well-posed problem must have the property that

  1. A solution exists
  2. The solution is unique
  3. The solution's behavior changes continuously with the initial conditions

简单来说就是有唯一解,并且是连续变化的。

Examples of archetypal well-posed problems include the Dirichlet problem for Laplace's equation, and the heat equation with specified initial conditions.

Problems that are not well-posed in the sense of Hadamard are termed ill-posed. Inverse problems are often ill-posed.

If the problem is well-posed, then it stands a good chance of solution on a computer using a stable algorithm. If it is not well-posed, it needs to be re-formulated for numerical treatment

well-posed problem and ill-posed problem的更多相关文章

  1. Problem : 1002 ( A + B Problem II )

    经验总结:一定要注意输出的格式,字符的空格,空行,一定要观察清楚.如本题的最后一个输出结果后面没有空行.最后代码实现的时候需要判断一下,代码如下 !=n) cout<<endl; Prob ...

  2. 2013-2014 ACM-ICPC, NEERC, Southern Subregional Contest Problem B. Travelling Camera Problem set贪心

    Problem B. Travelling Camera Problem 题目连接: http://www.codeforces.com/gym/100253 Description Programm ...

  3. Problem B The Blocks Problem(vector的使用)

    题目链接:Problem B 题意:有n块木块,编号为0~n-1,要求模拟以下4种操作(下面的a和b都是木块编号) 1. move a onto b: 把a和b上方的木块全部归位,然后把a摞在b上面. ...

  4. 几何入门合集 gym101968 problem F. Mirror + gym102082 Problem F Fair Chocolate-Cutting + gym101915 problem B. Ali and Wi-Fi

    abstract: V const & a 加速 F. Mirror 题意 链接 问题: 有n个人在y=0的平面上(及xoz平面).z=0平面上有一面镜子(边平行于坐标轴).z=a平面上有q个 ...

  5. A+B Problem Plus and A-B Problem Plus and A*B Problem Plus

    //we have defined the necessary header files here for this problem. //If additional header files are ...

  6. Problem J. Joseph’s Problem 约瑟夫问题--余数之和

    链接:https://vjudge.net/problem/UVA-1363 题意:给出n  k,当 i 属于 1~n 时 ,求解 n% i 的和 n 和 k 的范围都是 1 到 10^9; 商相同 ...

  7. Holes in the text Add problem to Todo list Problem code: HOLES

    import sys def count_holes(letter): hole_2 = ['A', 'D', 'O', 'P', 'Q', 'R'] if letter == 'B': return ...

  8. The Lead Game Add problem to Todo list Problem code: TLG

    '''def count_lead(first, second): if first > second: return 1, first - second elif first == secon ...

  9. Turbo Sort Add problem to Todo list Problem code: TSORT

    def heap_sort(ary): n = len(ary) first = int(n / 2 - 1) for start in range(first, -1, -1): # 3~0 rev ...

  10. POJ - Problem 2282 - The Counting Problem

    整体思路:对于每一位,先将当前未达到$limit$部分的段 [如 $0$ ~ $10000$] 直接处理好,到下一位时再处理达到$limit$的部分. · $1 × 10 ^ n$以内每个数(包括$0 ...

随机推荐

  1. 浅析Quartz的集群配置

    浅析Quartz的集群配置(一) 收藏人:Rozdy     2015-01-13 | 阅:1  转:22    |   来源   |  分享               1 基本信息 摘要:Quar ...

  2. FastDFS_v5.05安装配置

    废话不多讲,启动FastDFS文件服务器的命令是 #/usr/bin/fdfs_trackerd /etc/fdfs/tracker.conf #/usr/bin/fdfs_storaged /etc ...

  3. MapReduce编程系列 — 6:多表关联

    1.项目名称: 2.程序代码: 版本一(详细版): package com.mtjoin; import java.io.IOException; import java.util.Iterator; ...

  4. 自定义View(1)简单流程及示例模板

    1,继承View , ViewGroup,或TextView等等 2,绘制相关的api, canvas 画布, paint 画笔 2,重写重要的函数(注意这个顺序) onMeasure 属于View的 ...

  5. Linux文件与进程的Capability简介

    UID这种权限机制颗粒太粗,容易引起权利过剩(溢出),Linux引入了Capability:每个Capability系统内以一位Bit代表,OS内部使用64bit存储. 下面是android的capa ...

  6. CY7C68013A的一点总结

    一. 值得参考的资料:FX2 TechRefManual.USB应用开发宝典. LabVIEW-USB通信简单教程(用于参考生成labview驱动程序).USB设备请求和描述符整理(仅用于理解描述符的 ...

  7. 宏HASH_GET_NEXT

    /*******************************************************************//** Gets the next struct in a h ...

  8. UVa 11529 (计数) Strange Tax Calculation

    枚举一个中心点,然后将其他点绕着这个点按照极角排序. 统计这个中心点在外面的三角形的个数,然后用C(n-1, 3)减去这个数就是包含这个点的三角形的数量. 然后再枚举一个起点L,终点为弧度小于π的点R ...

  9. python - 回溯继承树 - 自己实现

    # -*- coding: utf-8 -*- class test(object): pass class test1(test): pass class test2(test1): pass pr ...

  10. Java [Leetcode 231]Power of Two

    题目描述: Given an integer, write a function to determine if it is a power of two. 解题思路: 判断方法主要依据2的N次幂的特 ...