1083. List Grades (25)
the problem is from PAT,which website is http://pat.zju.edu.cn/contests/pat-a-practise/1083
and the source code is as followed.
/*
firstly: sort the array using the algorithm "sort"
secondly: traverse all the possible answer and find the most suitable one.
*/
#include<iostream>
#include<vector>
#include<string>
#include<algorithm> using namespace std; struct record
{
string name;
string id;
int grade;
}; bool cmp(record x,record y)
{
return x.grade > y.grade;
} int main()
{
int n;
record temp;
vector<record> v;
cin>>n;
while (n--)
{
cin>>temp.name>>temp.id>>temp.grade;
v.push_back(temp);
}
int low,high;
cin>>low>>high; sort(v.begin(),v.end(),cmp);
int count = ;
for (int i = ; i < v.size(); i++)
{ if (v[i].grade>=low && v[i].grade <= high)
{
cout<<v[i].name<<" "<<v[i].id<<endl;
count += ;
}
}
if (count == )
{
cout<<"NONE"<<endl;
} }
this one is easy.and it doesn’t need to talk too much. If there are something to be noticed ,
maybe i think we should notice the boundery.
1083. List Grades (25)的更多相关文章
- 【PAT甲级】1083 List Grades (25 分)
题意: 输入一个正整数N(<=101),接着输入N个学生的姓名,id和成绩.接着输入两个正整数X,Y(0<=X,Y<=100),逆序输出成绩在x,y之间的学生的姓名和id. tric ...
- PAT (Advanced Level) 1083. List Grades (25)
简单排序. #include<cstdio> #include<cstring> #include<cmath> #include<vector> #i ...
- 1083. List Grades (25)-简单的排序
给定区间[L,R],给出在这区间之内的学生,并且按照他们的成绩非升序的顺序输出. #include <iostream> #include <cstdio> #include ...
- pat1083. List Grades (25)
1083. List Grades (25) 时间限制 400 ms 内存限制 65536 kB 代码长度限制 16000 B 判题程序 Standard 作者 CHEN, Yue Given a l ...
- PAT 甲级 1083 List Grades (25 分)
1083 List Grades (25 分) Given a list of N student records with name, ID and grade. You are supposed ...
- PAT 1083 List Grades[简单]
1083 List Grades (25 分) Given a list of N student records with name, ID and grade. You are supposed ...
- A1083 List Grades (25)(25 分)
A1083 List Grades (25)(25 分) Given a list of N student records with name, ID and grade. You are supp ...
- 1083 List Grades
Given a list of N student records with name, ID and grade. You are supposed to sort the records with ...
- PAT 甲级 1083 List Grades
https://pintia.cn/problem-sets/994805342720868352/problems/994805383929905152 Given a list of N stud ...
随机推荐
- Int.Parse()、Convert.toInt32()和(int)区别
通过网上的查询从而了解了Int.Parse().Convert.toInt32()和(int)区别. 一.定义上的差别 int类型表示一种整型,.NET Framework 类型为 System.In ...
- SQL Server2005安装配置以及测试
SQL Server2005有2种版本,一种是集成版的, 一种是2个文件夹形式的.这里使用后者,安装文件夹名字为:SQL Server x86,该文件夹里面有Servers和Tools文件夹以及一些其 ...
- Python对象体系揭秘
Guido用C语言创造了Python,在Python的世界中一切皆为对象. 一.C视角中的Python对象 让我们一起追溯到源头,Python由C语言实现,且向外提供了C的API http://doc ...
- BootStrap入门教程 (三) :可重用组件(按钮,导航,标签,徽章,排版,缩略图,提醒,进度条,杂项)
上讲回顾:Bootstrap的基础CSS(Base CSS)提供了优雅,一致的多种基础Html页面要素,包括排版,表格,表单,按钮等,能够满足前端工程师的基本要素需求. Bootstrap作为完整的前 ...
- Apache Rewrite常用设置说明
例子: RewriteEngine on 打开引擎 RewriteRule test.html /test.php [L] RewriteRule test.html?$ /tianqi.php?s1 ...
- Spark系列(九)DAGScheduler工作原理
以wordcount为示例进行深入分析 1 33 ) { 46 logInfo("Submitting " + tasks.size + " missi ...
- 新手指导:教你如何查看识别hadoop是32位还是64位
问题导读: 1.从哪些地方可以识别hadoop是32位还是64位?2.hadoop本地库在什么位置? 来源:about云 本文链接:http://www.aboutyun.com/thread-127 ...
- [JLOI2013]地形生成
JLOI2013过了好长时间,才写第四题.. 第一问比较好想. 第二问我想到了n^3次方的做法,但是数据....于是没敢写,然后上网查了一下题解,居然是O(n^3)过的,数据这么弱... /* * P ...
- GridControl表头全选操作实现之最优方法
突然发现很久没有写博客了. 昨天整了个Windows Live Writer 就为了以后好好写写博客. 所以,开始咯. 为了积累,也为了分享. 之前在博客园中看到一篇文章:<Winform分页控 ...
- jquery easyui将form表单元素的值序列化成对象
function serializeObject(form){ var o={}; $.each(form.serializeArray(),function(index){ if(o[this['n ...