fight
为啥用block copy.
从栈到拷贝到堆
循环引用,控制器引用block. block里面调用 self
self引用控件,控件引用block,block里面引用self
http://www.jianshu.com/p/b79bac09177e
控制器引用view,如果view strong引用代理属性,控制器又是view的代理,就不能被正常释放了,内存涨,闪退
autorelease
fight的更多相关文章
- Australian troops to the fight against Islamic State militants.
He arrived in Arnhem Land on Sunday, honouring an election promise to spend a week every year in an ...
- codeforces 487A A. Fight the Monster(二分)
题目链接: A. Fight the Monster time limit per test 1 second memory limit per test 256 megabytes input st ...
- shadow fight 1.6.0 内购
shadow fight 之前的版本只需要安装LocallApstore即可内购. 1.6.0的版本中加了越狱检查. 所以LocallApstore 无法直接使用. 需要安装xcon避开越狱检查. 也 ...
- Codeforces Round #278 (Div. 1) A. Fight the Monster 暴力
A. Fight the Monster Time Limit: 20 Sec Memory Limit: 256 MB 题目连接 http://codeforces.com/contest/487/ ...
- hdu 4778 Gems Fight! 博弈+状态dp+搜索
作者:jostree 转载请注明出处 http://www.cnblogs.com/jostree/p/4102743.html 题目链接:hdu 4778 Gems Fight! 博弈+状态dp+搜 ...
- hdu 4778 Gems Fight! 状态压缩DP
Gems Fight! Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 327680/327680 K (Java/Others)T ...
- Codeforces 954D Fight Against Traffic(BFS 最短路)
题目链接:Fight Against Traffic 题意:有n个点个m条双向边,现在给出两个点S和T并要增加一条边,问增加一条边且S和T之间距离不变短的情况有几种? 题解:首先dfs求一下S到其他点 ...
- HDU 4778 Gems Fight! (2013杭州赛区1009题,状态压缩,博弈)
Gems Fight! Time Limit: 20000/10000 MS (Java/Others) Memory Limit: 327680/327680 K (Java/Others)T ...
- 19. Fight over Fox-hunting 猎狐引发的冲突
. Fight over Fox-hunting 猎狐引发的冲突 ① Foxes and farmers have never got on well.These small dog-like ani ...
- Codeforces Round #354 (Div. 2) E. The Last Fight Between Human and AI 数学
E. The Last Fight Between Human and AI 题目连接: http://codeforces.com/contest/676/problem/E Description ...
随机推荐
- 【面试题】BD
一面: 自我介绍,简单介绍项目: /***********发现项目没什么可问的,然后开始各种基础知识o(╯□╰)o************/ 内存结构,低地址,高地址: STL底层实现,set是否有序 ...
- 封装原生Ajax
var Chef = { createAjax:function() { var xhr = null; try { //IE系列浏览器 xhr = new ActiveXObject("m ...
- HBase 分布式环境搭建
一.前期环境 安装概览 IP Host Name Software Node 192.168.23.128 ae01 JDK 1.7, Zookeeper-3.4.5 HMaster 192.168. ...
- Handling events in an MVVM WPF application
Posted: June 30, 2013 | Filed under: MVVM, WPF, XAML |1 Comment In a WPF application that uses the ...
- git冲突解决
http://www.cnblogs.com/sinojelly/archive/2011/08/07/2130172.html http://hi.baidu.com/jqxw4444/item/f ...
- 【bzoj3439】kpm的mc密码 题解
题目大意: 有n个字符串,编号为1~n,求每一个字符串在其他字符串中以它为后缀的字符串中编号第k小的字符串的编号. 思路: 将字符串倒过来建Trie,记录每个结尾节点的编号(可能会有重复,所以开一个v ...
- HDU - The number of divisors(约数) about Humble Numbers
Description A number whose only prime factors are 2,3,5 or 7 is called a humble number. The sequence ...
- 【Oracle】同义词问题
优点: 1.节省数据库空间,多用户可以操作同一张表: 2.扩展的数据库的使用范围,能够在不同的数据库用户之间实现无缝交互: 3.利用Database Link.创建同义词可以实现不同数据库服务器之间的 ...
- 关于Go,你可能不注意的7件事(转的)
http://tonybai.com/2015/09/17/7-things-you-may-not-pay-attation-to-in-go/ code https://github.com/bi ...
- 转载:C# this.invoke()作用 多线程操作UI 理解二
Invoke()的作用是:在应用程序的主线程上执行指定的委托.一般应用:在辅助线程中修改UI线程( 主线程 )中对象的属性时,调用this.Invoke(); //测试的窗体 public class ...