SELECT a.dzzmc, a.dzzdm, a.px, CONVERT(decimal(18, 2), ISNULL(b.sjpfzdf, 0) * 0.6 + (ISNULL(a.zddfzdf, 0) + ISNULL(b.zddfzdf, 0)) / 2 * 0.4) AS zzdf, CONVERT(decimal(18,
2), ISNULL(a.dzzjssjpf, 0) * 0.6 + (ISNULL(a.dzzjszddf, 0) + ISNULL(b.dzzjszddf, 0)) / 2 * 0.4) AS dzzjs, CONVERT(decimal(18, 2), ISNULL(a.dflzsjpf, 0)
* 0.6 + (ISNULL(a.dflzzddf, 0) + ISNULL(b.dflzzddf, 0)) / 2 * 0.4) AS Dflz, CONVERT(decimal(18, 2), ISNULL(a.xcgzsjpf, 0) * 0.6 + (ISNULL(a.xcgzzddf, 0)
+ ISNULL(b.xcgzzddf, 0)) / 2 * 0.4) AS Xcgz, CONVERT(decimal(18, 2), ISNULL(a.ghgzsjpf, 0) * 0.6 + (ISNULL(a.ghgzzddf, 0) + ISNULL(b.ghgzzddf, 0)) / 2 * 0.4) AS ghgz,
CONVERT(decimal(18, 2), ISNULL(a.gqtgzsjpf, 0) * 0.6 + (ISNULL(a.gqtgzzddf, 0) + ISNULL(b.gqtgzzddf, 0)) / 2 * 0.4) AS gqtgz, CONVERT(decimal(18, 2),
ISNULL(a.bmgzsjpf, 0) * 0.6 + (ISNULL(a.bmgzzddf, 0) + ISNULL(b.bmgzzddf, 0)) / 2 * 0.4) AS bmgz, CONVERT(decimal(18, 2), ISNULL(a.xfwdsjpf, 0)
* 0.6 + (ISNULL(a.xfwdzddf, 0) + ISNULL(b.xfwdzddf, 0)) / 2 * 0.4) AS xfwd, CONVERT(decimal(18, 2), ISNULL(a.zhzlsjpf, 0) * 0.6 + (ISNULL(a.zhzlzddf, 0)
+ ISNULL(b.zhzlzddf, 0)) / 2 * 0.4) AS zhzl
FROM (SELECT dbo.BranchGradeInf.branchgradeid, dbo.BranchGradeInf.dzzdm, dbo.BranchGradeInf.pfsj, dbo.BranchGradeInf.qywhzddf, dbo.BranchGradeInf.zddfzdf,
dbo.BranchGradeInf.xfwdzddf, dbo.BranchGradeInf.xfwdsjpf, dbo.BranchGradeInf.zhzlzddf, dbo.BranchGradeInf.zhzlsjpf, dbo.BranchGradeInf.dflzzddf,
dbo.BranchGradeInf.dflzsjpf, dbo.BranchGradeInf.dzzjszddf, dbo.BranchGradeInf.dzzjssjpf, dbo.BranchGradeInf.xcgzzddf, dbo.BranchGradeInf.xcgzsjpf,
dbo.BranchGradeInf.ghgzzddf, dbo.BranchGradeInf.ghgzsjpf, dbo.BranchGradeInf.gqtgzzddf, dbo.BranchGradeInf.gqtgzsjpf, dbo.BranchGradeInf.bmgzzddf,
dbo.BranchGradeInf.bmgzsjpf, dbo.BranchGradeInf.qywhsjpf, dbo.BranchGradeInf.sjpfzdf, dbo.BranchGradeInf.zpf, dbo.BranchGradeInf.ldpf,
