【LeetCode】622. Design Circular Queue 解题报告(Python & C++)
作者: 负雪明烛
id: fuxuemingzhu
个人博客: http://fuxuemingzhu.cn/
题目地址:https://leetcode.com/problems/design-circular-queue/description/
题目描述
Design your implementation of the circular queue. The circular queue is a linear data structure in which the operations are performed based on FIFO (First In First Out) principle and the last position is connected back to the first position to make a circle. It is also called ‘Ring Buffer’.
One of the Benefits of the circular queue is that we can make use of the spaces in front of the queue. In a normal queue, once the queue becomes full, we can not insert the next element even if there is a space in front of the queue. But using the circular queue, we can use the space to store new values.
Your implementation should support following operations:
- MyCircularQueue(k): Constructor, set the size of the queue to be k.
- Front: Get the front item from the queue. If the queue is empty, return -1.
- Rear: Get the last item from the queue. If the queue is empty, return -1.
- enQueue(value): Insert an element into the circular queue. Return true if the operation is successful.
- deQueue(): Delete an element from the circular queue. Return true if the operation is successful.
- isEmpty(): Checks whether the circular queue is empty or not.
- isFull(): Checks whether the circular queue is full or not.
Example:
MyCircularQueue circularQueue = new MycircularQueue(3); // set the size to be 3
circularQueue.enQueue(1); // return true
circularQueue.enQueue(2); // return true
circularQueue.enQueue(3); // return true
circularQueue.enQueue(4); // return false, the queue is full
circularQueue.Rear(); // return 3
circularQueue.isFull(); // return true
circularQueue.deQueue(); // return true
circularQueue.enQueue(4); // return true
circularQueue.Rear(); // return 4
Note:
- All values will be in the range of [1, 1000].
- The number of operations will be in the range of [1, 1000].
- Please do not use the built-in Queue library.
题目大意
实现一个环形链表。
解题方法
用直的代替弯的
环形的肯定不好设计,于是我就是直接弄了一个直的,不断的整体往后移,保持最大容纳k个元素。只需要维护好front和rear指针,就能模拟出来一个环状队列。
需要注意的几个点:
- Front()和Rear()函数要判断是否为空;
- 在得到元素的时候rear-1,而front不用。
代码如下:
class MyCircularQueue(object):
def __init__(self, k):
"""
Initialize your data structure here. Set the size of the queue to be k.
:type k: int
"""
self.queue = []
self.size = k
self.front = 0
self.rear = 0
def enQueue(self, value):
"""
Insert an element into the circular queue. Return true if the operation is successful.
:type value: int
:rtype: bool
"""
if self.rear - self.front < self.size:
self.queue.append(value)
self.rear += 1
return True
else:
return False
def deQueue(self):
"""
Delete an element from the circular queue. Return true if the operation is successful.
:rtype: bool
"""
if self.rear - self.front > 0:
self.front += 1
return True
else:
return False
def Front(self):
"""
Get the front item from the queue.
:rtype: int
"""
if self.isEmpty():
return -1
else:
return self.queue[self.front]
def Rear(self):
"""
Get the last item from the queue.
:rtype: int
"""
if self.isEmpty():
return -1
else:
return self.queue[self.rear - 1]
def isEmpty(self):
"""
Checks whether the circular queue is empty or not.
:rtype: bool
"""
return self.front == self.rear
def isFull(self):
"""
Checks whether the circular queue is full or not.
:rtype: bool
"""
return self.rear - self.front == self.size
# Your MyCircularQueue object will be instantiated and called as such:
# obj = MyCircularQueue(k)
# param_1 = obj.enQueue(value)
# param_2 = obj.deQueue()
# param_3 = obj.Front()
# param_4 = obj.Rear()
# param_5 = obj.isEmpty()
# param_6 = obj.isFull()
在经过做641. Design Circular Deque之后,我发现其实头尾指针都是不重要的,只要我们维护好这个list,使得这个list中保存的就是队列里面应该剩下来的元素即可。
所以删除头指针front的代码如下:
class MyCircularQueue(object):
def __init__(self, k):
"""
Initialize your data structure here. Set the size of the queue to be k.
:type k: int
"""
self.queue = []
self.size = k
self.rear = 0
def enQueue(self, value):
"""
Insert an element into the circular queue. Return true if the operation is successful.
