Gym100923H Por Costel and the Match
题目链接:http://codeforces.com/gym/100923/problem/H
分析:并查集,用enemy储存x的敌人,用weight储存权重决定根节点
需用scanf和puts输入输出否则会爆
1 #include<iostream>
2 #include<sstream>
3 #include<cstdio>
4 #include<cstdlib>
5 #include<string>
6 #include<cstring>
7 #include<algorithm>
8 #include<functional>
9 #include<iomanip>
10 #include<numeric>
11 #include<cmath>
12 #include<queue>
13 #include<vector>
14 #include<set>
15 #include<cctype>
16 #define PI acos(-1.0)
17 const int INF = 0x3f3f3f3f;
18 const int NINF = -INF - 1;
19 const int maxn = 1e5 + 5;
20 typedef long long ll;
21 using namespace std;
22 int n, m;
23 int fa[maxn], enemy[maxn], weight[maxn];
24 int find(int x)
25 {
26 return x == fa[x] ? x : fa[x] = find(fa[x]);
27 }
28 void unite(int x, int y)
29 {
30 if (weight[x] < weight[y]) fa[x] = y;
31 else
32 {
33 fa[y] = x;
34 if (weight[x] == weight[y]) weight[x]++;
35 }
36 }
37 int main()
38 {
39 //std::ios::sync_with_stdio(false);
40 freopen("meciul.in", "r", stdin);
41 freopen("meciul.out", "w", stdout);
42 int T;
43 scanf("%d", &T);
44 while (T--)
45 {
46 scanf("%d%d", &n, &m);
47 memset(enemy, 0, sizeof(enemy));
48 memset(weight, 0, sizeof(weight));
49 for (int i = 1; i <= n; ++i) fa[i] = i;
50 while (m--)
51 {
52 int x, y;
53 scanf("%d%d", &x, &y);
54 int f1 = find(x), f2 = find(y);
55 if (f1 == f2) puts("NO");
56 else
57 {
58 if (!enemy[x]) enemy[x] = y;
59 else unite(f2, find(enemy[x]));
60 if (!enemy[y]) enemy[y] = x;
61 else unite(f1, find(enemy[y]));
62 puts("YES");
63 }
64 }
65 }
66 return 0;
67 }
Gym100923H Por Costel and the Match的更多相关文章
- 【并查集】Gym - 100923H - Por Costel and the Match
meciul.in / meciul.out Oberyn Martell and Gregor Clegane are dueling in a trial by combat. The fight ...
- 【带权并查集】Gym - 100923H - Por Costel and the Match
裸题. 看之前的模版讲解吧,这里不再赘述了. #include<cstdio> #include<cstring> using namespace std; int fa[10 ...
- Gym-100923H-Por Costel and the Match(带权并查集)
链接: https://vjudge.net/problem/Gym-100923H 题意: Oberyn Martell and Gregor Clegane are dueling in a tr ...
- 【Heap-dijkstra】Gym - 100923B - Por Costel and the Algorithm
algoritm.in / algoritm.out Even though he isn't a student of computer science, Por Costel the pig ha ...
- 【找规律】Gym - 100923L - Por Costel and the Semipalindromes
semipal.in / semipal.out Por Costel the pig, our programmer in-training, has recently returned from ...
- 【分块打表】Gym - 100923K - Por Costel and the Firecracker
semipal.in / semipal.out Por Costel the pig, our programmer in-training, has recently returned from ...
- 【数形结合】Gym - 100923I - Por Costel and the Pairs
perechi3.in / perechi3.out We don't know how Por Costel the pig arrived at FMI's dance party. All we ...
- 【动态规划】Gym - 100923A - Por Costel and Azerah
azerah.in / azerah.out Por Costel the Pig has received a royal invitation to the palace of the Egg-E ...
- 【Gym - 100923A】Por Costel and Azerah(思维水题)
Por Costel and Azerah Descriptions 给你n个数 问你,有多少个子序列 的和是偶数 Example Input 233 10 124 2 Output 33 题目链接 ...
随机推荐
- Codeforces Round #594 (Div. 2) C. Ivan the Fool and the Probability Theory (思维,递推)
题意:给你一个\(n\)x\(m\)的矩阵,需要在这些矩阵中涂色,每个格子可以涂成黑色或者白色,一个格子四周最多只能有\(2\)个和它颜色相同的,问最多有多少种涂色方案. 题解:首先我们考虑一维的情况 ...
- Codeforces Round #550 (Div. 3) D. Equalize Them All (贪心,模拟)
题意:有一组数,可以选择某个数\(a_i\)相邻的一个数\(a_j\),然后可以让\(a_i\)加上或者减去\(|a_i-a_j|\),问最少操作多少次使得数组中所有数相同. 题解:不难发现,每次操作 ...
- 手动编译Selenium源码
起因 Selenium ChromeDriver和Chrome升级到最新v81版本,同时需要将Selenium3.3.1升级到3.141.59. Selenium本身不支持https,所以修改源码用于 ...
- 要想用活Redis,Lua脚本是绕不过去的坎
前言 Redis 当中提供了许多重要的高级特性,比如发布与订阅,Lua 脚本等.Redis 当中也提供了自增的原子命令,但是假如我们需要同时执行好几个命令的同时又想让这些命令保持原子性,该怎么办呢?这 ...
- Linux-压缩/解压缩命令
目录 Linux系统中常见的压缩包格式 gzip 压缩命令 zip 压缩命令 tar 压缩命令(归档) Linux系统中常见的压缩包格式 格式 压缩工具 .zip zip压缩工具 .gz gzip压缩 ...
- System.Windows.Forms.Help
在开发过程中,基本都需要实现帮助功能,而一般帮助功能就是打开一个帮助文档,System.Windows.Forms提供了Help类用于打开帮助文档,挺方便的. Help类提供的方法如下: Name ...
- ACM ICPC 2017 Warmup Contest 1 D
Daydreaming Stockbroker Gina Reed, the famous stockbroker, is having a slow day at work, and between ...
- C# 类 (5)
Static 静态成员 创建一个类,实例化它,然后使用实例的各种方法或者属性 然而有时候我们不想实例化这个类,难道我们就没法用他里面的成员了吗?比如计算矩形的面积,就是长*宽,万年不变 当然可以,用s ...
- Object Destructuring Assignment vs Object.assign
Object Destructuring Assignment vs Object.assign // const params = Object.assign({}, this.$route.par ...
- 互联网公司技术岗实习/求职经验(实习内推+简历+面试+offer篇)
找工作的事基本尘埃落定了,打算把这大半年来积累的经验写下来,基本都是我希望当年找实习的时候自己能够知道的东西,帮师弟师妹们消除一点信息不平等,攒攒RP~ 不要像我当年那样,接到电话吓成狗,没接到电话吓 ...