dbo.BranchGradeInf.qzpydf, dbo.BranchGradeInf.rwzbwwckf, dbo.BranchGradeInf.aqhbsgkf, dbo.BranchGradeInf.ygwfwjkf, dbo.BranchGradeInf.jhsywdbkf,
dbo.BranchGradeInf.dwbwdkf, dbo.BranchGradeInf.zhzlwdbkf, dbo.BranchGradeInf.dxkfzkf, dbo.BranchGradeInf.cewcrwjlf, dbo.BranchGradeInf.zzdf,
dbo.BranchGradeInf.jd, dbo.PartyBranch.dzzmc, dbo.PartyBranch.zbjb, dbo.PartyBranch.zblx, dbo.PartyBranch.dzzmcjc, dbo.PartyBranch.px
FROM dbo.BranchGradeInf INNER JOIN
dbo.PartyBranch ON dbo.BranchGradeInf.dzzdm = dbo.PartyBranch.dzzdm
WHERE (dbo.BranchGradeInf.jd = 3)) AS a FULL OUTER JOIN
(SELECT BranchGradeInf_1.branchgradeid, BranchGradeInf_1.dzzdm, BranchGradeInf_1.pfsj, BranchGradeInf_1.qywhzddf, BranchGradeInf_1.zddfzdf,
BranchGradeInf_1.xfwdzddf, BranchGradeInf_1.xfwdsjpf, BranchGradeInf_1.zhzlzddf, BranchGradeInf_1.zhzlsjpf, BranchGradeInf_1.dflzzddf,
BranchGradeInf_1.dflzsjpf, BranchGradeInf_1.dzzjszddf, BranchGradeInf_1.dzzjssjpf, BranchGradeInf_1.xcgzzddf, BranchGradeInf_1.xcgzsjpf,
BranchGradeInf_1.ghgzzddf, BranchGradeInf_1.ghgzsjpf, BranchGradeInf_1.gqtgzzddf, BranchGradeInf_1.gqtgzsjpf, BranchGradeInf_1.bmgzzddf,
BranchGradeInf_1.bmgzsjpf, BranchGradeInf_1.qywhsjpf, BranchGradeInf_1.sjpfzdf, BranchGradeInf_1.zpf, BranchGradeInf_1.ldpf,
BranchGradeInf_1.qzpydf, BranchGradeInf_1.rwzbwwckf, BranchGradeInf_1.aqhbsgkf, BranchGradeInf_1.ygwfwjkf, BranchGradeInf_1.jhsywdbkf,
BranchGradeInf_1.dwbwdkf, BranchGradeInf_1.zhzlwdbkf, BranchGradeInf_1.dxkfzkf, BranchGradeInf_1.cewcrwjlf, BranchGradeInf_1.zzdf,
BranchGradeInf_1.jd, PartyBranch_1.dzzmc, PartyBranch_1.zbjb, PartyBranch_1.zblx, PartyBranch_1.dzzmcjc, PartyBranch_1.px
FROM dbo.BranchGradeInf AS BranchGradeInf_1 INNER JOIN
dbo.PartyBranch AS PartyBranch_1 ON BranchGradeInf_1.dzzdm = PartyBranch_1.dzzdm
WHERE (BranchGradeInf_1.jd = 4)) AS b ON a.dzzdm = b.dzzdm
WHERE (a.zbjb = 1)

