选择的钥匙一定是连续的,人和钥匙一定从左到右连续对应。

就枚举钥匙区间即可。

#include<cstdio>
#include<algorithm>
using namespace std;
int Abs(int x){
return x<0 ? (-x) : x;
}
int n,K,p,a[1010],ans=2147483647,b[2010];
int main(){
scanf("%d%d%d",&n,&K,&p);
for(int i=1;i<=n;++i){
scanf("%d",&a[i]);
}
for(int i=1;i<=K;++i){
scanf("%d",&b[i]);
}
sort(a+1,a+n+1);
sort(b+1,b+K+1);
for(int i=1;i<=K;++i){
if(i+n-1>K){
break;
}
int maxx=0;
for(int j=1,k=i;j<=n;++j,++k){
maxx=max(maxx,Abs(a[j]-b[k])+Abs(b[k]-p));
}
ans=min(ans,maxx);
}
printf("%d\n",ans);
return 0;
}

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