Given an array A of strings made only from lowercase letters, return a list of all characters that show up in all strings within the list (including duplicates).  For example, if a character occurs 3 times in all strings but not 4 times, you need to include that character three times in the final answer.

You may return the answer in any order.

Example 1:

Input: ["bella","label","roller"]
Output: ["e","l","l"]

Example 2:

Input: ["cool","lock","cook"]
Output: ["c","o"]
class Solution {
public List<String> commonChars(String[] A) {
List<String> res = new ArrayList<>();
if (A == null || A.length == 0) {
return res;
}
int[] lowerCaseArr = new int[26];
for (char c: A[0].toCharArray()) {
lowerCaseArr[c - 'a'] += 1;
}
for (int i = 1; i < A.length; i++) {
int[] curDict = new int[26];
for (char c: A[i].toCharArray()) {
curDict[c - 'a'] += 1;
}
for (int j = 0; j < lowerCaseArr.length; j++) {
lowerCaseArr[j] = Math.min(lowerCaseArr[j], curDict[j]);
}
} for (int i = 0; i < lowerCaseArr.length; i++) {
while (lowerCaseArr[i] > 0) {
res.add(Character.toString((char)(i + 'a')));
lowerCaseArr[i] -= 1;
}
}
return res;
}
}

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