由于每个点的状态包含走过来的距离,所以要存二维的状态,但是状态总量太多,所以可以用哈希来搞。

那么就是bfs最短路,哈希记录状态了。

#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
const int maxn=5e3+9;
int n,m;
int a[maxn];
struct
{
struct
{
int next,to;
}e[maxn*10];
int head[maxn],lon;
void clear()
{
memset(head,-1,sizeof(head));
lon=-1;
}
void add(int from,int to)
{
e[++lon].to=to;
e[lon].next=head[from];
head[from]=lon;
}
}edge; struct
{
int head[111111],lon;
struct
{
int t,dist,next,sum;
}data[1111111];
void clear()
{
memset(head,-1,sizeof(head));
lon=-1;
}
bool push(int t,int dist,int sum)
{
int key=(t+abs(dist)%360*n)%111111;
for(int k=head[key];k!=-1;k=data[k].next)
{
if(t==data[k].t&&dist==data[k].dist)
return false;
}
data[++lon].t=t;
data[lon].dist=dist;
data[lon].next=head[key];
data[lon].sum=sum;
head[key]=lon;
return true;
}
}hash; struct
{
int t,dist,sum;
}que[1111111];
int bfs()
{
hash.clear();
int front=1,end=0;
que[++end].t=1;
que[end].sum=que[end].dist=0;
hash.push(1,0,0); while(front<=end)
{
int t=que[front].t;
int dist=que[front].dist;
int sum=que[front++].sum;
for(int k=edge.head[t];k!=-1;k=edge.e[k].next)
{
int u=edge.e[k].to;
int c=(a[u]+360-a[t])%360;
int uc=(a[t]+360-a[u])%360;
int tmp;
if(c<uc) tmp=c;
else tmp=-uc;
if(u==1&&dist+tmp!=0) return sum+1;
if(hash.push(u,dist+tmp,sum+1))
{
que[++end].t=u;
que[end].dist=dist+tmp;
que[end].sum=sum+1;
}
}
}
return -1;
} int main()
{
// freopen("in.txt","r",stdin);
while(scanf("%d %d",&n,&m)!=EOF)
{
edge.clear();
for(int i=1;i<=n;i++)
scanf("%d",&a[i]);
for(int i=1,from,to;i<=m;i++)
{
scanf("%d %d",&from,&to);
edge.add(from,to);
edge.add(to,from);
}
cout<<bfs()<<endl;
}
return 0;
}
#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
const int maxn=5e3+9;
int n,m;
int a[maxn];
struct
{
struct
{
int next,to;
}e[maxn*10];
int head[maxn],lon;
void clear()
{
memset(head,-1,sizeof(head));
lon=-1;
}
void add(int from,int to)
{
e[++lon].to=to;
e[lon].next=head[from];
head[from]=lon;
}
}edge; struct
{
int head[111111],lon;
struct
{
int t,dist,next,sum;
}data[1111111];
void clear()
{
memset(head,-1,sizeof(head));
lon=-1;
}
bool push(int t,int dist,int sum)
{
int key=(t+abs(dist)%360*n)%111111;
for(int k=head[key];k!=-1;k=data[k].next)
{
if(t==data[k].t&&dist==data[k].dist)
return false;
}
data[++lon].t=t;
data[lon].dist=dist;
data[lon].next=head[key];
data[lon].sum=sum;
head[key]=lon;
return true;
}
}hash; struct
{
int t,dist,sum;
}que[1111111];
int bfs()
{
hash.clear();
int front=1,end=0;
que[++end].t=1;
que[end].sum=que[end].dist=0;
hash.push(1,0,0); while(front<=end)
{
int t=que[front].t;
int dist=que[front].dist;
int sum=que[front++].sum;
for(int k=edge.head[t];k!=-1;k=edge.e[k].next)
{
int u=edge.e[k].to;
int c=(a[u]+360-a[t])%360;
int uc=(a[t]+360-a[u])%360;
int tmp;
if(c<uc) tmp=c;
else tmp=-uc;
if(u==1&&dist+tmp!=0) return sum+1;
if(hash.push(u,dist+tmp,sum+1))
{
que[++end].t=u;
que[end].dist=dist+tmp;
que[end].sum=sum+1;
}
}
}
return -1;
} int main()
{
// freopen("in.txt","r",stdin);
while(scanf("%d %d",&n,&m)!=EOF)
{
edge.clear();
for(int i=1;i<=n;i++)
scanf("%d",&a[i]);
for(int i=1,from,to;i<=m;i++)
{
scanf("%d %d",&from,&to);
edge.add(from,to);
edge.add(to,from);
}
cout<<bfs()<<endl;
}
return 0;
}
#include
#include <iostream>
#include <cstdio>
#include <cstring>
using namespace std;
const int maxn=5e3+9;
int n,m;
int a[maxn];
struct
{
struct
{
int next,to;
}e[maxn*10];
int head[maxn],lon;
void clear()
{
memset(head,-1,sizeof(head));
lon=-1;
}
void add(int from,int to)
