canvas基础绘制-倒计时(下)
digit_1.js:
digit =
[
[
[0,0,1,1,1,0,0],
[0,1,1,0,1,1,0],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[0,1,1,0,1,1,0],
[0,0,1,1,1,0,0]
],//
[
[0,0,0,1,1,0,0],
[0,1,1,1,1,0,0],
[0,0,0,1,1,0,0],
[0,0,0,1,1,0,0],
[0,0,0,1,1,0,0],
[0,0,0,1,1,0,0],
[0,0,0,1,1,0,0],
[0,0,0,1,1,0,0],
[0,0,0,1,1,0,0],
[1,1,1,1,1,1,1]
],//
[
[0,1,1,1,1,1,0],
[1,1,0,0,0,1,1],
[0,0,0,0,0,1,1],
[0,0,0,0,1,1,0],
[0,0,0,1,1,0,0],
[0,0,1,1,0,0,0],
[0,1,1,0,0,0,0],
[1,1,0,0,0,0,0],
[1,1,0,0,0,1,1],
[1,1,1,1,1,1,1]
],//
[
[1,1,1,1,1,1,1],
[0,0,0,0,0,1,1],
[0,0,0,0,1,1,0],
[0,0,0,1,1,0,0],
[0,0,1,1,1,0,0],
[0,0,0,0,1,1,0],
[0,0,0,0,0,1,1],
[0,0,0,0,0,1,1],
[1,1,0,0,0,1,1],
[0,1,1,1,1,1,0]
],//
[
[0,0,0,0,1,1,0],
[0,0,0,1,1,1,0],
[0,0,1,1,1,1,0],
[0,1,1,0,1,1,0],
[1,1,0,0,1,1,0],
[1,1,1,1,1,1,1],
[0,0,0,0,1,1,0],
[0,0,0,0,1,1,0],
[0,0,0,0,1,1,0],
[0,0,0,1,1,1,1]
],//
[
[1,1,1,1,1,1,1],
[1,1,0,0,0,0,0],
[1,1,0,0,0,0,0],
[1,1,1,1,1,1,0],
[0,0,0,0,0,1,1],
[0,0,0,0,0,1,1],
[0,0,0,0,0,1,1],
[0,0,0,0,0,1,1],
[1,1,0,0,0,1,1],
[0,1,1,1,1,1,0]
],//
[
[0,0,0,0,1,1,0],
[0,0,1,1,0,0,0],
[0,1,1,0,0,0,0],
[1,1,0,0,0,0,0],
[1,1,0,1,1,1,0],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[0,1,1,1,1,1,0]
],//
[
[1,1,1,1,1,1,1],
[1,1,0,0,0,1,1],
[0,0,0,0,1,1,0],
[0,0,0,0,1,1,0],
[0,0,0,1,1,0,0],
[0,0,0,1,1,0,0],
[0,0,1,1,0,0,0],
[0,0,1,1,0,0,0],
[0,0,1,1,0,0,0],
[0,0,1,1,0,0,0]
],//
[
[0,1,1,1,1,1,0],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[0,1,1,1,1,1,0],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[0,1,1,1,1,1,0]
],//
[
[0,1,1,1,1,1,0],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[1,1,0,0,0,1,1],
[0,1,1,1,0,1,1],
[0,0,0,0,0,1,1],
[0,0,0,0,0,1,1],
[0,0,0,0,1,1,0],
[0,0,0,1,1,0,0],
[0,1,1,0,0,0,0]
],//
[
[0,0,0,0],
[0,0,0,0],
[0,1,1,0],
[0,1,1,0],
[0,0,0,0],
[0,0,0,0],
[0,1,1,0],
[0,1,1,0],
[0,0,0,0],
[0,0,0,0]
]//:
];
单独一个数字的绘制分析:

canvas基础绘制-倒计时(下)的更多相关文章
- canvas基础绘制-倒计时(上)
效果: html: <!DOCTYPE html> <html lang="en"> <head> <meta charset=" ...
- canvas基础绘制-绚丽倒计时
效果图: html: <!DOCTYPE html> <html lang="en"> <head> <meta charset=&quo ...
- canvas基础绘制-绚丽时钟
效果图: 与canvas基础绘制-绚丽倒计时的代码差异: // var endTime = new Date();//const声明变量,不可修改,必须声明时赋值: // endTime.setTim ...
