Oracle 存储过程 split 代码实现

实现 字符串分割, 算法 如下:

算法 1:

DECLARE
  remove_column   myvarray_list;
  x    varchar(1000);
  sub  varchar(1000);
  i    NUMBER;
  j    NUMBER;
  c    NUMBER;
  rcount NUMBER;
BEGIN
    remove_column := myvarray_list();   --init array.

    sub:='ORA-26786: 键为 ("AAC001") = (11370911196606055225) 的行存在, 但具有冲突列 "AAC003", "AAE011", "AAE036", "AAE476" (在表 BI3.AC01 中)ORA-01403: 未找到任何数据';
    --sub:='ORA-26786: A row with key ("C1", "C2") = (TEST1, TEST1) exists but has conflicting column(s) "C4" in table SK.T1 ORA-01403: no data found';
    i:= INSTR(sub,'=',1, 1);
    sub := SUBSTR(sub, i);
    i:= INSTR(sub,' "',1, 1);
    sub := SUBSTR(sub, i);
    i := INSTR(sub,'"',-1, 1);
    sub := SUBSTR(sub, 1,i);
    sub:=REPLACE(sub,'"','');
    sub:=REPLACE(sub,' ','');
    --DBMS_OUTPUT.PUT_LINE(sub);
   ------------------------------------------------------------
    j:=1;
    rcount :=1;
    WHILE  INSTR(sub,',',1, j) !=0 LOOP
       i := INSTR(sub,',',1, j);
       IF j = 1 THEN
          c :=1;
        ELSE
          c :=1+ INSTR(sub,',',1, j-1);
       END IF;
       x := SUBSTR(sub,c,i-c);
       j:=j+1;
       --DBMS_OUTPUT.PUT_LINE(x);
       remove_column.extend;
       remove_column(rcount) := x;
       rcount :=rcount+1;

    END LOOP;
    IF j > 1 THEN
       i := INSTR(sub,',',1, j-1);
       x := SUBSTR(sub,i+1);
       --DBMS_OUTPUT.PUT_LINE(x);
    ELSE
       x := sub;
       --DBMS_OUTPUT.PUT_LINE(x);
    END IF;
    remove_column.extend;
    remove_column(rcount) := x;

    FOR x in 1..remove_column.count loop
         dbms_output.put_line(remove_column(x));
    END loop;
END;

算法 2:

DECLARE
  str_split   myvarray_list;
  p_str  varchar(1000);
  j INT := 0;
  i INT := 1;
  lens INT := 0;
  lenp INT := 0;
  p_delimiter VARCHAR(1) := ',';
  str VARCHAR2 (1000);
BEGIN
    str_split := myvarray_list();   --init array.

    p_str:='ORA-26786: 键为 ("AAC001") = (11370911196606055225) 的行存在, 但具有冲突列 "AAC003", "AAE011", "AAE036", "AAE476" (在表 BI3.AC01 中)ORA-01403: 未找到任何数据';
    --p_str:='ORA-26786: A row with key ("C1", "C2") = (TEST1, TEST1) exists but has conflicting column(s) "C4", "C3" in table SK.T1 ORA-01403: no data found';
    i:= INSTR(p_str,'=',1, 1);
    p_str := SUBSTR(p_str, i);
    i:= INSTR(p_str,' "',1, 1);
    p_str := SUBSTR(p_str, i);
    i := INSTR(p_str,'"',-1, 1);
    p_str := SUBSTR(p_str, 1,i);
    p_str:=REPLACE(p_str,'"','');
    p_str:=REPLACE(p_str,' ','');
   ------------------------------------------------------------
    lens := LENGTH (p_str);
    lenp := LENGTH (p_delimiter);
    dbms_output.put_line(lens);
    i := 1;
    j :=0;

    WHILE j < lens LOOP
        j := INSTR (p_str, p_delimiter, i);
        IF j = 0 THEN
            j := lens;
            str := SUBSTR (p_str, i);
            str_split.EXTEND;
            str_split (str_split.COUNT) := str;
            IF i >= lens
            THEN
                EXIT;
            END IF;
        ELSE
            str := SUBSTR (p_str, i, j - i);
            i := j + lenp;
            str_split.EXTEND;
            str_split (str_split.COUNT) := str;
        END IF;
    END LOOP;

    FOR x in 1..str_split.count loop
         dbms_output.put_line(str_split(x));
    END loop;
END;