Day03（黑客成长日记）------>元祖及列表的增减改查

#昨日作业解析：

# s = 'sadagwa'
# i = 0
# while i < len(s):
#     s1 = s[i]
#     print(s1)
#     i += 1
# while使用技巧，先找递增变量或者递减变量

#简单的加法计算器    print在输入多种元素时要用逗号隔开
# content = input('计算：').strip()
# s1 = content . split('+')
# num = 0
# for i in s1:
#     num += int(i)
# print(num)

# s = input('请输入：')
# count = 0
# s2 = s.split('abcd')
# for i in s2:
#     if s2.isdigit:
#         count = count+1
# print(count)

#判断用户输入的数据中数字的个数代码
# s = input('请输入：')
# count = 0
# for i in s :
#     if i .isdigit():
#         count+= 1
# print(count)

#
# s = input('请输入：')
# s2 = s.split(s.isalnum())

#23165  asdasd   321
# while :
#     count = count

#lise增删改查以及嵌套

#                          1. append                  增加到列表最后

# 公司整理人员名单输入代码                    （利用增加）
# li = ['alex','wusir','tongsir','qienfseir','taige']
#
# while 1 :
#     username = input('>>>>')
#     if username.strip().upper()== 'Q':
#         break
#     else:
#         li.append(username)
#         print(li)
# print(li)

#                         2.   insert                  镶嵌

# li = ['alex','wusir','tongsir','qienfseir','taige']
# li.insert(4,'tong')
# print(li)

#                         3.   extend   list叠加是元素，用exte    迭代嵌套（int数据不可以）

# li = ['alex','wusir','tongsir','qienfseir','taige']
# li.extend('同哥')
# print(li)             #['alex', 'wusir', 'tongsir', 'qienfseir', 'taige', '同', '哥']

#                         4.pop(索引)        删除元素

# li = ['alex','wusir','tongsir','qienfseir','taige']
# li.pop(1)
# print(li)               #------------->输出['alex', 'tongsir', 'qienfseir', 'taige']

# li = ['alex','wusir','tongsir','qienfseir','taige']
# name = li.pop(1)
# print(name,li)          #赋值的话会输出删除的元素，删唯一一个有返回值的用法，不填默认删除最后一个
                          #输出 wusir ['alex', 'tongsir', 'qienfseir', 'taige']

#
                          # 5.remove按照元素删除remove（'yuansu'）

                          # 6.clean 清空列表

                          # 7.del li 删除li列表    del li[0:2]

                          # 8.li[索引]='更改内容'

# li = ['alex','wusir','tongsir','qienfseir','taige']
# li[0]='tongs'
# print(li)       output = ['tongs', 'wusir', 'tongsir', 'qienfseir', 'taige']
#
#
# li[0:3] = [1,2,3,'sir','madom']
# print(li)       output = [1, 2, 3, 'sir', 'madom', 'qienfseir', 'taige']

                          # 9 .查列表元素
# li = [1, 2, 3, 'sir', 'madom', 'qienfseir', 'taige']
# for i in li :
#     print(i)
#
#
# output=  1
#          2
#          3
#          sir
#          madom
#          qienfseir
#          taige

                           #10.列表排序（面试考）
# li = [1,2,5,8,4,7]
# li.sort()                !=sort=正向排序
# print(li)               output = [1, 2, 4, 5, 7, 8]

# li = [1,2,5,8,4,7]
# li.sort(reverse=True)      !=sorted(reverse=True)则反向排序
# print(li)                 output = [8, 7, 5, 4, 2, 1]

#
li = [1,2,5,8,4,7]
# li.reverse()                 !=reverse()反转
# print(li)                   output = [7, 4, 8, 5, 2, 1]

# li = ['taibai','武藤兰','yuanwu',['alex','89'],23]
# print(li[1][1])
# print(li[0].capitalize())
# li[0] = li[0].capitalize()
# print(li)

# li[3][0]=li[3] [0].upper()
# print(li)

#想改什么先找出来，操作完放回去。
#将上面的li中89改为100
# li[3][1]=int(li[3][1])+11
# print(li)
#
# li[3][1] = 100
# print(li)

# 元祖tupe：只读列表，可以循环查询数据，但不可以修改，但是可以切片（儿子不能改，孙子可以改）（里面的元素不可以改，带里面的列表可以改，比如改下面的太白）
# tu = (1,2,3,'alex',[2,3,4,'taibai'],'egon')
# for i in tu:
#     print(i)         # 可以查询可以循环

#大写taibai
# tu[4][3]=tu[4][3].upper()
# print(tu)

#                              #11.    join的操作方法（可迭代对象）除了数字和bool返回的是字符串

# s = 'alex'
# s1 = ' '.join(s)
# print(s1)            #output = a l e x

#列表转换为Str用join，Str转换为list用str.split

#                              #12.          range 的用法
# for i in range(0,10,2):
#     print(i)
#output = 0 2 4 6 8

# for i in range(10,0,-2):
#     print(i)
# output = 10 8 6 4 2

# for i in range (0,10,-1)
#     print(i)                 output = 不输入任何数据！！！！！！！！！！面试题

# li = [1,2,3,4,'alex',[2,3,4,5,'taibai'],'afds']
# count = 0
# num = 0
# if 1 :
#     while count!=5 :
#         s = li[count]
#         print(s)
#         count += 1
#         if count ==6:
#             continue
#     while count ==5 :
#         s1 = li[5][num]
#         print(s1)
#         num += 1
#         if num >=5:
#             count +=1
#     while count!=5 :
#         s = li[count]
#         print(s)
#         count += 1
#         if count==7:
#             break

# for i in li:
#     print(i)
#     if i ==[2,3,4,5,'taibai']:
#         for s in i:
#             print(s)