Before the invention of book-printing, it was very hard to make a copy of a book. All the contents had
to be re-written by hand by so called scribers. The scriber had been given a book and after several
months he finished its copy. One of the most famous scribers lived in the 15th century and his name
was Xaverius Endricus Remius Ontius Xendrianus (Xerox). Anyway, the work was very annoying and
boring. And the only way to speed it up was to hire more scribers.
Once upon a time, there was a theater ensemble that wanted to play famous Antique Tragedies. The
scripts of these plays were divided into many books and actors needed more copies of them, of course.
So they hired many scribers to make copies of these books. Imagine you have m books (numbered
1; 2; : : : ;m) that may have different number of pages (p1; p2; : : : ; pm) and you want to make one copy of
each of them. Your task is to divide these books among k scribes, k m. Each book can be assigned
to a single scriber only, and every scriber must get a continuous sequence of books. That means, there
exists an increasing succession of numbers 0 = b0 < b1 < b2; : : : < bk

【NOIP提高组2015D2T1】uva 714 copying books【二分答案】——yhx的更多相关文章

  1. UVa 714 Copying Books - 二分答案

    求使最大值最小,可以想到二分答案. 然后再根据题目意思乱搞一下,按要求输出斜杠(这道题觉得就这一个地方难). Code /** * UVa * Problem#12627 * Accepted * T ...

  2. UVA 714 Copying Books 二分

    题目链接: 题目 Copying Books Time limit: 3.000 seconds 问题描述 Before the invention of book-printing, it was ...

  3. uva 714 Copying Books(二分法求最大值最小化)

    题目连接:714 - Copying Books 题目大意:将一个个数为n的序列分割成m份,要求这m份中的每份中值(该份中的元素和)最大值最小, 输出切割方式,有多种情况输出使得越前面越小的情况. 解 ...

  4. UVa 714 Copying Books(二分)

    题目链接: 传送门 Copying Books Time Limit: 3000MS     Memory Limit: 32768 KB Description Before the inventi ...

  5. UVA 714 Copying Books 最大值最小化问题 (贪心 + 二分)

      Copying Books  Before the invention of book-printing, it was very hard to make a copy of a book. A ...

  6. UVa 714 Copying books 贪心+二分 最大值最小化

    题目大意: 要抄N本书,编号为1,2,3...N, 每本书有1<=x<=10000000页, 把这些书分配给K个抄写员,要求分配给某个抄写员的那些书的编号必须是连续的.每个抄写员的速度是相 ...

  7. uva 714 - Copying Books(贪心 最大值最小化 二分)

    题目描写叙述开头一大堆屁话,我还细致看了半天..事实上就最后2句管用.意思就是给出n本书然后要分成k份,每份总页数的最大值要最小.问你分配方案,假设最小值同样情况下有多种分配方案,输出前面份数小的,就 ...

  8. UVA 714 Copying Books

    题意: 要抄N本书,编号为1,2,3...N, 每本书有1<=x<=10000000页, 把这些书分配给K个抄写员,要求分配给某个抄写员的那些书的编号必须是连续的.每个抄写员的速度是相同的 ...

  9. UVA 714 Copying Books 抄书 (二分)

    题意:把一个包含m个正整数的序列划分成k个非空的连续子序列.使得所有连续子序列的序列和Si的最大值尽量小. 二分,每次判断一下当前的值是否满足条件,然后修改区间.注意初始区间的范围,L应该为所有正整数 ...

随机推荐

  1. 从零开始学习Linux (cd命令)

    上一篇博客中提到,我们学习命令大多都要参考 --help 这个选项.但是cd命令并没有这个选项. 我们可以通过 help cd 来查看cd的使用方式.其实cd命令挺简单的,它的作用是进入文件夹,也就是 ...

  2. 【Effective Java】3、避免创建不必要的对象

    创建对象的时候,有些变量可以一直保持的时候,可以不必要每次实例化对象的时候都把这些变量初始化一遍,可以使用静态和静态块的方式把这些变量的数据固定下来 package cn.xf.cp.ch02.ite ...

  3. 自定义View_1_关于View,ViewGroup的测量和绘制流程

    自定义View(1) ------ 关于View,ViewGroup的测量和绘制流程 在Android当中,自定义控件属于比较高级的知识体系,今天我们就一起研究研究关于自定义View的那点事,看看它到 ...

  4. netty Failed to submit an exceptionCaught() event异常

    最近测试netty开发的服务端应用在关闭时,出现下列异常: ->###WARN#########nioEventLoopGroup-3-2###io.netty.util.internal.lo ...

  5. django配置fcgi参数解释

    manage.py runfcgi minspare=50 maxspare=200 maxchildren=1000 maxrequests=99999 host=127.0.0.1 port=80 ...

  6. nodeJS中npm常见的命令

    常用的nodeJS中npm的命令:npm主要是node包管理和发布的工具.npm常用的命令:1:npm install <name> //(下载包) 下载后的包放在当前路径下面 npm i ...

  7. Iscroll应用文档

    Iscroll是一个非常不错的区域滑动插件. 不过它有个小小的不足,就是它的说明文档. 全英文不说,整理的也不咋好,官网上看着很乱,不容易查阅. 因此上网找了一些相关的文档说明并加以整理. Iscro ...

  8. 浅谈ES6中的Proxy

    Proxy是一个很有趣的对象,它能够修改某些操作的默认行为,等同于在语言层面做出修改,属于一种‘元编程’,即对编程语言进行编程. Proxy其实很好理解,就是在目标对象之前架设一层拦截,外界的访问都得 ...

  9. 高精度练习(hdoj1042)

    Problem Description Given an integer N(0 ≤ N ≤ 10000), your task is to calculate N!   Input One N in ...

  10. 弃用的异步get和post方法之Block方法

    #import "ViewController.h" #import "Header.h" @interface ViewController () <N ...