.从双向路径的一端到另一端所花费时间为正值,从单向路径的源点到终点所花时间为负值.问是否存在一条从A出发,再回到A的回路,满足回到A的时间小于出发时间. 题 ...

  10. PMP十大知识领域整理

    2018-7-28至2018-12-8历时4个多月,学写了PMP(拍马屁),感觉自己经历了,哇-唉-哦-嗯这四个阶段 刚开始觉得如遇圣经,被PMP的知识体系和老师的精彩课程深深震撼! 后来觉得很多东西 ...