Codeforces Round #250 (Div. 2)—A. The Child and Homework
好题啊,被HACK了。曾经做题都是人数越来越多。这次比赛 PASS人数 从2000直掉 1000人 被HACK 1000多人!
!
!
!
没见过的科技啊
1 2 4 8 这组数 被黑的
1 second
256 megabytes
standard input
standard output
Once upon a time a child got a test consisting of multiple-choice questions as homework. A multiple-choice question consists of four choices: A, B, C and D.
Each choice has a description, and the child should find out the only one that is correct.
Fortunately the child knows how to solve such complicated test. The child will follow the algorithm:
- If there is some choice whose description at least twice shorter than all other descriptions, or at least twice longer than all other descriptions, then the child thinks the choice is great.
- If there is exactly one great choice then the child chooses it. Otherwise the child chooses C (the child think it is the luckiest choice).
You are given a multiple-choice questions, can you predict child's choose?
The first line starts with "A." (without quotes), then followed the description of choice A.
The next three lines contains the descriptions of the other choices in the same format. They are given in order: B, C, D. Please
note, that the description goes after prefix "X.", so the prefix mustn't be counted in description's length.
Each description is non-empty and consists of at most 100 characters. Each character can be either uppercase English letter or lowercase English letter, or "_".
Print a single line with the child's choice: "A", "B", "C"
or "D" (without quotes).
A.VFleaKing_is_the_author_of_this_problem
B.Picks_is_the_author_of_this_problem
C.Picking_is_the_author_of_this_problem
D.Ftiasch_is_cute
D
A.ab
B.abcde
C.ab
D.abc
C
A.c
B.cc
C.c
D.c
B
In the first sample, the first choice has length 39, the second one has length 35, the third one has length 37, and the last one has length 15. The choice D (length
15) is twice shorter than all other choices', so it is great choice. There is no other great choices so the child will choose D.
In the second sample, no choice is great, so the child will choose the luckiest choice C.
In the third sample, the choice B (length 2) is twice longer than all other choices', so it is great choice. There is no other great choices so the child will
choose B.
AC:
#include <iostream>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <algorithm>
const int N = 110;
using namespace std;
char a[10][N];
int s[10];
int main()
{
for(int i = 0;i<4;i++)
{
scanf("%s",a[i]);
s[i] = strlen(a[i]);
s[i] -=2;
}
int flag = 0,flag1 = 0;
sort(s,s+4);
int ma = s[3];
int mi = s[0];
for(int i = 1;i<4;i++)
{
if(s[0]==0)
break;
if((s[i]/s[0])>=2)
{
flag++;
}
}
for(int i = 0;i<3;i++)
{
if(s[i]==0)
break;
if((s[3]/s[i])>=2)
{
flag1++; }
} if(flag1==3 && flag!=3)
{
for(int i = 0;i<4;i++)
{
int len = strlen(a[i]);
len -= 2;
if(len==ma)
{
printf("%c",'A'+i);
}
}
}
else if(flag==3 && flag1!=3)
{
for(int i = 0;i<4;i++)
{
int len = strlen(a[i]);
len -=2;
if(len==mi)
{
printf("%c",'A'+i);
}
}
}
else
printf("C\n"); return 0;
}
Codeforces Round #250 (Div. 2)—A. The Child and Homework的更多相关文章
- Codeforces Round #250 (Div. 2) A. The Child and Homework
注意题目长度不能考虑前缀,而且如果即存在一个选项的长度的两倍小于其他所有选项的长度,也存在一个选项的长度大于其他选项长度的两倍,则答案不是一个好的选择,只能选择C. #include <iost ...
- Codeforces Round #250 (Div. 1) D. The Child and Sequence 线段树 区间取摸
D. The Child and Sequence Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest ...
- Codeforces Round #250 (Div. 1) B. The Child and Zoo 并查集
B. The Child and Zoo Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/438/ ...
- Codeforces Round #250 (Div. 1) A. The Child and Toy 水题
A. The Child and Toy Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/438/ ...
- Codeforces Round #250 (Div. 1) D. The Child and Sequence (线段树)
题目链接:http://codeforces.com/problemset/problem/438/D 给你n个数,m个操作,1操作是查询l到r之间的和,2操作是将l到r之间大于等于x的数xor于x, ...
- Codeforces Round #250 (Div. 1) D. The Child and Sequence(线段树)
D. The Child and Sequence time limit per test 4 seconds memory limit per test 256 megabytes input st ...
- Codeforces Round #250 (Div. 1) D. The Child and Sequence
D. The Child and Sequence time limit per test 4 seconds memory limit per test 256 megabytes input st ...
- Codeforces Round #250 (Div. 2) D. The Child and Zoo 并查集
D. The Child and Zoo time limit per test 2 seconds memory limit per test 256 megabytes input standar ...
- Codeforces Round #250 (Div. 2)B. The Child and Set 暴力
B. The Child and Set At the children's day, the child came to Picks's house, and messed his house ...
随机推荐
- result 相关
1.dispatcher 2.redirect 3.chain 4.redirectAction 5.freemarker 6.httpheader 7.stream 8.velocity 9.xsl ...
- iOS 设置状态栏的颜色
1.在plist文件中设置如下属性: 2.在delegate中设置 [[UIApplication sharedApplication] setStatusBarStyle:UIStatusBarSt ...
- TabelView的多选模式
@interface ViewController ()<UITableViewDelegate,UITableViewDataSource> @property(nonatomic,st ...
- 内置的材质包含文件 .cginc
Unity中包含几个文件,可以用于你的Shader程序,里面包含了预定义的变量和辅助函数.使用它需要用 #include指令 CGPROGRAM // ... #include "Unity ...
- N个任务掌握java系列之统计一篇文章中单词出现的次数
问题:统计一篇文章中单词出现的次数 思路: (1)将文章(一个字符串存储)按空格进行拆分(split)后,存储到一个字符串(单词)数组中. (2)定义一个Map,key是字符串类型,保存单词:valu ...
- AeroSpike 记录
1.基本概念: namespace:类似关系型数据库中的schema,这个需要在配置文件中配置,可以指定存储引擎.存储大小.备份数.存活时间等 set:类似关系型数据库中的表 record:类似关系型 ...
- jQuery validate入门
<html> <head> <meta charset="utf8"></meta> </head> <body& ...
- [Windows编程] 使用AttachThreadInput 来捕捉其它窗口的键盘输入
在一些情况下(比如屏幕软键盘或者输入法程序),自己的窗口没有输入焦点但是想要当前焦点窗口的键盘输入消息,可以使用Win32 API函数AttachThreadInput()来解决这个问题.Attach ...
- 汇编语言学习——第二章 寄存器(CPU工作原理)
1.一个典型的CPU由运算器.控制器.寄存器等器件组成,这些器件靠内部总线相连. 区别: 内部总线实现CPU内部各个器件之间的联系. 外部总线实现CPU和主板上其它器件的联系. 8086CPU有14个 ...
- 【PAT】1009. Product of Polynomials (25)
题目链接:http://pat.zju.edu.cn/contests/pat-a-practise/1009 分析:简单题.相乘时指数相加,系数相乘即可,输出时按指数从高到低的顺序.注意点:多项式相 ...