POJ-1953 World Cup Noise(线性动规)
World Cup Noise
Time Limit: 1000MS Memory Limit: 30000K
Total Submissions: 16374 Accepted: 8097
Description
Background
“KO-RE-A, KO-RE-A” shout 54.000 happy football fans after their team has reached the semifinals of the FIFA World Cup in their home country. But although their excitement is real, the Korean people are still very organized by nature. For example, they have organized huge trumpets (that sound like blowing a ship’s horn) to support their team playing on the field. The fans want to keep the level of noise constant throughout the match.
The trumpets are operated by compressed gas. However, if you blow the trumpet for 2 seconds without stopping it will break. So when the trumpet makes noise, everything is okay, but in a pause of the trumpet,the fans must chant “KO-RE-A”!
Before the match, a group of fans gathers and decides on a chanting pattern. The pattern is a sequence of 0’s and 1’s which is interpreted in the following way: If the pattern shows a 1, the trumpet is blown. If it shows a 0, the fans chant “KO-RE-A”. To ensure that the trumpet will not break, the pattern is not allowed to have two consecutive 1’s in it.
Problem
Given a positive integer n, determine the number of different chanting patterns of this length, i.e., determine the number of n-bit sequences that contain no adjacent 1’s. For example, for n = 3 the answer is 5 (sequences 000, 001, 010, 100, 101 are acceptable while 011, 110, 111 are not).
Input
The first line contains the number of scenarios.
For each scenario, you are given a single positive integer less than 45 on a line by itself.
Output
The output for every scenario begins with a line containing “Scenario #i:”, where i is the number of the scenario starting at 1. Then print a single line containing the number of n-bit sequences which have no adjacent 1’s. Terminate the output for the scenario with a blank line.
Sample Input
2
3
1
Sample Output
Scenario #1:
5
Scenario #2:
2
注意结果int存不下。简单的动规,递推即可
#include <iostream>
#include <algorithm>
#include <string.h>
#include <stdlib.h>
#include <math.h>
using namespace std;
int n;
long long int dp[50][2];
int main()
{
int a;
while(scanf("%d",&a)!=EOF)
{
int cas=0;
while(a--)
{
memset(dp,0,sizeof(dp));
dp[1][0]=1;
dp[1][1]=1;
scanf("%d",&n);
for(int i=2;i<=n;i++)
{
dp[i][1]+=dp[i-1][0];
dp[i][0]+=(dp[i-1][0]+dp[i-1][1]);
}
printf("Scenario #%d:\n",++cas);
printf("%lld\n\n",dp[n][1]+dp[n][0]);
}
}
return 0;
}
POJ-1953 World Cup Noise(线性动规)的更多相关文章
- Poj 1953 World Cup Noise之解题报告
World Cup Noise Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 16369 Accepted: 8095 ...
- POJ 1953 World Cup Noise
World Cup Noise Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 14397 Accepted: 7129 ...
- poj 1953 World Cup Noise (dp)
World Cup Noise Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 16774 Accepted: 8243 ...
- poj - 1953 - World Cup Noise(dp)
题意:n位长的01序列(0 < n < 45),但不能出现连续的两个1,问序列有多少种. 题目链接:id=1953" target="_blank">h ...
- HOJ 2156 &POJ 2978 Colored stones(线性动规)
Colored stones Time Limit: 1000MS Memory Limit: 65536K Total Submissions: 1759 Accepted: 829 Descrip ...
- POJ 1953 World Cup Noise(递推)
https://vjudge.net/problem/POJ-1953 题意:输入一个n,这n位数只由0和1组成,并且不能两个1相邻.计算共有多少种排列方法. 思路:递推题. 首先a[1]=2,a[2 ...
- POJ-1958 Strange Towers of Hanoi(线性动规)
Strange Towers of Hanoi Time Limit: 1000MS Memory Limit: 30000K Total Submissions: 2677 Accepted: 17 ...
- POJ-1458 Common Subsequence(线性动规,最长公共子序列问题)
Common Subsequence Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 44464 Accepted: 18186 ...
- POJ--1050--To the Max(线性动规,最大子矩阵和)
To the Max Time Limit: 1000MS Memory Limit: 10000K Total Submissions: 44723 Accepted: 23679 Descript ...
随机推荐
- iis7错误提示An error occurred on the server when processing the URL...
win7下面运行ASP程序总是出错,原来是站点配置的问题... 问题一:MS Jet引擎改变了临时目录的位置,但是又没有对临时目录的存取权限,导致数据库使用失败(因为sql问题,后改用access数据 ...
- [CNN] What is Convolutional Neural Network
Ref: 从LeNet-5看卷积神经网络CNNs 关于这篇论文的一些博文的QAC: 1. 基本原理 MLP(Multilayer Perceptron,多层感知器)是一种前向神经网络(如下图所示),相 ...
- NetBpm如何指定下一流程处理人(8)
NETBPM如何指定下一流程处理人 本着“软件以应用为本”(潘加宇老师对我的影响在这一点上很深.)的原则,我为ERP搭建了一个用NETBPM作的支持网站,想着能够看着软件得以应用,自是非常高兴. 不过 ...
- flexbox子盒子align-self属性
<!DOCTYPE html> <html lang="en"> <head> <meta charset="UTF-8&quo ...
- Django 配置
Django 配置 运行 django-admin.py startproject [project-name] 命令会生成一系列文件,在Django 1.6版本以后的 settings.py 文 ...
- openjdk源码阅读
http://rednaxelafx.iteye.com/blog/1549577 http://blog.csdn.net/fancyerii/article/details/7007503 ├—a ...
- Linux chmod和chown更改文件目录的所属者命令的用法
一.chown 命令 用途:更改文件的所有者或组.命令由单词change owner组合而成. 使用示例: 1,更改文件的所有者: chown jim program.c 文件 program.c 的 ...
- 自定义 Core Data 迁移
本文转载至 http://objccn.io/issue-4-7/ 感谢本文作者 朱宏旭 的不啬分享 自定义 Core Data 迁移似乎是一个不太起眼的话题.苹果在这方面只提供了很少的文档,若是初次 ...
- 【技术分享会】 @第二期 微信开放API简述-0212
什么是微信开放平台? 微信开放平台作为第三方移动程序提供接口,使用户可将第三方程序的内容发布给好友或分享至朋友圈,第三方内容借助微信平台获得更广泛的传播.从而形成了一种主流的线上线下微信互动营销方式. ...
- 【Drools-开源业务规则引擎】入门实例(含源码)
该实例转自:http://blog.csdn.net/quzishen/article/details/6163012 便于理解的应用实例1: 现在我们模拟一个应用场景:网站伴随业务产生而进行的积分发 ...