LeetCode: Binary Tree Maximum Path Sum 解题报告
Binary Tree Maximum Path Sum
Given a binary tree, find the maximum path sum.
The path may start and end at any node in the tree.
For example:
Given the below binary tree,
1
/ \
2 3

SOLUTION 1:
计算树的最长path有2种情况:
1. 通过根的path.
(1)如果左子树从左树根到任何一个Node的path大于零,可以链到root上
(2)如果右子树从右树根到任何一个Node的path大于零,可以链到root上
2. 不通过根的path. 这个可以取左子树及右子树的path的最大值。
所以创建一个inner class:
记录2个值:
1. 本树的最大path。
2. 本树从根节点出发到任何一个节点的最大path.
注意,当root == null,以上2个值都要置为Integer_MIN_VALUE; 因为没有节点可取的时候,是不存在solution的。以免干扰递归的计算
/**
* Definition for binary tree
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class Solution {
public class ReturnType {
int maxSingle;
int max;
ReturnType (int maxSingle, int max) {
this.max = max;
this.maxSingle = maxSingle;
}
} public int maxPathSum(TreeNode root) {
return dfs(root).max;
} public ReturnType dfs(TreeNode root) {
ReturnType ret = new ReturnType(Integer.MIN_VALUE, Integer.MIN_VALUE);
if (root == null) {
return ret;
} ReturnType left = dfs(root.left);
ReturnType right = dfs(root.right); int cross = root.val; // if any of the path of left and right is below 0, don't add it.
cross += Math.max(0, left.maxSingle);
cross += Math.max(0, right.maxSingle); // 注意,这里不可以把Math.max(left.maxSingle, right.maxSingle) 与root.val加起来,
// 会有可能越界!
int maxSingle = Math.max(left.maxSingle, right.maxSingle); // may left.maxSingle and right.maxSingle are below 0
maxSingle = Math.max(maxSingle, 0);
maxSingle += root.val; ret.maxSingle = maxSingle;
ret.max = Math.max(right.max, left.max);
ret.max = Math.max(ret.max, cross); return ret;
}
}
GITHUB:
https://github.com/yuzhangcmu/LeetCode_algorithm/blob/master/tree/MaxPathSum.java
LeetCode: Binary Tree Maximum Path Sum 解题报告的更多相关文章
- 【LeetCode】124. Binary Tree Maximum Path Sum 解题报告 (C++)
作者: 负雪明烛 id: fuxuemingzhu 个人博客:http://fuxuemingzhu.cn/ 目录 题目描述 题目大意 解题方法 递归 日期 题目地址:https://leetcode ...
- [leetcode]Binary Tree Maximum Path Sum
Binary Tree Maximum Path Sum Given a binary tree, find the maximum path sum. The path may start and ...
- 二叉树系列 - 二叉树里的最长路径 例 [LeetCode] Binary Tree Maximum Path Sum
题目: Binary Tree Maximum Path Sum Given a binary tree, find the maximum path sum. The path may start ...
- [leetcode]Binary Tree Maximum Path Sum @ Python
原题地址:https://oj.leetcode.com/problems/binary-tree-maximum-path-sum/ 题意: Given a binary tree, find th ...
- [LeetCode] Binary Tree Maximum Path Sum 求二叉树的最大路径和
Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. ...
- leetcode–Binary Tree Maximum Path Sum
1.题目说明 Given a binary tree, find the maximum path sum. The path may start and end at any node in t ...
- C++ leetcode Binary Tree Maximum Path Sum
偶然在面试题里面看到这个题所以就在Leetcode上找了一下,不过Leetcode上的比较简单一点. 题目: Given a binary tree, find the maximum path su ...
- [LeetCode] Binary Tree Maximum Path Sum(最大路径和)
Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. ...
- [Leetcode] Binary tree maximum path sum求二叉树最大路径和
Given a binary tree, find the maximum path sum. The path may start and end at any node in the tree. ...
随机推荐
- easymock快速入门
easymock是众多mock之中的很容易用的mock,今天刚开始学习,来个简单的教程.以购物车结算为例子,比如首先是每一个商品项的pojo. public class Item { private ...
- nginx init 官方启动脚本
#!/bin/sh # # nginx - this script starts and stops the nginx daemon # # chkconfig: - 85 15 # descrip ...
- 安卓listView实现下拉刷新上拉加载滑动仿QQ的删除功能
大家对这些功能都是看的多了,然后对上拉刷新和下拉加载的原理都是非常清楚的,所以实现这功能其实也就是为了让大家能够从众多的同行们来进行比较学习而已,虽然即使是这样,但是面试的时候面试官还是会问你上拉和下 ...
- .NET压缩图片保存 .NET CORE WebApi Post跨域提交 C# Debug和release判断用法 tofixed方法 四舍五入 (function($){})(jQuery); 使用VUE+iView+.Net Core上传图片
.NET压缩图片保存 需求: 需要将用户后买的图片批量下载打包压缩,并且分不同的文件夹(因:购买了多个用户的图片情况) 文章中用到了一个第三方的类库,Nuget下载 SharpZipLib 目前用 ...
- 【Android】图片切角,切指定的边。
公司的项目,UI和应用都是我自己做的.前几天设计了一个UI,出现了半边圆角的情况,如下图片所示.图片都来自服务器,肯定不能要求返回的图片按这个格式,必须在应用端对图片进行切角. Google了好久,发 ...
- DCM 图片查看
因为要处理一些医学图像,需要把dcm格式的文件转换成jpg格式.本来用Sante DICOM Editor用得挺好的,方便查看dcm文件,但是在转换上每次只能转一张(本人没有找到用该软件批量转格式的方 ...
- Java 8 flatMap example
Java 8 flatMap example In Java 8, Stream can hold different data types, for examples: Stream<Stri ...
- Java 8 – Filter a null value from a Stream
Java 8 – Filter a null value from a Stream package com.mkyong.java8; import java.util.List;import ja ...
- python selenium 使用unittest 示例
python selenium 使用unittest 示例 并等待某个元素示例 from selenium.webdriver.support.ui import WebDriverWait from ...
- ubuntu14安装redis
1.下载源文件 wget http://download.redis.io/releases/redis-3.0.7.tar.gz 2.解压 tar vxzf redis-3.0.7.tar.gz 3 ...