因为会溢出,因此判断条件需要转化。变成b>c-a

#include<cstdio>
#include<cstring>
#include<cmath>
#include<vector>
#include<queue>
#include<algorithm>
using namespace std; long long a,b,c; int main()
{
int T; scanf("%d",&T);
int Case=;
while(T--)
{
scanf("%lld%lld%lld",&a,&b,&c);
printf("Case #%d: ",Case++);
if(b>c-a) printf("true\n");
else printf("false\n");
}
return ;
}

PAT (Advanced Level) 1065. A+B and C (64bit) (20)的更多相关文章

  1. PAT (Advanced Level) Practice 1031 Hello World for U (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1031 Hello World for U (20 分) 凌宸1642 题目描述: Given any string of N (≥5) ...

  2. PAT (Advanced Level) Practice 1023 Have Fun with Numbers (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1023 Have Fun with Numbers (20 分) 凌宸1642 题目描述: Notice that the number ...

  3. PAT (Advanced Level) 1069. The Black Hole of Numbers (20)

    简单题. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #in ...

  4. PAT (Advanced Level) Practice 1001 A+B Format (20 分)

    题目链接:https://pintia.cn/problem-sets/994805342720868352/problems/994805528788582400 Calculate a+b and ...

  5. PAT (Advanced Level) Practice 1001 A+B Format 分数 20

    Calculate a+b and output the sum in standard format -- that is, the digits must be separated into gr ...

  6. 【PAT甲级】1065 A+B and C (64bit) (20 分)(大数溢出)

    题意: 输入三个整数A,B,C(long long范围内),输出是否A+B>C. trick: 测试点2包括溢出的数据,判断一下是否溢出即可. AAAAAccepted code: #defin ...

  7. PAT (Advanced Level) Practice(更新中)

    Source: PAT (Advanced Level) Practice Reference: [1]胡凡,曾磊.算法笔记[M].机械工业出版社.2016.7 Outline: 基础数据结构: 线性 ...

  8. PAT (Advanced Level) Practice 1001-1005

    PAT (Advanced Level) Practice 1001-1005 PAT 计算机程序设计能力考试 甲级 练习题 题库:PTA拼题A官网 背景 这是浙大背景的一个计算机考试 刷刷题练练手 ...

  9. PAT (Advanced Level) Practice 1046 Shortest Distance (20 分) 凌宸1642

    PAT (Advanced Level) Practice 1046 Shortest Distance (20 分) 凌宸1642 题目描述: The task is really simple: ...

随机推荐

  1. 如何更改mysql可执行路径及更改mysql数据库文件路径

    一.如何更改服务中MySQL的可执行文件路径: 解决方法:到注册表里HKEY_LOCAL_MECHINE---SYSTEM ---CurrentControlSet 更改查找一. MySQL项值,然后 ...

  2. 二分图匹配之KM求二分图最佳匹配算法

    参考网址:http://blog.163.com/suntroop@yeah/blog/static/17012103120115185927194/ 对于具有二部划分( V1, V2 )的加权完全二 ...

  3. 第4章 流程控制----编写Java程序,使用while循环语句计算1+1/2!+1/3!+...+1/20!之和

    package four; public class fouronetwo { public static void main(String args[]){ double sum = 0,a = 1 ...

  4. android,view的执行过程onDraw、onSizeChanged,onFinishInflate

    小试view的执行过程,此是入门,高手绕道. ----------------------------------------------------------------------------- ...

  5. 注意题目条件!!! 团问题 HDU 5952

    题目大意:团的定义就是,团内的所有点,两两之间各有一条边,团的大小就是点的个数.现给你一个n个点,m条边的图.问,该图中有多少点的个数为s的团. (题目保证每个点的度数不超过20,n<=100, ...

  6. $scope

    $scope.aaa = 3; $scope.bbb = 4; $scope.aaa = $scope.bbb; //这只是简单的赋值 $scope.bbb = 5; 输出 $scope.aaa为4 ...

  7. lepus bug

    ------------------------------------------------BUG fix-------------------------------------------- ...

  8. asp发邮件控件

    <% Set jmail = Server.CreateObject("JMAIL.SMTPMail") ’创建一个JMAIL对象 jmail.silent = true ’ ...

  9. eclipse配置tomcat及修改tomcat默认根目录

    1.安装eclipse for j2ee和tomcat: 2.下载tomcat对eclipse的插件:http://www.eclipsetotale.com/tomcatPlugin.html 下载 ...

  10. wpf中ListBox的选中项与ComboBox间的绑定

    产品类: public class Product:NotificationObject { private int productID; public int ProductID { get { r ...