The Hardest Problem Ever

链接:http://acm.hdu.edu.cn/showproblem.php?pid=1048

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 31307    Accepted Submission(s):
14491

Problem Description
Julius Caesar lived in a time of danger and intrigue.
The hardest situation Caesar ever faced was keeping himself alive. In order for
him to survive, he decided to create one of the first ciphers. This cipher was
so incredibly sound, that no one could figure it out without knowing how it
worked.
You are a sub captain of Caesar's army. It is your job to decipher
the messages sent by Caesar and provide to your general. The code is simple. For
each letter in a plaintext message, you shift it five places to the right to
create the secure message (i.e., if the letter is 'A', the cipher text would be
'F'). Since you are creating plain text out of Caesar's messages, you will do
the opposite:

Cipher text
A B C D E F G H I J K L M N O P Q R S T U V
W X Y Z

Plain text
V W X Y Z A B C D E F G H I J K L M N O P Q R S T U

Only letters are shifted in this cipher. Any non-alphabetical character
should remain the same, and all alphabetical characters will be upper
case.

 
Input
Input to this problem will consist of a (non-empty)
series of up to 100 data sets. Each data set will be formatted according to the
following description, and there will be no blank lines separating data sets.
All characters will be uppercase.

A single data set has 3 components:

Start line - A single line, "START"

Cipher message - A single
line containing from one to two hundred characters, inclusive, comprising a
single message from Caesar

End line - A single line, "END"

Following the final data set will be a single line,
"ENDOFINPUT".

 
Output
For each data set, there will be exactly one line of
output. This is the original message by Caesar.
 
Sample Input
START
NS BFW, JAJSYX TK NRUTWYFSHJ FWJ YMJ WJXZQY TK YWNANFQ HFZXJX
END
START
N BTZQI WFYMJW GJ KNWXY NS F QNYYQJ NGJWNFS ANQQFLJ YMFS XJHTSI NS WTRJ
END
START
IFSLJW PSTBX KZQQ BJQQ YMFY HFJXFW NX RTWJ IFSLJWTZX YMFS MJ
END
ENDOFINPUT
 
Sample Output
IN WAR, EVENTS OF IMPORTANCE ARE THE RESULT OF TRIVIAL CAUSES
I WOULD RATHER BE FIRST IN A LITTLE IBERIAN VILLAGE THAN SECOND IN ROME
DANGER KNOWS FULL WELL THAT CAESAR IS MORE DANGEROUS THAN HE
 
Source
 
可以用JAVA进行枚举。
import java.util.Scanner;

public class Main {
public static void main(String[] args) {
@SuppressWarnings("resource")
Scanner inScanner = new Scanner(System.in);
while(inScanner.hasNext()) {
String string = inScanner.nextLine();
if(string.equals("ENDOFINPUT")) {
break;
}
else if(string.equals("START") || string.equals("END")) {
continue;
}
else {
for(int i = ;i<string.length();i++) {
if(string.charAt(i)>='A' && string.charAt(i)<='E') {
System.out.printf("%c",string.charAt(i)+-);
}
else if(string.charAt(i)>='F'&&string.charAt(i)<='Z'){
System.out.printf("%c", string.charAt(i)-);
}
else {
System.out.printf("%c",string.charAt(i));
}
}
}
System.out.println();
}
}
}

(字符串 枚举)The Hardest Problem Ever hdu1048的更多相关文章

  1. The Hardest Problem Ever(字符串)

    The Hardest Problem Ever Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 24039   Accept ...

  2. HDUOJ-------The Hardest Problem Ever

    The Hardest Problem Ever Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java ...

  3. hdu_1048_The Hardest Problem Ever_201311052052

    The Hardest Problem Ever Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java ...

  4. HDU1048The Hardest Problem Ever

    The Hardest Problem Ever Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & ...

  5. POJ 1298 The Hardest Problem Ever【字符串】

    Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever faced was ke ...

  6. Poj1298_The Hardest Problem Ever(水题)

    一.Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar eve ...

  7. poj1298 The Hardest Problem Ever 简单题

    链接:http://poj.org/problem?id=1298&lang=default&change=true 简单的入门题目也有这么强悍的技巧啊!! 书上面的代码: 很厉害有没 ...

  8. HDOJ 1048 The Hardest Problem Ever(加密解密类)

    Problem Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caes ...

  9. C - The Hardest Problem Ever

    Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever ...

随机推荐

  1. Spring Boot 构建电商基础秒杀项目 (十) 交易下单

    SpringBoot构建电商基础秒杀项目 学习笔记 新建表 create table if not exists order_info ( id varchar(32) not null defaul ...

  2. Windows Server 2012 Hyper-V 快照

    快照 Hyper-V 可提供擷取執行中虛擬機器快照的能力,因此可輕易地回復至前一狀態,對於測試環境相當有幫助. 快照的功用雖然很不錯,不過每次建立快照時都是會消耗相當的硬碟資源,尤其目前的快照點和上一 ...

  3. 使用脚本调用maven命令后脚本直接退出问题

    在带有maven命令的bat脚本执行的时候,执行完一个mvn 目标后会自动退出,pause命令也无效. 原因:mvn本身是一个bat命令,因此在exit退出的时候,整个脚本进程将退出,加入call命令 ...

  4. POJ 3349-Snowflake Snow Snowflakes-字符串哈希

    哈希后,对每片雪花对比6次. #include <cstdio> #include <cstring> #include <vector> #include < ...

  5. centos安装php7.2环境

    centos安装php7.2环境 安装apache服务 yum -y install httpd 首先获取rpm: rpm -Uvh https://dl.fedoraproject.org/pub/ ...

  6. BZOJ 1497 最大获利

    最大权闭合子图 对于这个题,可以抽象成一个图论模型,如果我们把用户与其要求建立的中转站连边,获得的利益看成正权值,付出的代价看成负权值,我们可以发现,选取一个用户的时候,就相当于选取了一个闭合子图. ...

  7. sublime3添加verilog自动补全代码段

    前言 sublime默认的verilog自动补全十分垃圾,不过提供了代码段这个功能,你可以自己写个重用率高的代码段减轻工作量.写个模板当tb也很爽啦. 流程 1.打开user文件夹,创建verilog ...

  8. mysql中存储字段类型的查询效率

    检索性能从快到慢的是(此处是听人说的): 第一:tinyint,smallint,mediumint,int,bigint第二:char,varchar第三:NULL 解释(转载): 整数类型1.TI ...

  9. linux中监控CPU、内存和磁盘状态的shell脚本。(centos7)

    这篇博客中所写的脚本,在实际工作中并没有什么卵用,工作中并不会用到这种脚本去监控.不过自己写一遍,可以让初学者对CPU.内存.磁盘等一些基础知识和基础命令更加了解. 1.利用vmstat工具监控CPU ...

  10. 洛谷 P1129 [ZJOI2007]矩阵游戏 解题报告

    P1129 [ZJOI2007]矩阵游戏 题目描述 小\(Q\)是一个非常聪明的孩子,除了国际象棋,他还很喜欢玩一个电脑益智游戏――矩阵游戏.矩阵游戏在一个\(N*N\)黑白方阵进行(如同国际象棋一般 ...