The count-and-say sequence is the sequence of integers beginning as follows:

1, 11, 21, 1211, 111221, ...

1 is read off as "one 1" or 11.
11 is read off as "two 1s" or 21.
21 is read off as "one 2, then one 1" or 1211.

Given an integer n, generate the nth sequence.

Note: The sequence of integers will be represented as a string.

代码如下:

方法一:

 public class Solution {
public String countAndSay(int n) { String s="1";
if(n==0||n==1)
return s; String result="";
for(int k=1;k<n;k++) //用for循环
{ char[] ss=s.toCharArray(); result="";
int i=0;
int j=0; for( i=0;i<ss.length;)
{
char a=ss[i];
int count=0;
for(j=i;j<ss.length;j++)
{
if(a==ss[j])
count++;
else break;
}
result=result+Integer.toString(count)+Character.toString(a); i=j;
} s=result;
} return s;
}
}

方法二:

 public class Solution {
public String countAndSay(int n) { String s="1";
if(n==0||n==1)
return s; s=countAndSay(n-1);//用递归
String result=""; char[] ss=s.toCharArray();
result="";
int i=0;
int j=0; for( i=0;i<ss.length;)
{
char a=ss[i];
int count=0;
for(j=i;j<ss.length;j++)
{
if(a==ss[j])
count++;
else break;
}
result=result+Integer.toString(count)+Character.toString(a); i=j;
} return result;
}
}

38. Count and Say的更多相关文章

  1. LeetCode - 38. Count and Say

    38. Count and Say Problem's Link ------------------------------------------------------------------- ...

  2. LeetCode题解38.Count and Say

    38. Count and Say The count-and-say sequence is the sequence of integers beginning as follows: 1, 11 ...

  3. leetCode练题——38. Count and Say

    1.题目 38. Count and Say The count-and-say sequence is the sequence of integers with the first five te ...

  4. 【leetcode❤python】 38. Count and Say

    #-*- coding: UTF-8 -*- class Solution(object):    def countAndSay(self, n):        """ ...

  5. 【LeetCode】38 - Count and Say

    The count-and-say sequence is the sequence of integers beginning as follows:1, 11, 21, 1211, 111221, ...

  6. Java [leetcode 38]Count and Say

    题目描述: The count-and-say sequence is the sequence of integers beginning as follows: 1, 11, 21, 1211, ...

  7. 38. Count and Say - Unsolved

    https://leetcode.com/problems/count-and-say/#/description The count-and-say sequence is the sequence ...

  8. 【一天一道LeetCode】#38. Count and Say

    一天一道LeetCode系列 (一)题目 The count-and-say sequence is the sequence of integers beginning as follows: 1, ...

  9. [leetcode]38. Count and Say数数

    The count-and-say sequence is the sequence of integers with the first five terms as following: 1. 1 ...

随机推荐

  1. 用C#用C#实现窗体在规定时间弹出,例如:10:00.弹出后关闭。并在5分钟后再次弹出。5次后停止。最好有具体代码实现窗体在规定时间弹出,例如:10:00.弹出后关闭。并在5分钟后再次弹出。5次后停止。最好有具体代码

    run(){        while(true)        {                show();                if(条件)                {     ...

  2. nuget的小Tips

    1.nuget常用命令 nuget spec -a bin\Debug\DllName.dll -f //根据dll生成.nuspec文件,这样会生成无用的默认标签,比如licenseUrl.tags ...

  3. 11个Linux基础面试问题

    Q.1: Linux 操作系统的核心是什么? Shell Kernel Command Script Terminal 答: 内核(Kernel)是Linux 操作系统的核心.Shell是一个命令行解 ...

  4. 黑马程序员——OC语言Foundation框架 结构体

    Java培训.Android培训.iOS培训..Net培训.期待与您交流! (以下内容是对黑马苹果入学视频的个人知识点总结) (一)结构体 NSRange(location length) NSPoi ...

  5. Linux下备份系统至另一硬盘

    首先会想到dd命令. 但,, 1,若是小硬盘还好,上T的大硬盘这样做肯定不明智; 2,况且dd是在硬件层面的拷贝,前面的MBR也会随之恢复到另一个盘,若源硬盘是100G,目标盘是200G,又会出问题, ...

  6. [转]VS2005 Debug时提示"没有找到MSVCR80D.dll"的解决办法

    总结各种解决方法如下: 原因:(不知道在说啥)由于VS.net 2005 采用了一种新的DLL方案,搞成一个exe还要配有一个manifest文件(一般在嵌入文件里了,所以看不到,不过也可以不嵌入,这 ...

  7. 指针属性直接赋值 最好先retain 否则内存释放导致crash

    //先释放之前的 YK_RELEASE_SAFELY(_selectedDate); //retain新的 _selectedDate = [aDate retain]; NSString 属性的好像 ...

  8. 数组的filter方法

    filter()函数用于过滤序列,filter()把传入的函数依次作用于每个元素,然后根据返回值是True还是False决定保留还是丢弃该元素. eg: var arr=[10,11,12,13,14 ...

  9. Android布局— — —线性布局

    以水平或垂直的方式显示界面中的控件 线性布局 语法格式: <LinearLayout xmlns:android="http://schemas.android.com/apk/res ...

  10. PAT 06-2 字符串字母大小写转换

    没什么好说的,记得使用ctype.h就好了,谭浩强那本书就介绍了,再不使用就太对不起他老人家了:有一点小小的地方需要注意一下,&&的优先级比=号高,所以getchar()两边没有括号的 ...