ural1701 Ostap and Partners
Ostap and Partners
Memory limit: 64 MB
“Looking for a job,” Ivan answered wearily.
“You know, I was also looking for a job not so long ago, and I found an excellent one!” Vassily was excited. “It's nearby and they promised to pay well! And you can join us too!”
“What's that job like?” no wonder, jobless Ivan became interested.
“Have you heard about the company Ostap and Partners? They've been producing horns and hoofs for a number of years already. And now I'm a hoof picker of the third class with them!” answered Vassily proudly.
“How much do they pay you?” Ivan wanted to know.
“They don't pay me yet,” answered his friend with disappointment. “It's the first month I work there and I'm a probationer. And the guys in the brigade don't tell me their wages, it's the company's policy.” He paused and lowered his voice to a whisper. “But I know that our foreman drives a Mercedes!”
“Ah, I would like to know how much money they get,” Ivan said dreamily imagining himself driving a Merc.
“I can learn it after all!” Vassily had a sudden inspiration. “The guys like to brag at smoking breaks that their wages are greater than someone else's. For example, Stepan said recently that he was getting 1200 rubles more than Fyodor. And Fyodor once complained that he was getting 5500 rubles less than the foreman.”
“Collect then as many such comparisons as you can, and we will know all the wages!” Ivan rejoiced.
“OK, I'll do that!”
Input
Output
Samples
| input | output |
|---|---|
5 6 |
Possible |
3 5 |
Impossible after 3 statements |
3 2 |
Impossible after 2 statements |
分析:并查集合并;
代码:
#include <iostream>
#include <cstdio>
#include <cstdlib>
#include <cmath>
#include <algorithm>
#include <climits>
#include <cstring>
#include <string>
#include <set>
#include <map>
#include <queue>
#include <stack>
#include <vector>
#include <list>
#define rep(i,m,n) for(i=m;i<=n;i++)
#define rsp(it,s) for(set<int>::iterator it=s.begin();it!=s.end();it++)
#define mod 1000000007
#define inf 0x3f3f3f3f
#define vi vector<int>
#define pb push_back
#define mp make_pair
#define fi first
#define se second
#define ll long long
#define pi acos(-1.0)
#define pii pair<int,int>
#define Lson L, mid, rt<<1
#define Rson mid+1, R, rt<<1|1
const int maxn=5e4+;
using namespace std;
ll gcd(ll p,ll q){return q==?p:gcd(q,p%q);}
ll qpow(ll p,ll q){ll f=;while(q){if(q&)f=f*p;p=p*p;q>>=;}return f;}
int n,m,k,t,p[maxn],flag;
ll a[maxn],b[maxn];
int find(int x)
{
if(x==p[x])return x;
else
{
int fa=p[x];
p[x]=find(p[x]);
a[x]+=a[fa];
}
return p[x];
}
int main()
{
int i,j;
scanf("%d%d",&n,&m);
rep(i,,n-)p[i]=i;
rep(i,,m)
{
int c,d,e;
scanf("%d%d%d",&c,&d,&e);
int fa=find(c),fb=find(d);
if(fa!=fb)
{
p[fa]=fb;
a[fa]=-a[c]+a[d]+e;
}
else
{
if(a[c]-a[d]!=e)return *printf("Impossible after %d statements\n",i);
}
}
int ca;
rep(i,,n-)
{
int fa=find(i);
if(i==)b[fa]=-a[i],ca=fa;
else if(fa==ca)continue;
else if(a[i]<)b[fa]=max(b[fa],-a[i]);
}
rep(i,,n-)
{
int fa=find(i);
if(a[i]+b[fa]<||a[i]+b[fa]>1e9)return *printf("Impossible after %d statements\n",m);
}
puts("Possible");
rep(i,,n-)printf("%lld\n",a[i]+b[find(i)]);
//system("Pause");
return ;
}
ural1701 Ostap and Partners的更多相关文章
- 1701. Ostap and Partners(并查集-关系)
1701 又是类似食物链的这一类题 这题是找与根节点的和差关系 因为0节点是已知的 为0 那么所有的都可以转换为与0的和差关系 可以规定合并的两节点 由大的指向小的 然后再更新和差关系 有可能最后有 ...
