The Hardest Problem Ever

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 13590    Accepted Submission(s): 6212

Problem Description
Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever faced was keeping himself alive. In order for him to survive, he decided to create one of the first ciphers. This cipher was so incredibly sound, that no one could figure it out without knowing how it worked. You are a sub captain of Caesar's army. It is your job to decipher the messages sent by Caesar and provide to your general. The code is simple. For each letter in a plaintext message, you shift it five places to the right to create the secure message (i.e., if the letter is 'A', the cipher text would be 'F'). Since you are creating plain text out of Caesar's messages, you will do the opposite:
Cipher text A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Plain text V W X Y Z A B C D E F G H I J K L M N O P Q R S T U
Only letters are shifted in this cipher. Any non-alphabetical character should remain the same, and all alphabetical characters will be upper case.
 
Input
Input to this problem will consist of a (non-empty) series of up to 100 data sets. Each data set will be formatted according to the following description, and there will be no blank lines separating data sets. All characters will be uppercase.
A single data set has 3 components:
Start line - A single line, "START"
Cipher message - A single line containing from one to two hundred characters, inclusive, comprising a single message from Caesar
End line - A single line, "END"
Following the final data set will be a single line, "ENDOFINPUT".
 
Output
For each data set, there will be exactly one line of output. This is the original message by Caesar.
 
Sample Input
START
NS BFW, JAJSYX TK NRUTWYFSHJ FWJ YMJ WJXZQY TK YWNANFQ HFZXJX
END
START
N BTZQI WFYMJW GJ KNWXY NS F QNYYQJ NGJWNFS ANQQFLJ YMFS XJHTSI NS WTRJ
END
START
IFSLJW PSTBX KZQQ BJQQ YMFY HFJXFW NX RTWJ IFSLJWTZX YMFS MJ
END
ENDOFINPUT
 
Sample Output
IN WAR, EVENTS OF IMPORTANCE ARE THE RESULT OF TRIVIAL CAUSES
I WOULD RATHER BE FIRST IN A LITTLE IBERIAN VILLAGE THAN SECOND IN ROME
DANGER KNOWS FULL WELL THAT CAESAR IS MORE DANGEROUS THAN HE
 
Source
 
 
 #include <stdio.h>
#include <string.h> int main()
{
char str1[],str2[],str3[];
while(scanf("%s",str1),str1[]!='E')
{
int i,len;
memset(str2,,sizeof(str2));
getchar();
gets(str2);
scanf("%s",str3);
//puts(str2);
len=strlen(str2);
for(i=;i<len;i++)
{
if(str2[i]>='F'&&str2[i]<='Z')
str2[i]-=;
else if(str2[i]>='A'&&str2[i]<='E')
str2[i]+=;
}
printf("%s\n",str2);
}
return ;
}

简单字符串处理题

 

hdu_1048_The Hardest Problem Ever_201311052052的更多相关文章

  1. HDU1048The Hardest Problem Ever

    The Hardest Problem Ever Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & ...

  2. The Hardest Problem Ever(字符串)

    The Hardest Problem Ever Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 24039   Accept ...

  3. (字符串 枚举)The Hardest Problem Ever hdu1048

    The Hardest Problem Ever 链接:http://acm.hdu.edu.cn/showproblem.php?pid=1048 Time Limit: 2000/1000 MS ...

  4. HDUOJ-------The Hardest Problem Ever

    The Hardest Problem Ever Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java ...

  5. HDOJ 1048 The Hardest Problem Ever(加密解密类)

    Problem Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caes ...

  6. C - The Hardest Problem Ever

    Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever ...

  7. POJ 1298 The Hardest Problem Ever【字符串】

    Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever faced was ke ...

  8. Poj1298_The Hardest Problem Ever(水题)

    一.Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar eve ...

  9. poj1298 The Hardest Problem Ever 简单题

    链接:http://poj.org/problem?id=1298&lang=default&change=true 简单的入门题目也有这么强悍的技巧啊!! 书上面的代码: 很厉害有没 ...

随机推荐

  1. hadoop-Combiner作用用法

    文章来源http://blog.csdn.net/ipolaris/article/details/8723782 reduce的输入每个key所对应的value将是一大串1,但处理的文本很多时,这一 ...

  2. PCB OD工具破解实例应用

    以下破解Genesis为例,对OD工具使用进行实例讲解 工具简单 介绍下下载地址: OD工具:是一个新的动态追踪工具,将IDA与SoftICE结合起来的思想,Ring 3级调试器, 是为当今最为流行的 ...

  3. E20170930-hm

    parse   vt. 从语法上描述或分析(词句等);

  4. Dsp和ARM的区别

    有一次上课老师在将ARM的时候说到了Dsp. Dsp(Digital Signal Process),数字信号处理技术,而Dsp芯片和ARM的结构也有很多相似之处.比如有流水线.采用哈佛结构(早期的A ...

  5. hastable 用法

    一,哈希表(Hashtable)简述 在.NET Framework中,Hashtable是System.Collections命名空间提供的一个容器,用于处理和表现类似keyvalue的键值对,其中 ...

  6. [转]android-学习笔记之按钮事件

    本文转载自: http://zhangkun716717-126-com.iteye.com/blog/761080 前备知识: 1.需要了解怎么得到界面元素. 那么如何得到界面元素呢?在界面配置文件 ...

  7. [转]如何借助 TLS/SSL 确保套接字连接的安全(使用 C#/VB/C++ 和 XAML 的 Windows 应用商店应用)

    本文转自:http://msdn.microsoft.com/zh-cn/library/windows/apps/jj150597.aspx 本主题将展示在使用 StreamSocket 功能时,如 ...

  8. Js控制样式的诸多方法

    function TableCss(options){ //如果没参数,就退出 if(arguments.length < 1 || !document.getElementById(optio ...

  9. Spring Boot (25) RabbitMQ消息队列

    MQ全程(Message Queue)又名消息队列,是一种异步通讯的中间件.可以理解为邮局,发送者将消息投递到邮局,然后邮局帮我们发送给具体的接收者,具体发送过程和时间与我们无关,常见的MQ又kafk ...

  10. JVM 内存区域划分

    一.运行时数据区包括哪几部分? 根据<Java虚拟机规范>的规定,运行时数据区通常包括这几个部分:程序计数器(Program Counter Register).Java栈(VM Stac ...