Poj3087
| Time Limit: 1000MS | Memory Limit: 65536K | |
| Total Submissions: 8842 | Accepted: 4077 |
Description
A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuffling chips is performed by starting with two stacks of poker chips, S1 and S2, each stack containing C chips. Each stack may contain chips of several different colors.
The actual shuffle operation is performed by interleaving a chip from S1 with a chip from S2 as shown below for C = 5:

The single resultant stack, S12, contains 2 * C chips. The bottommost chip of S12 is the bottommost chip from S2. On top of that chip, is the bottommost chip from S1. The interleaving process continues taking the 2nd chip from the bottom of S2 and placing that on S12, followed by the 2nd chip from the bottom of S1 and so on until the topmost chip from S1 is placed on top of S12.
After the shuffle operation, S12 is split into 2 new stacks by taking the bottommost C chips from S12 to form a new S1 and the topmost C chips from S12 to form a new S2. The shuffle operation may then be repeated to form a newS12.
For this problem, you will write a program to determine if a particular resultant stack S12 can be formed by shuffling two stacks some number of times.
Input
The first line of input contains a single integer N, (1 ≤ N ≤ 1000) which is the number of datasets that follow.
Each dataset consists of four lines of input. The first line of a dataset specifies an integer C, (1 ≤ C ≤ 100) which is the number of chips in each initial stack (S1 and S2). The second line of each dataset specifies the colors of each of theC chips in stack S1, starting with the bottommost chip. The third line of each dataset specifies the colors of each of the C chips in stack S2 starting with the bottommost chip. Colors are expressed as a single uppercase letter (A throughH). There are no blanks or separators between the chip colors. The fourth line of each dataset contains 2 * C uppercase letters (A through H), representing the colors of the desired result of the shuffling of S1 and S2 zero or more times. The bottommost chip’s color is specified first.
Output
Output for each dataset consists of a single line that displays the dataset number (1 though N), a space, and an integer value which is the minimum number of shuffle operations required to get the desired resultant stack. If the desired result can not be reached using the input for the dataset, display the value negative 1 (−1) for the number of shuffle operations.
Sample Input
2
4
AHAH
HAHA
HHAAAAHH
3
CDE
CDE
EEDDCC
Sample Output
1 2
2 -1
Source
#include<cstdio>
#include<cstring>
#include<iostream>
using namespace std;
#define N 1010
char s1[N],s2[N],str[N],shuffle[N],goal[N];
int x,n;
inline int dfs(){
int step=,x,y,i;
for(;;){
step++;
x=y=;
for(int i=;i<*n;i++){
if(i%==)
shuffle[i]=s2[x++];
else
shuffle[i]=s1[y++];
}
shuffle[*n]='\0';
if(strcmp(shuffle,goal)==) return step;
if(strcmp(shuffle,str)==) return -;
strncpy(s1,shuffle,n);
s1[n]='\0';
strncpy(s2,shuffle+n,n);
s2[n]='\0';
}
}
int main(){
cin>>x;
for(int t=;t<=x;t++){
cin>>n;
cin>>s1>>s2>>goal;
strncpy(str,s1,n);
strncpy(str+n,s2,n);
str[*n]='\0';
cout<<t<<" "<<dfs()<<endl;
}
return ;
}
Poj3087的更多相关文章
- POJ3087 Shuffle'm Up 简单模拟
题意:就是给你两副扑克,然后一张盖一张洗牌,不断重复这个过程,看能不能达到目标的扑克顺序 分析:然后就模拟下,-1的情况就是有循环节 #include<cstdio> #include&l ...
- POJ3087 Shuffle'm Up(模拟)
题目链接. AC代码如下; #include <iostream> #include <cstdio> #include <cstring> #include &l ...
- 搜索:POJ2251&POJ1426&POJ3087&POJ2488
图的遍历也称为搜索,就是从图中某个顶点出发,沿着一些边遍历图中所有的顶点,且每个顶点仅被访问一次,遍历可采取两种不同的方式:深度优先搜索(DFS)和广度优先搜索(BFS). 1.DFS算法思想` 从顶 ...
- poj3087 Shuffle'm Up(bfs)
http://poj.org/problem?id=3087 注意复制字符串的时候,要在末尾加上'\0',否则导致strcmp出错. 还有就是开数组大小的时候看清楚一点,别开错了debug了好久. # ...
- poj3087 Shuffle'm Up(模拟)
Shuffle'm Up Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 10766 Accepted: 4976 Des ...
- POJ3087:Shuffle'm Up(模拟)
http://poj.org/problem?id=3087 Description A common pastime for poker players at a poker table is to ...
- POJ-3087 Shuffle'm Up (模拟)
Description A common pastime for poker players at a poker table is to shuffle stacks of chips. Shuff ...
- POJ3087(KB1-G 简单搜索)
Shuffle'm Up Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 10366 Accepted: 4800 Des ...
- POJ3087(模拟)
#include"iostream" #include"string" #include"map" using namespace std; ...
随机推荐
- JavaScript-深入理解JavaScript(一、预编译和执行过程)
一.预解析 JavaScript 在执行前会进行类似“预解析”的操作:首先会创建一个在当前执行环境下的活动对象, 并将那些用 var 声明的变量.定义的函数设置为活动对象的属性, 但是此时这些变量的赋 ...
- CI框架下nginx重写规则
因为: server { listen ; server_name 222.73.130.124; location / { index index.html index.htm index.php; ...
- AFN访问https设置
AFN访问https的时候需要设定如下两个属性: manager.securityPolicy.allowInvalidCertificates = YES; manager.securityPoli ...
- MongoDB Query 判断为空 取值为空的时间
if (!string.IsNullOrEmpty(STATES)) { DateTime? dtnull = null; //Return if (STATES == "Return&qu ...
- 浅谈ThreadPool 线程池(引用)
出自:http://www.cnblogs.com/xugang/archive/2010/04/20/1716042.html 浅谈ThreadPool 线程池 相关概念: 线程池可以看做容纳线程的 ...
- Django中的 动态URL配置
举个例子,一家在线书店会为每一本书提供一个URL,如:/books/243/./books/81196/. 让我们创建第三个视图来显示当前时间和加上时间偏差量的时间,设计是这样的: /time/plu ...
- .Net MVC ViewBag
ViewBag用来做视图的值绑定,我不清楚是不是这么称呼.之前看过安卓的值绑定做法,mvc直接动态类型,瞬间逼格满满 Controller: public class HomeController : ...
- atitit.nfc 身份证 银行卡 芯片卡 解决方案 attilax总结
atitit.nfc 身份证 银行卡 芯片卡 解决方案 attilax总结 1. nfc(近距离无线通讯技术) 1 2. 工作模式 1 3. NFC 蓝牙 红外具体对比如下表: 2 4. TypeA ...
- 文件上传之 commons-fileupload(二)
对commons fileupload上传组件的简单封装 在上一篇文章<利用Jakarta commons fileupload组件实现多文件上传>中,我介绍了commons fileup ...
- python学习之locals()
locals() 返回一个字典对象.收集并返回局部变量.可以用在函数中,用来收集局部变量. >>> def f(): ... a = 'tom' ... print(locals() ...