geeksforgeeks@ Sorting Elements of an Array by Frequency (Sort)
http://www.practice.geeksforgeeks.org/problem-page.php?pid=493
Sorting Elements of an Array by Frequency
Given an array of integers, sort the array according to frequency of elements. For example, if the input array is {2, 3, 2, 4, 5, 12, 2, 3, 3, 3, 12}, then modify the array to {3, 3, 3, 3, 2, 2, 2, 12, 12, 4, 5}.
If frequencies of two elements are same, print them in increasing order.
Input:
The first line of input contains an integer T denoting the number of test cases. The description of T test cases follows. The first line of each test case contains a single integer N denoting the size of array. The second line contains N space-separated integers A1, A2, ..., AN denoting the elements of the array.
Output:
Print each sorted array in a seperate line. For each array its numbers should be seperated by space.
Constraints:
1 ≤ T ≤ 70
30 ≤ N ≤ 130
1 ≤ A [ i ] ≤ 60
Example:
Input:
1
5
5 5 4 6 4
Output:
4 4 5 5 6
import java.util.*;
import java.lang.*;
import java.io.*; class pair {
public int freq;
public int key;
public pair(int f, int k) {
super();
this.freq = f;
this.key = k;
}
} class cmp implements Comparator<pair> { public int compare(pair p1, pair p2) {
if(p1.freq != p2.freq) {
return p2.freq - p1.freq;
} else {
return p1.key - p2.key;
}
}
} class GFG { public static void pln(Object[] ls) {
for(int i=0; i<ls.length; ++i) {
System.out.print(ls[i]);
} System.out.println();
} public static void func(int[] arr) { int n = arr.length;
HashMap<Integer, Integer> mapping = new HashMap<Integer, Integer> (); for(int na: arr) {
if(!mapping.containsKey(na)) {
mapping.put(na, 0);
}
mapping.put(na, mapping.get(na) + 1);
} TreeSet<pair> freqToKey = new TreeSet<pair> (new cmp());
Iterator iter = mapping.entrySet().iterator();
while(iter.hasNext()) {
Map.Entry entry = (Map.Entry) iter.next();
int key = (int) entry.getKey();
int freq = (int) entry.getValue();
pair p = new pair(freq, key);
freqToKey.add(p);
} Object[] ls = freqToKey.toArray();
for(int i=0; i<ls.length; ++i) {
pair p = (pair) ls[i];
int freq = p.freq;
int key = p.key; while(freq > 0) {
--freq;
System.out.print(key + " ");
}
} System.out.println();
} public static void main (String[] args) {
Scanner in = new Scanner(System.in);
int times = in.nextInt(); while(times > 0) {
--times; int n = in.nextInt();
int[] arr = new int[n];
for(int i=0; i<n; ++i) {
arr[i] = in.nextInt();
} func(arr);
}
}
}
geeksforgeeks@ Sorting Elements of an Array by Frequency (Sort)的更多相关文章
- Array类的Sort()方法
刚复习了Array类的sort()方法, 这里列举几个常用的,和大家一起分享. Array类实现了数组中元素的冒泡排序.Sort()方法要求数组中的元素实现IComparable接口.如System. ...
- 【leetcode】1144. Decrease Elements To Make Array Zigzag
题目如下: Given an array nums of integers, a move consists of choosing any element and decreasing it by ...
- 【LeetCode】1464. 数组中两元素的最大乘积 Maximum Product of Two Elements in an Array (Python)
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 暴力 找最大次大 日期 题目地址:https://le ...
- 排序算法 (sorting algorithm)之 冒泡排序(bubble sort)
http://www.algolist.net/Algorithms/ https://docs.oracle.com/javase/tutorial/collections/algorithms/ ...
- [Algorithms] Divide and Recurse Over an Array with Merge Sort in JavaScript
Merge sort is a recursive sorting algorithm. If you don't understand recursion, I recommend finding ...
- .NET中string[]数组和List<string>泛型的相互转换以及Array类的Sort()方法(转)
从string[]转List<string>: " }; List<string> list = new List<string>(str); 从List ...
- js中的数组Array定义与sort方法使用示例
Array的定义及sort方法使用示例 Array数组相当于java中的ArrayList 定义方法: 1:使用new Array(5 )创建数组 var ary = new Array(5): ...
- 排序算法(sorting algorithm) 之 选择排序(selection sort)
https://en.wikipedia.org/wiki/Selection_sort loop1: 4,6,1,3,7 -> 4,6,1,3,7 4,6,1,3,7 -> ,3,7 1 ...
- 排序算法(sorting algorithm)之 插入排序(insertion sort)
https://en.wikipedia.org/wiki/Insertion_sort loop1: 4,6,1,3,7 -> 4,6,1,3,7 loop2: 4,6,1,3,7 -> ...
随机推荐
- 单元测试之道(使用NUnit)
首先来看下面几个场景你是否熟悉 1.你正在开发一个系统,你不断地编码-编译-调试-编码-编译-调试……终于,你负责的功能模块从上到下全部完成且编译通过!你长出一口气,怀着激动而 又忐忑的心情点击界面上 ...
- Create a unit test project
https://msdn.microsoft.com/en-us/library/hh598957.aspx Unit tests often mirror the structure of the ...
- number-of-boomerangs
https://leetcode.com/problems/number-of-boomerangs/ package com.company; import java.util.*; class S ...
- hdu 4856 Tunnels (bfs + 状压dp)
题目链接 The input contains mutiple testcases. Please process till EOF.For each testcase, the first line ...
- WCF常见异常-The maximum string content length quota (8192) has been exceeded while reading XML data
异常信息:The maximum string content length quota (8192) has been exceeded while reading XML data 问题:调用第三 ...
- 51nod1125 交换机器的最小代价
跟做过的bzoj一道置换群的题几乎一样,只是数据范围大了点,那么就用map就好了... #include<cstdio> #include<cstring> #include& ...
- kafka_2.9.2-0.8.1.1分布式集群搭建代码开发实例
准备3台虚拟机, 系统是RHEL64服务版. 1) 每台机器配置如下:$ cat /etc/hosts # zookeeper hostnames: 192.168.8.182 ...
- BZOJ 1452 Count
长知识啦..二维BIT. #include<iostream> #include<cstdio> #include<cstring> #include<alg ...
- BZOJ 3391 Tree Cutting网络破坏
不想写. #include<iostream> #include<cstdio> #include<cstring> #include<cstdlib> ...
- HDU 5371 Hotaru's problem (Manacher,回文串)
题意:给一个序列,找出1个连续子序列,将其平分成前,中,后等长的3段子序列,要求[前]和[中]是回文,[中]和[后]是回文.求3段最长为多少?由于平分的关系,所以答案应该是3的倍数. 思路:先Mana ...