POJ-1953 World Cup Noise(线性动规)
World Cup Noise
Time Limit: 1000MS Memory Limit: 30000K
Total Submissions: 16374 Accepted: 8097
Description
Background
“KO-RE-A, KO-RE-A” shout 54.000 happy football fans after their team has reached the semifinals of the FIFA World Cup in their home country. But although their excitement is real, the Korean people are still very organized by nature. For example, they have organized huge trumpets (that sound like blowing a ship’s horn) to support their team playing on the field. The fans want to keep the level of noise constant throughout the match.
The trumpets are operated by compressed gas. However, if you blow the trumpet for 2 seconds without stopping it will break. So when the trumpet makes noise, everything is okay, but in a pause of the trumpet,the fans must chant “KO-RE-A”!
Before the match, a group of fans gathers and decides on a chanting pattern. The pattern is a sequence of 0’s and 1’s which is interpreted in the following way: If the pattern shows a 1, the trumpet is blown. If it shows a 0, the fans chant “KO-RE-A”. To ensure that the trumpet will not break, the pattern is not allowed to have two consecutive 1’s in it.
Problem
Given a positive integer n, determine the number of different chanting patterns of this length, i.e., determine the number of n-bit sequences that contain no adjacent 1’s. For example, for n = 3 the answer is 5 (sequences 000, 001, 010, 100, 101 are acceptable while 011, 110, 111 are not).
Input
The first line contains the number of scenarios.
For each scenario, you are given a single positive integer less than 45 on a line by itself.
Output
The output for every scenario begins with a line containing “Scenario #i:”, where i is the number of the scenario starting at 1. Then print a single line containing the number of n-bit sequences which have no adjacent 1’s. Terminate the output for the scenario with a blank line.
Sample Input
2
3
1
Sample Output
Scenario #1:
5
Scenario #2:
2
注意结果int存不下。简单的动规,递推即可
#include <iostream>
#include <algorithm>
#include <string.h>
#include <stdlib.h>
#include <math.h>
using namespace std;
int n;
long long int dp[50][2];
int main()
{
int a;
while(scanf("%d",&a)!=EOF)
{
int cas=0;
while(a--)
{
memset(dp,0,sizeof(dp));
dp[1][0]=1;
dp[1][1]=1;
scanf("%d",&n);
for(int i=2;i<=n;i++)
{
dp[i][1]+=dp[i-1][0];
dp[i][0]+=(dp[i-1][0]+dp[i-1][1]);
}
printf("Scenario #%d:\n",++cas);
printf("%lld\n\n",dp[n][1]+dp[n][0]);
}
}
return 0;
}
POJ-1953 World Cup Noise(线性动规)的更多相关文章
- Poj 1953 World Cup Noise之解题报告
World Cup Noise Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 16369 Accepted: 8095 ...
- POJ 1953 World Cup Noise
World Cup Noise Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 14397 Accepted: 7129 ...
- poj 1953 World Cup Noise (dp)
World Cup Noise Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 16774 Accepted: 8243 ...
- poj - 1953 - World Cup Noise(dp)
题意:n位长的01序列(0 < n < 45),但不能出现连续的两个1,问序列有多少种. 题目链接:id=1953" target="_blank">h ...
- HOJ 2156 &POJ 2978 Colored stones(线性动规)
Colored stones Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 1759 Accepted: 829 Descrip ...
- POJ 1953 World Cup Noise(递推)
https://vjudge.net/problem/POJ-1953 题意:输入一个n,这n位数只由0和1组成,并且不能两个1相邻.计算共有多少种排列方法. 思路:递推题. 首先a[1]=2,a[2 ...
- POJ-1958 Strange Towers of Hanoi(线性动规)
Strange Towers of Hanoi Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 2677 Accepted: 17 ...
- POJ-1458 Common Subsequence(线性动规,最长公共子序列问题)
Common Subsequence Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 44464 Accepted: 18186 ...
- POJ--1050--To the Max(线性动规,最大子矩阵和)
To the Max Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 44723 Accepted: 23679 Descript ...
随机推荐
- 用VS2012不能打开VS2010的项目
应该是装过sql2012或者sql2008,自带的那个visual studio,你可以直接在外面打开VS2012,然后用里面的文件去打开项目.而不要直接双击那个解决方案的文件.
- mongo文件空间
mongo的文件空间,是由一个一个的文件空间组成,如下图 在mongodb刚安装完成时只有一个指定的db都只有一个文件空间而已,例如这里的db是filedb 那么他的第一个文件空间为filedb.0, ...
- SpringBoot------连接mysql时出现警告:Establishing SSL connection without server's identity verification is not recommended
SpringBoot连接MySQL时出现警告: 英文: Mon Jun :: CST WARN: Establishing SSL connection without server's identi ...
- spring学习之springMVC 返回类型选择 以及 SpringMVC中model,modelMap.request,session取值顺序
spring mvc处理方法支持如下的返回方式:ModelAndView, Model, ModelMap, Map,View, String, void.下面将对具体的一一进行说明: ModelAn ...
- UITextField中文输入法输入时对字符长度的限制 输入时对字符类型的限制
检索一个字符串的长度的话:直接用 length,去进行判断就行了, 如果要检索字符串是否是自己要限制的类型的话,可以用正则表达式: 举个例子: 匹配9-15个由字母/数字组成的字符串的正则表达式: ...
- iOS NSError
写在前面 在iOS开发中,NSError的使用非常常见,使用也比较简单,也正因为简单,所以对这一部分知识不甚注重.但是近期在做app底层网络封装时发现了一些问题.我使用的网络框架是AFNetworki ...
- Suggestion: add 'tools:replace="android:value"' to <meta-data> element at AndroidManifest.xml:25:5-27:41 to override.
记录下来少走些坑吧 一:不管用 tools:replace="android:icon,android:theme" xmlns:tools="http://schema ...
- lua总则
lua官方英文文档:http://www.lua.org/manual/5.2/ lua中国开发者网址:http://bbs.luaer.cn/ <lua程序设计(第二版)>(闭合函数和闭 ...
- iOS 事件的产生、传递、响应
一.事件的产生和传递 1.1.事件的产生 发生触摸事件后,系统会将该事件加入到一个由UIApplication管理的事件队列中为什么是队列而不是栈?因为队列的特定是先进先出,先产生的事件先处理才符合常 ...
- 转:ANDROID音频系统散记之四:4.0音频系统HAL初探
昨天(2011-11-15)发布了Android4.0的源码,今天download下来,开始挺进4.0时代.简单看了一下,发现音频系统方面与2.3的有较多地方不同,下面逐一描述. 一.代码模块位置 1 ...