hdu_1048_The Hardest Problem Ever_201311052052
The Hardest Problem Ever
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 13590 Accepted Submission(s): 6212
Cipher text A B C D E F G H I J K L M N O P Q R S T U V W X Y Z
Plain text V W X Y Z A B C D E F G H I J K L M N O P Q R S T U
Only letters are shifted in this cipher. Any non-alphabetical character should remain the same, and all alphabetical characters will be upper case.
A single data set has 3 components:
Start line - A single line, "START"
Cipher message - A single line containing from one to two hundred characters, inclusive, comprising a single message from Caesar
End line - A single line, "END"
Following the final data set will be a single line, "ENDOFINPUT".
#include <stdio.h>
#include <string.h> int main()
{
char str1[],str2[],str3[];
while(scanf("%s",str1),str1[]!='E')
{
int i,len;
memset(str2,,sizeof(str2));
getchar();
gets(str2);
scanf("%s",str3);
//puts(str2);
len=strlen(str2);
for(i=;i<len;i++)
{
if(str2[i]>='F'&&str2[i]<='Z')
str2[i]-=;
else if(str2[i]>='A'&&str2[i]<='E')
str2[i]+=;
}
printf("%s\n",str2);
}
return ;
}
简单字符串处理题
hdu_1048_The Hardest Problem Ever_201311052052的更多相关文章
- HDU1048The Hardest Problem Ever
The Hardest Problem Ever Time Limit:1000MS Memory Limit:32768KB 64bit IO Format:%I64d & ...
- The Hardest Problem Ever(字符串)
The Hardest Problem Ever Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 24039 Accept ...
- (字符串 枚举)The Hardest Problem Ever hdu1048
The Hardest Problem Ever 链接:http://acm.hdu.edu.cn/showproblem.php?pid=1048 Time Limit: 2000/1000 MS ...
- HDUOJ-------The Hardest Problem Ever
The Hardest Problem Ever Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java ...
- HDOJ 1048 The Hardest Problem Ever(加密解密类)
Problem Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caes ...
- C - The Hardest Problem Ever
Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever ...
- POJ 1298 The Hardest Problem Ever【字符串】
Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar ever faced was ke ...
- Poj1298_The Hardest Problem Ever(水题)
一.Description Julius Caesar lived in a time of danger and intrigue. The hardest situation Caesar eve ...
- poj1298 The Hardest Problem Ever 简单题
链接:http://poj.org/problem?id=1298&lang=default&change=true 简单的入门题目也有这么强悍的技巧啊!! 书上面的代码: 很厉害有没 ...
随机推荐
- redhat6 改 centos yum 源
**redhat的yum在线更新是收费的,如果没有注册的话不能使用,如果要使用,需将redhat的yum卸载后,重启安装其他yum源,再配置其他源.** 本文包括配置本地源及第三方源.第三方源包括:网 ...
- Linux必知必会的目录结构
1.目录结构 /bin 二进制文件 命令 /sbin 超级命令 只有root用户可以使用 /boot 系统的引导文件 系统内核 /dev 设备文件 光盘 硬盘分区 /etc 系统配置文件 /home ...
- Unity 代码改宏定义
两个函数 PlayerSettings.GetScriptingDefineSymbolsForGroup(targetGroup); //所有宏定义 ; 分割 PlayerSettings.SetS ...
- [Apple开发者帐户帮助]七、注册设备(2)注册多个设备
如果您有许多测试设备,则可以创建包含设备名称和设备ID的文件,并将整个文件上载到开发人员帐户.您的开发人员帐户支持以下两种文件格式:具有.deviceids文件扩展名和纯文本文件的属性列表文件.您选择 ...
- Win7 + VS2015 + Python3.6编译
0. 下载安装hg. http://bitbucket.org/tortoisehg/files/downloads/tortoisehg-4.0.1-x64.msi 1. 下载Python3.6源代 ...
- JAVA小记(一)
java中向上转型.向下转型.内部类中所需注意的问题: 向上转型与向下转型: 举个例子:有2个类,Father是父类,Son类继承自Father. Father f1 = new Son(); / ...
- [ 51Nod 1327 ] 棋盘游戏
\(\\\) \(Description\) 给出一张\(N\times M\)的棋盘,每个格子最多放置一个棋子,一个合法的放置方案需满足: 每列至多放置一个棋子 对于第\(i\)行,前\(L_i\) ...
- 前端h5开发调试神奇vconsole
(1)项目中安装vconcole插件 npm install vconcole (2)在vue项目中main.js中引入插件 import Vconsole from 'vconsole'; cons ...
- jQuery——this
js注册事件this代表的dom对象 jQuery注册事件this代表的也是dom对象,所以需要$(this)转成jQuery对象
- C# 执行sql语句批量更新
int x = db.Database.ExecuteSqlCommand(string.Format("update T_Pension SET UnitType = '{0}' WHER ...