Code Signal_练习题_evenDigitsOnly
Check if all digits of the given integer are even.
Example
- For
n = 248622, the output should beevenDigitsOnly(n) = true; - For
n = 642386, the output should beevenDigitsOnly(n) = false.
我的解答:
def evenDigitsOnly(n):
for i in range(len(str(n))):
if int(str(n)[i]) % 2 != 0:
return False
return True
def evenDigitsOnly(n):
return all([int(i)%2==0 for i in str(n)]) 想起来用列表推导式了...但没想起来all函数....
膜拜大佬
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