:type value: int
:rtype: bool
"""
if not self.isFull():
self.queue.append(value)
self.rear += 1
return True
else:
return False
def deQueue(self):
"""
Delete an element from the circular queue. Return true if the operation is successful.
:rtype: bool
"""
if not self.isEmpty():
self.queue.pop(0)
self.rear -= 1
return True
else:
return False
def Front(self):
"""
Get the front item from the queue.
:rtype: int
"""
if self.isEmpty():
return -1
else:
return self.queue[0]
def Rear(self):
"""
Get the last item from the queue.
:rtype: int
"""
if self.isEmpty():
return -1
else:
return self.queue[self.rear - 1]
def isEmpty(self):
"""
Checks whether the circular queue is empty or not.
:rtype: bool
"""
return 0 == self.rear
def isFull(self):
"""
Checks whether the circular queue is full or not.
:rtype: bool
"""
return self.rear == self.size
# Your MyCircularQueue object will be instantiated and called as such:
# obj = MyCircularQueue(k)
# param_1 = obj.enQueue(value)
# param_2 = obj.deQueue()
# param_3 = obj.Front()
# param_4 = obj.Rear()
# param_5 = obj.isEmpty()
# param_6 = obj.isFull()
同理,只要维护的list中保存的元素和队列应该有的元素相同的,那么末尾指针rear一直指向了list的结尾,所以,可以把rear也删除。
删除front和rear的代码如下:
class MyCircularQueue(object):
def __init__(self, k):
"""
Initialize your data structure here. Set the size of the queue to be k.
:type k: int
"""
self.queue = []
self.size = k
def enQueue(self, value):
"""
Insert an element into the circular queue. Return true if the operation is successful.
:type value: int
:rtype: bool
"""
if not self.isFull():
self.queue.append(value)
return True
else:
return False
def deQueue(self):
"""
Delete an element from the circular queue. Return true if the operation is successful.
:rtype: bool
"""
if not self.isEmpty():
self.queue.pop(0)
return True
else:
return False
def Front(self):
"""
Get the front item from the queue.
:rtype: int
"""
if self.isEmpty():
return -1
else:
return self.queue[0]
def Rear(self):
"""
Get the last item from the queue.
:rtype: int
"""
if self.isEmpty():
return -1
else:
return self.queue[-1]
def isEmpty(self):
"""
Checks whether the circular queue is empty or not.
:rtype: bool
"""
return 0 == len(self.queue)
def isFull(self):
"""
Checks whether the circular queue is full or not.
:rtype: bool
"""
return len(self.queue) == self.size
# Your MyCircularQueue object will be instantiated and called as such:
# obj = MyCircularQueue(k)
# param_1 = obj.enQueue(value)
# param_2 = obj.deQueue()
# param_3 = obj.Front()
# param_4 = obj.Rear()
# param_5 = obj.isEmpty()
# param_6 = obj.isFull()
数组循环利用
环形队列的物理结构就是一个固定长度的数组,然后前后指针到达尾部之后,移到最前。使用了first指针指向队列的首部,使用了last指针指向了队列的尾部的后一个元素。
C++代码如下:
class MyCircularQueue {
public:
/** Initialize your data structure here. Set the size of the queue to be k. */
MyCircularQueue(int k) {
q = vector<int>(k + 1, 0);
K = k;
first = 0;
last = 0;
count = 0;
}
/** Insert an element into the circular queue. Return true if the operation is successful. */
bool enQueue(int value) {
if (!isFull()) {
q[last] = value;
last = (last + 1 + K) % K;
count ++;
return true;
} else {
return false;
}
}
/** Delete an element from the circular queue. Return true if the operation is successful. */
bool deQueue() {
if (!isEmpty()) {
int val = q[first];
first = (first + 1 + K) % K;
count --;
return true;
} else {
return false;
}
}
/** Get the front item from the queue. */
int Front() {
if (isEmpty())
return -1;
return q[first];
}
/** Get the last item from the queue. */
int Rear() {
if (isEmpty())
return -1;
return q[(last - 1 + K) % K];
}
/** Checks whether the circular queue is empty or not. */
bool isEmpty() {
return count == 0;
}
/** Checks whether the circular queue is full or not. */
bool isFull() {
return count == K;
}
private:
vector<int> q;
int first;
int last;
int K;
int count;
};
/**
* Your MyCircularQueue object will be instantiated and called as such:
* MyCircularQueue* obj = new MyCircularQueue(k);
* bool param_1 = obj->enQueue(value);
* bool param_2 = obj->deQueue();
* int param_3 = obj->Front();
* int param_4 = obj->Rear();
* bool param_5 = obj->isEmpty();
* bool param_6 = obj->isFull();
*/
日期
2018 年 7 月 13 日 —— 早起困一上午,中午必须好好休息才行啊
2018 年 12 月 12 日 —— 双十二
【LeetCode】622. Design Circular Queue 解题报告(Python & C++)的更多相关文章
- [LeetCode] 622.Design Circular Queue 设计环形队列
Design your implementation of the circular queue. The circular queue is a linear data structure in w ...