- canvas基础绘制-arc
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8&quo ...
- canvas基础绘制-一个小球的坠落、反弹
效果如图: html: <!DOCTYPE html> <html lang="en"> <head> <meta charset=&qu ...
- 自定义控件之Canvas图形绘制基础练习-青春痘笑脸^_^
对于自定义控件的意义不言而喻,所以对它的深入研究是很有必要的,前些年写过几篇关于UI效果的学习过程,但是中途比较懒一直就停滞了,而对于实际工作还是面试来说系统深入的了解自定义控件那是很有必要的,所以接 ...
- HTML5 canvas标签绘制正三角形 鼠标按下点为中间点,鼠标抬起点为其中一个顶点
用html5的canvas标签绘制圆.矩形比较容易,绘制三角形,坐标确定相当于前面两种难点,这里绘制的是正三角形,比较容易,我们只需要把鼠标刚按下去的点设置为三角形的中心点,鼠标抬起的点设置为三角形右 ...
- 小程序canvas绘制倒计时
如果本文对你有用,请爱心点个赞,提高排名,帮助更多的人.谢谢大家!❤ 如果解决不了,可以在文末进群交流. 效果展示: //广告倒计时 advTimeCountDown:function(advTime ...
- HTML5移动开发学习笔记之Canvas基础
1.第一个Canvas程序 看的是HTML5移动开发即学即用这本书,首先学习Canvas基础,废话不多说,直接看第一个例子. 效果图为: 代码如下: <!DOCTYPE html> < ...
随机推荐
- java 开发面试题小整理(二)
51.Anonymous Inner Class(匿名内部类)是否可以继承其它类?是否可以实现接口? 答:可以继承其他类或实现其他接口,在Swing编程和Android开发中常用此方式来实现事件监听和 ...
- 完美解决pip install scrapy,安装Scrapy错误:Microsoft Visual C++ 14.0 is required. Get it with "Microsoft Visual C++ Build Tools": http://landinghub.visualstudio.com/visual-cpp-build-tools
1,在Python3.6 安装Scrapy 出现以下报错 2,错误分析 红色报的错误指向的是Twisted 1,Twisted 没安装上 2,Twisted 没安装成功 3,Twisted 版本与Py ...
- jquery实现无限滚动瀑布流实现原理
现在类似于pinterest这类的表现效果很火,其实我比较中意的是他的布局效果,而不是那种瀑布流. 虽然我不是特别喜欢这种瀑布流的表现样式,但是还是写了几篇关于无限滚动瀑布流效果的文章,Infinit ...
- python的日志logging模块性能以及多进程
写在前面: 日志是记录操作的一种好方式.但是日志,基本都是基于文件的,也就是要写到磁盘上的.这时候,磁盘将会成为一个性能瓶颈.对于普通的服务器硬盘(机械磁盘,非固态硬盘),python日志的性能瓶颈是 ...
- Spring MVC访问页面直接显示源码
转自:https://blog.csdn.net/u011781521/article/details/78751253
- E20180419-hm
rectangle n. [数] 长方形,矩形; ratio n. 比例; 比,比率; 系数; vt. 求出比值,除,使…成比例; 将(相片)按比例放大[缩小]; aspect n. 方面; 面貌 ...
- (水题)洛谷 - P1583 - 魔法照片
https://www.luogu.org/problemnew/show/P1583 设计一个strcut cmp用来比较,就可以了. #include<bits/stdc++.h> u ...
- HDU6035:Colorful Tree(树形DP)
传送门 题意 给出一棵最小生成树及每个节点的颜色,询问\(\frac{n(n-1)}2\)条路径的权值和,一条路径的权值为该路径的颜色种数 分析 勉强理解了ftae的做法,但是代码还是不太会,还是太弱 ...
- POJ2796【单调栈】
题意: 题意:n个数,求某段区间的最小值*该段区间所有元素之和的最大值 思路: 主要参考:http://www.cnblogs.com/ziyi–caolu/archive/2013/06/23/31 ...
- hihoCoder 1032
最长回文子串的O(1)算法Manacher算法 #include <iostream> #include <stdio.h> #include <string.h> ...