sql中保留到小数点后两位以及非空判断赋值为零的更多相关文章

  1. Android(java)开发之将double类型,强制保留到小数点后两位解决方法。

    作者:程序员小冰,CSDN博客:http://blog.csdn.net/qq_21376985 前提:当我们进行double数据类型与double进行运算的时候,可能会遇到 得到小数点后好多位,但是 ...

  2. 班上有学生若干名,已知每名学生的成绩(整数),求班上所有学生的平均成绩,保留到小数点后两位。同时输出该平均成绩整数部分四舍五入后的数值。 第一行有一个整数n(1<= n <= 100),表示学生的人数。其后n行每行有1个整数,表示每个学生的成绩,取值在int范围内。

    #include<iostream> #include<iomanip> using namespace std ; int main() { int n; while(cin ...

  3. JS控制文本框只能输入数字 \保留小数点后两位

    <input type="text" placeholder="保留到小数点后两位" maxlength="200" onkeyup= ...

  4. 关于Oracle中查询的数字值的显示格式需要保留小数点后两位(或者三位,及其他位数)

    关于Oracle中查询的数字值的显示格式需要保留小数点后两位(或者三位,及其... 方法一:使用to_char的fm格式,即: to_char(round(data.amount,2),'FM9999 ...

  5. Java中double类型的数据精确到小数点后两位

    Java中double类型的数据精确到小数点后两位 多余位四舍五入,四种方法 一: double f = 111231.5585;BigDecimal b = new BigDecimal(f); d ...

  6. 控制input标签中只能输入数字以及小数点后两位

    js 代码如下: /* 控制input标签中只能输入数字 和小数点后两位 */ function checkNum(obj) { //检查是否是非数字值 if (isNaN(obj.value)) { ...

  7. input内强制保留小数点后两位 位数不足时自动补0

    input内强制保留小数点后两位 位数不足时自动补0 小数点后位数超出2位时进行四舍五入 需引入jquery包 1.11.2版本 1 function xiaoshu(x) 2 { 3 var f = ...

  8. JAVA除法保留小数点后两位的两种方法 Java Math的 floor,round和ceil的总结

    floor 返回不大于的最大整数 round 则是4舍5入的计算,入的时候是到大于它的整数round方法,它表示“四舍五入”,算法为Math.floor(x+0.5),即将原来的数字加上0.5后再向下 ...

  9. Java中取小数点后两位(四种方法)

    摘自http://irobot.iteye.com/blog/285537 Java中取小数点后两位(四种方法)   一 Long是长整型,怎么有小数,是double吧     java.text.D ...

随机推荐

  1. 20145213《Java程序设计》第七周学习总结

    20145213<Java程序设计>第七周学习总结 教材学习内容总结 周末快乐的时间总是短暂的,还没好好感受就到了要写博客的周日.有人喟叹时间都去哪儿了,那本周我们就来认识一下Java里的 ...

  2. .NET后台如何获取前台HMTL控件的值

    很多时候我们需要HTML控件,感觉比服务器控件更加简介,清爽,那么如何获取HMTL控件的值呢,请看下面例子: 前台页面代码: <input id="Text1" type=& ...

  3. Linux iostat字段解析

    iostat主要用于监控系统设备的IO负载情况,iostat首次运行时显示自系统启动开始的各项统计信息,之后运行iostat将显示自上次运行该命令以后的统计信息.用户可以通过指定统计的次数和时间来获得 ...

  4. python基础——单元测试

    python基础——单元测试 如果你听说过“测试驱动开发”(TDD:Test-Driven Development),单元测试就不陌生. 单元测试是用来对一个模块.一个函数或者一个类来进行正确性检验的 ...

  5. alias命令(使用命令别名)

    通过alias命令可以给一些命令定义别名,如,将长的难记住的命令起一个容易记住的别名,提高工作效率 alias -p 查看已有的别名列表 命名别名格式: alias 新命令名='原命令名 -参数/选项 ...

  6. MyEclipse生成WAR包并在Tomcat下部署发布(转发)

    从来没有想过web项目还能打包的,但是有要求,就不得不去实现,在网上找了一下,发现挺简单的. 首先是使用MyEclipse将web项目打包,如下图所示. 右键选中项目,选择export. 然后选择J2 ...

  7. 索引的重载 str["name"] str[i]

    class Program { static void Main(string[] args) { IndexClass names = new IndexClass(); names[] = &qu ...

  8. Linux下pipe使用注意事项

    转自:http://blog.yufeng.info/archives/1485 Linux下的pipe使用非常广泛, shell本身就大量用pipe来粘合生产者和消费者的. 我们的服务器程序通常会用 ...

  9. 重温WCF之构建一个简单的WCF(一)(1)通过控制台和IIS寄宿服务

    一.理解什么是WCFWCF就是.NET平台下各种分布式技术的集成,并提供了一套统一的编程接口 二.WCF的定义WCF(Windows Communication Foundation)是微软为构建面向 ...

  10. Myeclipse 2016 & 2014 下载

    myeclipse-2016-ci-6-offline-installer-windowshttps://downloads.genuitec.com/downloads/myeclipse/inst ...