- LeetCode 622. Design Circular Queue
原题链接在这里:https://leetcode.com/problems/design-circular-queue/ 题目: Design your implementation of the c ...
- 【LeetCode】641. Design Circular Deque 解题报告(Python & C++)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/design-ci ...
- 【leetcode】622. Design Circular Queue
题目如下: Design your implementation of the circular queue. The circular queue is a linear data structur ...
- 【LeetCode】899. Orderly Queue 解题报告(Python)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址: https://leetcode.com/problems/orderly- ...
- 【LeetCode】62. Unique Paths 解题报告(Python & C++)
作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fuxuemingzhu.cn/ 题目地址:https://leetcode.com/problems/unique-pa ...
- [LeetCode] 641.Design Circular Deque 设计环形双向队列
Design your implementation of the circular double-ended queue (deque). Your implementation should su ...
- LeetCode 622:设计循环队列 Design Circular Queue
LeetCode 622:设计循环队列 Design Circular Queue 首先来看看队列这种数据结构: 队列:先入先出的数据结构 在 FIFO 数据结构中,将首先处理添加到队列中的第一个元素 ...
- 【LeetCode】456. 132 Pattern 解题报告(Python)
[LeetCode]456. 132 Pattern 解题报告(Python) 标签(空格分隔): LeetCode 作者: 负雪明烛 id: fuxuemingzhu 个人博客: http://fu ...
随机推荐
- Excel—在Excel中利用宏定义实现MD5对字符串(如:手机号)或者文件加密
下载宏文件[md5宏] 加载宏 试验md5加密 可能遇到的问题 解决办法 下载宏文件[md5宏] 下载附件,解压,得md5宏.xla md5宏.zip 加载宏 依次打开[文件]-[选项]-[自定义功能 ...
- CPF C#跨平台UI框架发布安卓端预览版
CPF的安卓端适配采用Xamarin的安卓绑定库,而不是Xamarin.Form.CPF和flutter差不多,完全由skia绘制,基本不依赖原生控件. 当前还只是预览版,不建议用在正式项目中. 可能 ...
- 一次线上GC故障解决过程记录
排查了三四个小时,终于解决了这个GC问题,记录解决过程于此,希望对大家有所帮助.本文假定读者已具备基本的GC常识和JVM调优知识,关于JVM调优工具使用可以查看我在同一分类下的另一篇文章: http: ...
- Java实现单链表的增删查改及逆置打印
//所提供的接口 LinkList.java package Struct; public interface LinkList {//判断链表为空public boolean linkListIsE ...
- easyhadoop 安装
ldconfig deferred processing now taking place正在处理用于 libapache2-mod-php5 的触发器... * Reloading web serv ...
- 【Java 基础】java 创建对象时重写方法
TransactionLock mockLock = new TransactionLock() { public boolean lock(String id) { return true; } p ...
- SSM框架整合后使用pagehelper实现分页功能
一.导入pagehelper-5.1.10.jar和jsqlparser-3.1.jar两个jar包 二.配置pagehelper 2.1 在mybatis配置文件中配置 <plugins> ...
- 阿里巴巴Java开发手册摘要(一)
一命名风格 1.代码中的命名均不能以下划线或美元符号开始,也不能以下划线或美元符号结尾. 反例:_name / $name / name_ / name$ 2.类名使用UpperCamelCase风格 ...
- 【C/C++】例题5-4 反片语/算法竞赛入门经典/C++与STL入门/映射:map
本题是映射:map的例题. map:键值对. [题目] 输入一些单词,找出所有满足如下条件的单词:该单词不能通过字母重排,得到输入文本中的另外一个单词. 在判断是否满足条件时,字母不分大小写,但在输出 ...
- idea 无法创建子目录
idea 无法创建子目录 解决方案