{
e[++lon].to=to;
e[lon].next=head[from];
head[from]=lon;
}
}edge; struct
{
int head[111111],lon;
struct
{
int t,dist,next,sum;
}data[1111111];
void clear()
{
memset(head,-1,sizeof(head));
lon=-1;
}
bool push(int t,int dist,int sum)
{
int key=(t+abs(dist)%360*n)%111111;
for(int k=head[key];k!=-1;k=data[k].next)
{
if(t==data[k].t&&dist==data[k].dist)
return false;
}
data[++lon].t=t;
data[lon].dist=dist;
data[lon].next=head[key];
data[lon].sum=sum;
head[key]=lon;
return true;
}
}hash; struct
{
int t,dist,sum;
}que[1111111];
int bfs()
{
hash.clear();
int front=1,end=0;
que[++end].t=1;
que[end].sum=que[end].dist=0;
hash.push(1,0,0); while(front<=end)
{
int t=que[front].t;
int dist=que[front].dist;
int sum=que[front++].sum;
for(int k=edge.head[t];k!=-1;k=edge.e[k].next)
{
int u=edge.e[k].to;
int c=(a[u]+360-a[t])%360;
int uc=(a[t]+360-a[u])%360;
int tmp;
if(c<uc) tmp=c;
else tmp=-uc;
if(u==1&&dist+tmp!=0) return sum+1;
if(hash.push(u,dist+tmp,sum+1))
{
que[++end].t=u;
que[end].dist=dist+tmp;
que[end].sum=sum+1;
}
}
}
return -1;
} int main()
{
// freopen("in.txt","r",stdin);
while(scanf("%d %d",&n,&m)!=EOF)
{
edge.clear();
for(int i=1;i<=n;i++)
scanf("%d",&a[i]);
for(int i=1,from,to;i<=m;i++)
{
scanf("%d %d",&from,&to);
edge.add(from,to);
edge.add(to,from);
}
cout<<bfs()<<endl;
}
return 0;
}
<iostream>#include <cstdio>#include <cstring>using namespace std;const int maxn=5e3+9;int n,m;int a[maxn];struct{    struct    {        int next,to;    }e[maxn*10];    int head[maxn],lon;    void clear()    {        memset(head,-1,sizeof(head));        lon=-1;    }    void add(int from,int to)    {        e[++lon].to=to;        e[lon].next=head[from];        head[from]=lon;    }}edge;struct{    int head[1111111],lon;    struct    {        int t,dist,next,sum;    }data[1111111];    void clear()    {        memset(head,-1,sizeof(head));        lon=-1;    }    bool push(int t,int dist,int sum)    {        int key=t+abs(dist)%360*n;        for(int k=head[key];k!=-1;k=data[k].next)        {            if(t==data[k].t&&dist==data[k].dist)            return false;        }        data[++lon].t=t;        data[lon].dist=dist;        data[lon].next=head[key];        data[lon].sum=sum;        head[key]=lon;        return true;    }}hash;struct{    int t,dist,sum;}que[1111111];int bfs(){    hash.clear();    int front=1,end=0;    que[++end].t=1;    que[end].sum=que[end].dist=0;    hash.push(1,0,0);    while(front<=end)    {        int t=que[front].t;        int dist=que[front].dist;        int sum=que[front++].sum;        for(int k=edge.head[t];k!=-1;k=edge.e[k].next)        {            int u=edge.e[k].to;            int c=(a[u]+360-a[t])%360;            int uc=(a[t]+360-a[u])%360;            int tmp;            if(c<uc) tmp=c;            else tmp=-uc;            if(u==1&&dist+tmp!=0) return sum+1;            if(hash.push(u,dist+tmp,sum+1))            {                que[++end].t=u;                que[end].dist=dist+tmp;                que[end].sum=sum+1;            }        }    }    return -1;}int main(){//    freopen("in.txt","r",stdin);    while(scanf("%d %d",&n,&m)!=EOF)    {        edge.clear();        for(int i=1;i<=n;i++)        scanf("%d",&a[i]);        for(int i=1,from,to;i<=m;i++)        {            scanf("%d %d",&from,&to);            edge.add(from,to);            edge.add(to,from);        }        cout<<bfs()<<endl;    }    return 0;}

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