POJ 2406

其实就是一个简单的kmp应用:

ans = n % (n - f[n]) == 0 ? n / (n - f[n]) : 1

其中f是失配函数

 //#pragma comment(linker, "/STACK:1677721600")
#include <map>
#include <set>
#include <stack>
#include <queue>
#include <cmath>
#include <ctime>
#include <vector>
#include <cstdio>
#include <cctype>
#include <cstring>
#include <cstdlib>
#include <iostream>
#include <algorithm>
using namespace std;
#define INF 0x3f3f3f3f
#define inf (-((LL)1<<40))
#define lson k<<1, L, (L + R)>>1
#define rson k<<1|1, ((L + R)>>1) + 1, R
#define mem0(a) memset(a,0,sizeof(a))
#define mem1(a) memset(a,-1,sizeof(a))
#define mem(a, b) memset(a, b, sizeof(a))
#define FIN freopen("in.txt", "r", stdin)
#define FOUT freopen("out.txt", "w", stdout)
#define rep(i, a, b) for(int i = a; i <= b; i ++)
#define dec(i, a, b) for(int i = a; i >= b; i --) template<class T> T MAX(T a, T b) { return a > b ? a : b; }
template<class T> T MIN(T a, T b) { return a < b ? a : b; }
template<class T> T GCD(T a, T b) { return b ? GCD(b, a%b) : a; }
template<class T> T LCM(T a, T b) { return a / GCD(a,b) * b; } //typedef __int64 LL;
typedef long long LL;
const int MAXN = + ;
const int MAXM = ;
const double eps = 1e-;
LL MOD = ; char s[MAXN];
int f[MAXN]; void get_next(int n) {
mem0(f);
rep (i, , n - ) {
int j = f[i];
while(j && s[i] != s[j]) j = f[j];
f[i + ] = s[i] == s[j] ? j + : ;
}
} int main()
{
//FIN;
while(~scanf("%s", s) && s[] != '.') {
int n = strlen(s);
get_next(n);
printf("%d\n", n % (n - f[n]) == ? n / (n - f[n]) : );
}
return ;
}

POJ 2406Power Strings(KMP)的更多相关文章

  1. poj 2406Power Strings

    http://poj.org/problem?id=2406 #include<cstdio> #include<cstring> #include<algorithm& ...

  2. POJ 1961 Period( KMP )*

    Period Time Limit: 3000MSMemory Limit: 30000K Total Submissions: 12089Accepted: 5656 Description For ...

  3. POJ 2406 Power Strings (KMP)

    Power Strings Time Limit: 3000MSMemory Limit: 65536K Total Submissions: 29663Accepted: 12387 Descrip ...

  4. poj 2406 Power Strings kmp算法

    点击打开链接 Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 27368   Accepted:  ...

  5. poj 2406 Power Strings (kmp 中 next 数组的应用||后缀数组)

    http://poj.org/problem?id=2406 Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submiss ...

  6. POJ 2406 - Power Strings - [KMP求最小循环节]

    题目链接:http://poj.org/problem?id=2406 Time Limit: 3000MS Memory Limit: 65536K Description Given two st ...

  7. POJ:2406-Power Strings(寻找字符串循环节)

    Power Strings Time Limit: 3000MS Memory Limit: 65536K Description Given two strings a and b we defin ...

  8. POJ 2406 Power Strings KMP运用题解

    本题是计算一个字符串能完整分成多少一模一样的子字符串. 原来是使用KMP的next数组计算出来的,一直都认为是能够利用next数组的.可是自己想了非常久没能这么简洁地总结出来,也仅仅能查查他人代码才恍 ...

  9. poj 2406 Power Strings(KMP变形)

    Power Strings Time Limit: 3000MS   Memory Limit: 65536K Total Submissions: 28102   Accepted: 11755 D ...

随机推荐

  1. 35. Search Insert Position(二分查找)

    Given a sorted array and a target value, return the index if the target is found. If not, return the ...

  2. 234. Palindrome Linked List(判断链表是否回文)

    Given a singly linked list, determine if it is a palindrome. Follow up:Could you do it in O(n) time ...

  3. 92. Reverse Linked List II(链表部分反转)

    Reverse a linked list from position m to n. Do it in-place and in one-pass. For example:Given 1-> ...

  4. 470. Implement Rand10() Using Rand7() (拒绝采样Reject Sampling)

    1. 问题 已提供一个Rand7()的API可以随机生成1到7的数字,使用Rand7实现Rand10,Rand10可以随机生成1到10的数字. 2. 思路 简单说: (1)通过(Rand N - 1) ...

  5. Spring MVC 复习笔记04

    复习 springmvc框架: DispatcherServlet前端控制器:接收request,进行response HandlerMapping处理器映射器:根据url查找Handler.(可以通 ...

  6. selenium-python读取XML文件

    首先这是我们要读取的XML文件 <?xml version="1.0" encoding="utf-8" ?><info> <ba ...

  7. tomcat的安装和启动

    下载apache-tomcat-8.5.5-src,我将其放在了/usr/local/tomcat目录下 要启动需要运行: /usr/local/tomcat/apache-tomcat-8.5.5- ...

  8. ZLYD团队第三周项目总结

    ZLYD团队第三周项目总结 项目进展 我们的吃豆子游戏的程序由八个文件组成:Wall.java.Gold.java.Player.java.Fruit.java.Enemy.java.Ticker.j ...

  9. godaddy之ssl申请

    第一步 执行下面命令生成csr和key文件 openssl req -new -newkey rsa: -nodes -keyout trips.com.key -out trips.com.csr ...

  10. Flask 1 Introductory Chapter

    reference: <Flask Web 开发> Environment Python 3 Mac OSX Introductory Chapter: 安装 1.安装第三方工具 virt ...