The 2018 ACM-ICPC Chinese Collegiate Programming Contest Caesar Cipher
#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>
#include <algorithm>
#include <utility>
#include <vector>
#include <map>
#include <queue>
#include <stack>
#include <cstdlib>
typedef long long ll;
#define lowbit(x) (x&(-x))
#define ls l,m,rt<<1
#define rs m+1,r,rt<<1|1
using namespace std;
int t,n,m;
string s1,s2,s3;
int main()
{
scanf("%d",&t);
for(int i=;i<=t;i++)
{
scanf("%d%d",&n,&m);
cin>>s1>>s2>>s3;
int x=s2[]-s1[];
for(int i=;i<m;i++){
s3[i]-=x;//最好改自己
if(s3[i]<'A') s3[i]+=;
else if(s3[i]>'Z') s3[i]-=;
}
printf("Case #%d: ",i);
for(int i=;i<m;i++){
printf("%c",s3[i]);
}
printf("\n");
}
return ;
}
/*
以下是针对本题的误区
string s;
s="";
for(int i=0;i<3;i++){
s[i]='A';
printf("%c\n",s[i]);
}
cout<<s<<endl;//会出现段错误
A
A
A //应为s=""时就默认s.size()=0了
//若改为s=" ",两个空格,最后输出AA。
*/
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