- Windows Phone 8 解锁提示IpOverUsbSvc问题——IpOverUsbEnum返回No connected partners found解决方案
我的1520之前总是无法解锁,提示:IpOverUsbSvc服务没有开启什么的. 根据网上网友的各种解决方案: 1. 把手机时间设置为当前时间,并且关闭“自动设置” 2. 确保手机接入了互联网 3.确 ...
- Codeforces Round #382 (Div. 2) A. Ostap and Grasshopper bfs
A. Ostap and Grasshopper 题面 On the way to Rio de Janeiro Ostap kills time playing with a grasshopper ...
- Codeforces Round #382 (Div. 2)E. Ostap and Tree
E. Ostap and Tree time limit per test 2 seconds memory limit per test 256 megabytes input standard i ...
- Codeforces735A Ostap and Grasshopper 2016-12-13 11:53 78人阅读 评论(0) 收藏
A. Ostap and Grasshopper time limit per test 2 seconds memory limit per test 256 megabytes input sta ...
- 一些SAP Partners能够通过二次开发实现打通C/4HANA和S/4HANA的方法介绍
有好几位朋友在公众号后台给我留言询问SAP C/4HANA和S/4HANA集成的方案. 尽管我给这些朋友推送了一个方案:打通C/4HANA和S/4HANA的一个原型开发:智能服务创新案例,然而我得到的 ...
- Codeforces 735 E Ostap and Tree
Discription Ostap already settled down in Rio de Janiero suburb and started to grow a tree in his ga ...
- 【64.22%】【codefoces round 382A】Ostap and Grasshopper
time limit per test2 seconds memory limit per test256 megabytes inputstandard input outputstandard o ...
- [Ccodeforces 736C] Ostap and Tree - 树形DP
给定一个n个点的树,把其中一些点涂成黑色,使得对于每个点,其最近的黑点的距离不超过K. 树形DP. 设置状态f[i][j]: 当j <= K时: 合法状态,表示i的子树中到根的最近黑点距离为j的 ...
随机推荐
- A. Mike and Cellphone(Round 361 Div.2)
写一半去开程序的时候不小心关了网页,LOFTER我都不奢望加入代码高亮,最起码我关闭的时候弹个对话框,再不济也给我定时保存一下草稿吧. A. Mike and Cellphone time limit ...
- html_web存储
HTML5存储 HTML5 web存储,一个比cookie更好的本地存储方式. 什么是HTML5 Web存储? 使用HTML5可以在本地存储用户的浏览数据. 早些时候,本地存储使用的是cookie.但 ...
- HDU 5811 Colosseo
首先判断一下两个集合是否能够拓扑排序,顺便记录下每个节点的拓扑序. 然后看T2中每个点在T1中能够放在哪一个位置,记录下这个位置Pi. 然后T2中(按拓扑序排好),计算Pi的一个非严格递增的LIS.L ...
- C语言_error_MSB8031
关于Visual Studio 2013 编译 multi-byte character set MFC程序出现 MSB8031 错误的解决办法 Visual Studio 2013 编译旧的 mul ...
- leetcode441(巧妙利用取整和解方程)
You have a total of n coins that you want to form in a staircase shape, where every k-th row must ha ...
- java se 另一博客
http://blog.csdn.net/terryzero/article/category/517680
- 让AutoMapper在你的项目里飞一会儿(转)
出处:http://www.cnblogs.com/WeiGe/p/3835523.html 先说说DTO DTO是个什么东东? DTO(Data Transfer Object)就是数据传输对象,说 ...
- servlet第2讲(下集)----通过HttpServlet实现一个用户登录网站(继承HttpServlet)
1.计划框架 2.先建立Login的servlet (1)建立Login,编写代码,进行编译 (2)配置web.xml (3)重新加载,并且验证 (4)解决乱码问题 (5)再次加载,然后验证 ...
- postfix防垃圾邮件
Postfix 2.x 打开/etc/postfix/main.cf文件,在其中增加如下的几行(如果相关的配置存在,就替换之): vi /etc/postfix/main.cf [...] smtpd ...
- linux sigaction信号处理
sigaction函数相比signal函数更为复杂,但更具灵活性,下面具体介绍她的结构和用法: #include <signal.h> int sigaction(int signum, ...