Find the contiguous subarray within an array (containing at least one number) which has the largest sum.

For example, given the array [−2,1,−3,4,−1,2,1,−5,4],
the contiguous subarray [4,−1,2,1] has the largest sum = 6.

  public static int maxSubArray(int[] A)
{
int max=A[0];
for(int i=0;i<A.length;i++)
{
int sum=0;
for(int j=i;j<A.length;j++)
{
sum+=A[j];
if(sum>max) max=sum; }
} return max;
}

O(n):

 public static int maxSubArray(int[] A)
{
int max=A[0];
int sum=0;
for(int i=0;i<A.length;i++)
{
sum+=A[i];
if(sum>max)
max=sum; if(sum<0)
sum=0;
}
return max;
}

Maximum Subarray (JAVA)的更多相关文章

  1. 53. Maximum Subarray (JAVA)

    iven an integer array nums, find the contiguous subarray (containing at least one number) which has ...

  2. LeetCode 53. Maximum Subarray(最大的子数组)

    Find the contiguous subarray within an array (containing at least one number) which has the largest ...

  3. LeetCode: Maximum Subarray 解题报告

    Maximum Subarray Find the contiguous subarray within an array (containing at least one number) which ...

  4. LeetCode 53. 最大子序和(Maximum Subarray)

    53. 最大子序和 53. Maximum Subarray 题目描述 给定一个整数数组 nums,找到一个具有最大和的连续子数组(子数组最少包含一个元素),返回其最大和. LeetCode53. M ...

  5. [LintCode] Maximum Subarray 最大子数组

    Given an array of integers, find a contiguous subarray which has the largest sum. Notice The subarra ...

  6. 【leetcode】Maximum Subarray (53)

    1.   Maximum Subarray (#53) Find the contiguous subarray within an array (containing at least one nu ...

  7. 算法:寻找maximum subarray

    <算法导论>一书中演示分治算法的第二个例子,第一个例子是递归排序,较为简单.寻找maximum subarray稍微复杂点. 题目是这样的:给定序列x = [1, -4, 4, 4, 5, ...

  8. LEETCODE —— Maximum Subarray [一维DP]

    Maximum Subarray Find the contiguous subarray within an array (containing at least one number) which ...

  9. 【leetcode】Maximum Subarray

    Maximum Subarray Find the contiguous subarray within an array (containing at least one number) which ...

随机推荐

  1. struts1面试题

    由于找了很久的工作都没有找的,只能四处收集那个面试题的.和看面试题的 还有那个记忆力也不是很好了的,而那些公司面试的时候总会有一个面试题的!   在这里分享给大家(那个本来是想上传文件的,但是找不到的 ...

  2. UIView的动画之初步学习

    animateWithDuration:<#(NSTimeInterval)#> delay:<#(NSTimeInterval)#> options:<#(UIView ...

  3. react基于webpack和babel以及es6的项目搭建

    项目demo地址https://github.com/aushion/webpack_reac_config 1.打开命令提示窗口,输入 mkdir react_test cd react_test ...

  4. (转)创建和查看Javadoc文档

    原地址:http://jinnaxu-tju-edu-cn.iteye.com/blog/667177 Javadoc是Sun公司提供的一个技术,它从程序源代码中抽取类.方法.成员等注释形成一个和源代 ...

  5. 操作数据表中的记录——SELECT (where表达式、GROUP BY、HAVING、LIMIT)

    原文链接:http://www.ifyao.com/2015/01/26/%E6%93%8D%E4%BD%9C%E6%95%B0%E6%8D%AE%E8%A1%A8%E4%B8%AD%E7%9A%84 ...

  6. fence repair(队列水过)

    Fence Repair Time Limit: 2000MS   Memory Limit: 65536K Total Submissions: 32916   Accepted: 10638 点我 ...

  7. mac终端 使用摘要

    Root  (拥有对此计算机的所有权限) 查看当前用户:who 切换到root(默认系统是不会使用root的):sudo -s  然后输入密码 更改密码:passwd

  8. 线程池之ThreadPool类与辅助线程 - <第二篇>

    一.CLR线程池 管理线程开销最好的方式: 尽量少的创建线程并且能将线程反复利用(线程池初始化时没有线程,有程序请求线程则创建线程): 最好不要销毁而是挂起线程达到避免性能损失(线程池创建的线程完成任 ...

  9. 用VS2013+VELT-0.1.4进行海思平台 Linux内核 的开发

    快乐虾 http://blog.csdn.net/lights_joy/(QQ群:Visual EmbedLinux Tools 375515651) 欢迎转载,但请保留作者信息 本文仅适用于vs20 ...

  10. Implement Stack using Queues 解答

    Question Implement the following operations of a stack using queues. push(x) -- Push element x onto ...