问题 : cut sticks

时间限制: 1 Sec  内存限制: 128 MB

题目描述

George took sticks of the same length and cut them randomly until all parts became at most 20 units long. Now he wants to return sticks to the original state, but he forgot how many sticks he had originally and how long they were originally. Please help him and design a program which computes the smallest possible original length of those sticks. All lengths expressed in units are integers greater than zero.

输入

Input  consists of multiple problem  instances.  Each  instance  contains blocks of 2 lines. The first line contains the number of sticks parts after cutting, there are at most 64 sticks. The second line contains the lengths of those parts separated by the space. The last line of the file contains zero.

输出

The output should contains the smallest possible length of original sticks, one per line.

样例输入

9
5 2 1 5 2 1 5 2 1
4
1 2 3 4
0

样例输出

6
5
#include <stdio.h>
#include <algorithm>
using namespace std;
int main()
{
    int n, s[65];
    while (scanf("%d", &n), n)
    {
        for (int i = 0; i < n; i++)
            scanf("%d", &s[i]);
        sort(s, s + n);
        printf("%d\n", s[0] + s[n - 1]);
    }
    return 0;
}

cut sticks的更多相关文章

  1. Cut the sticks

    def main(): n = int(raw_input()) arr = map(int, raw_input().strip().split()) for i in range(n): cutN ...

  2. hduoj 1455 && uva 243 E - Sticks

    http://acm.hdu.edu.cn/showproblem.php?pid=1455 http://uva.onlinejudge.org/index.php?option=com_onlin ...

  3. POJ1011 Sticks

    Description George took sticks of the same length and cut them randomly until all parts became at mo ...

  4. hdu.5203.Rikka with wood sticks(数学推导:一条长度为L的线段经分割后可以构成几种三角形)

    Rikka with wood sticks Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/O ...

  5. hdu 1455 Sticks

    Sticks Time Limit:1000MS     Memory Limit:32768KB     64bit IO Format:%I64d & %I64u Submit Statu ...

  6. DFS(剪枝) POJ 1011 Sticks

    题目传送门 /* 题意:若干小木棍,是由多条相同长度的长木棍分割而成,问最小的原来长木棍的长度: DFS剪枝:剪枝搜索的好题!TLE好几次,终于剪枝完全! 剪枝主要在4和5:4 相同长度的木棍不再搜索 ...

  7. poj 1011 Sticks

    Sticks Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 126238   Accepted: 29477 Descrip ...

  8. POJ 1011 sticks 搜索

    Sticks Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 125918   Accepted: 29372 Descrip ...

  9. poj1011 Sticks(dfs+剪枝)

    Sticks Time Limit: 1000MS   Memory Limit: 10000K Total Submissions: 110416   Accepted: 25331 Descrip ...

随机推荐

  1. JAVA进阶3

    间歇性混吃等死,持续性踌躇满志系列-------------第3天 1.局部内部类 局部内部类是指在类的方法中定义的内部类,它的作用范围也是在这个方法体内. class SellOutClass{ p ...

  2. objectMapper、JsonNode、JsonObject常用方法

    一.objectMapper https://blog.csdn.net/han1196639488/article/details/79358743 二.JsonNode.JsonObject常用方 ...

  3. RESTful支持

    springmvc restful 支持 - 哎幽的成长 - CSDN博客http://blog.csdn.net/u012373815/article/details/47208345 RESTfu ...

  4. shell编程 之 运算符

    1 shell运算符简介 Shell 和其他编程语言一样,支持多种运算符,包括: 算数运算符 形如:val=`expr 2 + 2`:echo "两数之和为 : $val"    ...

  5. Spring @Bean注解 (基于java的容器注解)

    基于java的容器注解,意思就是使用Java代码以及一些注解,就可以取代spring 的 xml配置文件. 1-@Configuration & @Bean的配合 @Configuration ...

  6. 2018牛客暑期ACM多校训练营第一场(有坑未填)

    (重新组队后的第一场组队赛 也是和自己队友的一次磨合吧 这场比赛真的算是一个下马威吧……队友上手一看 啊这不是莫队嘛 然后开敲 敲完提交发现t了 在改完了若干个坑点后还是依然t(真是一个悲伤的故事)然 ...

  7. Shell-find . -type f -name "*.log" -print0 | xargs -0 rm -f

    用 rm 删除太多的文件时候,可能得到一个错误信息:/bin/rm Argument list too long.

  8. 设计模式C++学习笔记之三(Singleton单例模式)

    单例模式看起来也蛮简单的,就是在系统中只允许产生这个类的一个实例,既然这么简单,就直接贴代码了.更详细的内容及说明可以参考原作者博客:cbf4life.cnblogs.com. 3.1.解释 main ...

  9. iperf 2.05版本升级到2.0.9

    将openwrt  trunk 分支上iperf 2.0.9移植到 bb版本上时,编译遇到如下问题: make[6]: Entering directory '/home/hbg/bb/build_d ...

  10. ubuntu Qt linuxdeployqt打包

    1.下载PatchELF 0.9.,https://nixos.org/patchelf.html 安装:./configure make sudo make install 2.终端命令设置设置环境 ...