Given a string, we can "shift" each of its letter to its successive letter, for example: "abc" -> "bcd". We can keep "shifting" which forms the sequence:

"abc" -> "bcd" -> ... -> "xyz"

Given a list of strings which contains only lowercase alphabets, group all strings that belong to the same shifting sequence.

For example, given: ["abc", "bcd", "acef", "xyz", "az", "ba", "a", "z"],
A solution is:

[
["abc","bcd","xyz"],
["az","ba"],
["acef"],
["a","z"]
]
 
Solution:
public class Solution {
public List<List<String>> groupStrings(String[] strings) {
List<List<String>> resLists = new LinkedList<List<String>>(); HashMap<String,List<String>> patternMap = new HashMap<String,List<String>>();
for (String str : strings){
StringBuilder builder = new StringBuilder().append(str);
int delta = builder.charAt(0)-'a';
builder.setCharAt(0,'a');
for (int i=1;i<builder.length();i++){
char c = (char) ((builder.charAt(i) + 26 - delta)%26);
builder.setCharAt(i,c);
}
String pattern = builder.toString();
if (!patternMap.containsKey(pattern)){
patternMap.put(pattern,new LinkedList<String>());
}
patternMap.get(pattern).add(str);
} for (List<String> strList : patternMap.values()){
resLists.add(strList);
}
return resLists;
}
}

LeetCode-Group Shifted Strings的更多相关文章

  1. [LeetCode] Group Shifted Strings 群组偏移字符串

    Given a string, we can "shift" each of its letter to its successive letter, for example: & ...

  2. LeetCode – Group Shifted Strings

    Given a string, we can "shift" each of its letter to its successive letter, for example: & ...

  3. [Locked] Group Shifted Strings

    Group Shifted Strings Given a string, we can "shift" each of its letter to its successive ...

  4. [LeetCode#249] Group Shifted Strings

    Problem: Given a string, we can "shift" each of its letter to its successive letter, for e ...

  5. LeetCode 249. Group Shifted Strings (群组移位字符串)$

    Given a string, we can "shift" each of its letter to its successive letter, for example: & ...

  6. [LeetCode] 249. Group Shifted Strings 分组偏移字符串

    Given a string, we can "shift" each of its letter to its successive letter, for example: & ...

  7. Group Shifted Strings -- LeetCode

    Given a string, we can "shift" each of its letter to its successive letter, for example: & ...

  8. 249. Group Shifted Strings

    题目: Given a string, we can "shift" each of its letter to its successive letter, for exampl ...

  9. [Swift]LeetCode249.群组偏移字符串 $ Group Shifted Strings

    Given a string, we can "shift" each of its letter to its successive letter, for example: & ...

  10. Group Shifted Strings

    Given a string, we can "shift" each of its letter to its successive letter, for example: & ...

随机推荐

  1. Objective-C中常用的结构体NSRange,NSPoint,NSSize(CGSize),NSRect

    本节要点:红色标记 需要记下来 1   NSRange typedef struct _NSRange {     NSUInteger location;     NSUInteger length ...

  2. 8 Regular Expressions You Should Know

    Regular expressions are a language of their own. When you learn a new programming language, they're ...

  3. C语言指针学习(续)

    五.数组和指针的关系 int array[10] = {0,1,2,3,4,5,6,7,8,9},value; ... ... value = array[0];//也可以写成 value = *ar ...

  4. python 小程序练习

    还有一些小bug 基本有 输入用户名密码 认证成功后显示欢迎信息 输出三次后锁定 # -*- coding:utf-8 -*- account_file=('C:\Users\guigu\Deskto ...

  5. char,vchar,nchar,nvchar的区别

    char和varchar的长度都在1到8000之间,它们的区别在于char是定长字符数据,而varchar是变长字符数据.所谓定长就是长度固定的,当输入的数据长度没有达到指定的长度时将自动以英文空格在 ...

  6. uva 122 trees on the level——yhx

    题目如下:Given a sequence of binary trees, you are to write a program that prints a level-order traversa ...

  7. IOS Orientation, 想怎么转就怎么转~~~

    此博文主要针对IOS应用, 是屏幕旋转相关问题的一个总结. 主要内容有: IOS5,6,7不同版的适配. 强制旋转和自动旋转. 博客: http://www.cnblogs.com/jhzhu 邮箱: ...

  8. 边工作边刷题:70天一遍leetcode: day 85-3

    Zigzag Iterator 要点: 实际不是zigzag而是纵向访问 这题可以扩展到k个list,也可以扩展到只给iterator而不给list.结构上没什么区别,iterator的hasNext ...

  9. UVA-10652 (凸包)

    题意: 给n个矩形,问包含这些矩形的尽量小的凸多边形的面积是多少; 思路: 由于给的矩形的形式是给出了中心的坐标,长和宽以及旋转的角度,所以先转换成四个点的坐标,然后求一遍凸包就好了,第一次写凸包,代 ...

  10. UVALive 6470 Chomp --记忆化搜索

    题意:给一个只有三行的方块阵(横向最多100个),然后p,q,r分别代表第1,2,3层的方格数,两人轮流去掉一个格子,此时这个格子的右上方都会被去掉,面临只剩最左下角的一个格子的状态的人输,问先手能否 ...