LeetCode(225) Implement Stack using Queues
题目
Implement the following operations of a stack using queues.
push(x) – Push element x onto stack.
pop() – Removes the element on top of the stack.
top() – Get the top element.
empty() – Return whether the stack is empty.
Notes:
You must use only standard operations of a queue – which means only push to back, peek/pop from front, size, and is empty operations are valid.
Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
分析
用队列实现栈。
用两个队列,其中一个队列用户存储当前元素,另一个辅助队列作为pop和top操作时的临时存储。并利用flag标志,表示存储当前所有元素的队列。
AC代码
class Stack {
public:
// Push element x onto stack.
void push(int x) {
que[flag].push(x);
}
// Removes the element on top of the stack.
void pop() {
while (que[flag].size() > 1)
{
que[1 - flag].push(que[flag].front());
que[flag].pop();
}//while
que[flag].pop();
flag = 1 - flag;
}
// Get the top element.
int top() {
while (que[flag].size() > 1)
{
que[1 - flag].push(que[flag].front());
que[flag].pop();
}//while
int ret = que[flag].front();
que[1 - flag].push(que[flag].front());
que[flag].pop();
flag = 1 - flag;
return ret;
}
// Return whether the stack is empty.
bool empty() {
return que[flag].empty();
}
private:
queue<int> que[2];
int flag = 0; //作为存储队列
};
LeetCode(225) Implement Stack using Queues的更多相关文章
- LeetCode(28)Implement strStr()
题目 Implement strStr(). Returns the index of the first occurrence of needle in haystack, or -1 if nee ...
- LeetCode(232) Implement Queue using Stacks
题目 Implement the following operations of a queue using stacks. push(x) – Push element x to the back ...
- LeetCode(155) Min Stack
题目 Design a stack that supports push, pop, top, and retrieving the minimum element in constant time. ...
- 【LeetCode】232 & 225 - Implement Queue using Stacks & Implement Stack using Queues
232 - Implement Queue using Stacks Implement the following operations of a queue using stacks. push( ...
- leetcode 155. Min Stack 、232. Implement Queue using Stacks 、225. Implement Stack using Queues
155. Min Stack class MinStack { public: /** initialize your data structure here. */ MinStack() { } v ...
- leetcode:Implement Stack using Queues 与 Implement Queue using Stacks
一.Implement Stack using Queues Implement the following operations of a stack using queues. push(x) - ...
- 232. Implement Queue using Stacks,225. Implement Stack using Queues
232. Implement Queue using Stacks Total Accepted: 27024 Total Submissions: 79793 Difficulty: Easy Im ...
- Implement Queue by Two Stacks & Implement Stack using Queues
Implement Queue by Two Stacks Implement the following operations of a queue using stacks. push(x) -- ...
- LeetCode(275)H-Index II
题目 Follow up for H-Index: What if the citations array is sorted in ascending order? Could you optimi ...
随机推荐
- NET Core 2.0 自定义
ASP.NET Core 2.0 自定义 _ViewStart 和 _ViewImports 的目录位置 在 ASP.NET Core 里扩展 Razor 查找视图目录不是什么新鲜和困难的事情,但 _ ...
- Linux下常用的数据恢复工具
一.数据删除 命令:rm -rf,将任何数据直接从硬盘删除,且没有任何提示 建议做法: 把命令参数放到后面:rm -rfi 将删除的东西通过mv命令移动到系统下的/temp目录下,然后写个脚 本定期执 ...
- WebView全面学习(一)--常用类和方法
WebView全面学习(一)--常用类和方法 WebView本质上是一个View,他基于webkit引擎来展示web页面 在Android不同的版本webkit内核有所区别,从Android版本上看, ...
- gitlab api批量操作 批量添加用户
import os,time import requests,json # def downloadFile(name, url): # headers = {'Proxy-Connection': ...
- SQLServer 2012 Always on配置全过程
AlwaysOn取数据库镜像和故障转移集群之长.AlwaysOn不再像故障转移集群那样需要共享磁盘,从而主副本和辅助副本可以更容易的部署到不同的地理位置:AlwaysOn还打破了镜像只能1对1的限制, ...
- LibreOJ #2037. 「SHOI2015」脑洞治疗仪
线段树区间合并问题 恶心... 屠龙宝刀点击就送 #include <cstdio> #define N 200005 struct Segment { int l,r,mid,sum,l ...
- 洛谷 P2895 [USACO08FEB]流星雨Meteor Shower
题目描述 Bessie hears that an extraordinary meteor shower is coming; reports say that these meteors will ...
- python基础教程总结10——文件
1.打开文件 open(name[mode[,buffing]) 参数: 文件,模式,缓冲 1)name: 是强制选项,模式和缓冲是可选的 #如果文件不在,会报下面错误1 >>&g ...
- UVA 12673 Erratic Expansion 奇怪的气球膨胀 (递推)
不难发现,每过一个小时,除了右下方的气球全都是蓝色以外,其他都和上一个小时的气球是一样的,所以是可以递推的.然后定义一类似个前缀和的东西f(k,i)表示k小时之后上面i行的红气球数.预处理出k小时的红 ...
- Predicate Programming Guide
https://developer.apple.com/library/content/documentation/Cocoa/Conceptual/Predicates/AdditionalChap ...