Borrowers UVA - 230
I mean your borrowers of books — those mutilators of collections, spoilers of the symmetry of shelves, and creators of odd volumes.
– (Charles Lamb, Essays of Elia (1823) ‘The Two Races of Men’)
Like Mr. Lamb, librarians have their problems with borrowers too. People don’t put books back where they should. Instead, returned books are kept at the main desk until a librarian is free to replace them in the right places on the shelves. Even for librarians, putting the right book in the right place can be very time-consuming. But since many libraries are now computerized, you can write a program to help.
When a borrower takes out or returns a book, the computer keeps a record of the title. Periodically, the librarians will ask your program for a list of books that have been returned so the books can be returned to their correct places on the shelves. Before they are returned to the shelves, the returned books are sorted by author and then title using the ASCII collating sequence. Your program should output the list of returned books in the same order as they should appear on the shelves. For each book, your program should tell the librarian which book (including those previously shelved) is already on the shelf before which the returned book should go.
Input
First, the stock of the library will be listed, one book per line, in no particular order. Initially, they are all on the shelves. No two books have the same title. The format of each line will be:
"title" by author
The end of the stock listing will be marked by a line containing only the word:
END
Following the stock list will be a series of records of books borrowed and returned, and requests from librarians for assistance in restocking the shelves. Each record will appear on a single line, in one of the following formats:
BORROW title
RETURN title
SHELVE
The list will be terminated by a line containing only the word:
END
Output
Each time the SHELVE command appears, your program should output a series of instructions for the librarian, one per line, in the format:
Put title1 after title2 or, for the special case of the book being the first in the collection:
Put title first
After the set of instructions for each SHELVE, output a line containing only the word:
END
Assumptions & Limitations:
1. A title is at most 80 characters long.
2. An author is at most 80 characters long.
3. A title will not contain the double quote (") character.
Sample Input
"The Canterbury Tales" by Chaucer, G.
"The Canterbury Taless" by Chaucer, B.
"Algorithms" by Sedgewick, R.
"The C Programming Language" by Kernighan, B. and Ritchiee, D.
"The C Programming Languag" by Kernighan, B. and Ritchiee, D.
"The D Programming Language" by Kernighan, B. and Ritchiee, D.
"A House for Mr. Biswas" by Naipaul, V.S.
"A Congo Diary" by Naipaul, V.S.
END
BORROW "Algorithms"
BORROW "The C Programming Language"
BORROW "The C Programming Languag"
BORROW "The Canterbury Taless"
SHELVE
RETURN "Algorithms"
RETURN "The Canterbury Taless"
SHELVE
RETURN "The C Programming Languag"
SHELVE
BORROW "The C Programming Languag"
BORROW "The Canterbury Taless"
BORROW "A House for Mr. Biswas"
RETURN "The Canterbury Taless"
SHELVE
RETURN "The C Programming Language"
RETURN "A House for Mr. Biswas"
SHELVE
END
Sample Output
Put "The C Programming Language" after "The Canterbury Tales"
Put "Algorithms" after "The C Programming Language"
END
HINT
使用结构体数组进行操作。定义一个结构体,成员为头作者和书名两个字符串。排序使用sort(),但要自己定义排序方法。另外,借出书籍的时候,要想定位并删除此元素要自己定义一个指针,使用find()函数无法对结构体进行比较,在结构体里面重载运算符应该是可以的,但小白表示不会。。。所以定义一个auto指针来查找。因为输出书名需要双引号所以存入就不去除双引号了。
整体的框架很好理解,录入书籍整行读取,然后分割书名和作者。然后读入指令,对指令区分操作,小细节还是比较多的,具体看代码。
#include<bits/stdc++.h>
using namespace std;
struct books {
string title; //书名
string name; //作者
};
bool compare(books a, books b) { //自定义的排序方法,用于sort
if (a.name == b.name)return a.title < b.title;
return a.name < b.name;
}
int main(){
vector<books>list; //目前书架上的书籍
vector<books>ret; //归还的书籍
map<string, string>alllist; //存储书籍副本
string s,title;books temp;
while (getline(cin, s) && s != "END") { //录入书籍信息
int i=s.find('\"',1); //对书籍进行分割
temp.title = s.substr(0, i+1);
temp.name = s.substr(i + 1, s.size() - 1);
list.push_back(temp); //存入数组并且保存map副本
alllist[temp.title] = temp.name;
}
while (cin>>s&&s!="END"){
if (s == "SHELVE") { //对未上架的图书上架处理
sort(ret.begin(), ret.end(), compare); //排序
for (int i = 0;i < ret.size();i++) { //挨个书籍处理
temp = ret[i];
list.push_back(temp); //上架
sort(list.begin(), list.end(), compare);//排序
for (int i = 0;i < list.size();i++) { //查找并输出
if (list[i].name == temp.name && list[i].title == temp.title) {
if(i==0)cout << "Put " << temp.title << " first" << endl;
else cout << "Put " << temp.title << " after " << list[i-1].title << endl;
break;
}
}
}
ret.clear(); //每次输出完毕必须清空记录,一面影响下一次的使用
cout << "END" << endl;
}
else {
getchar(); //吃掉空格
getline(cin, title);//读入标题
temp.title = title; //保存到临时结构体
temp.name = alllist[title];
if (s == "BORROW") {
auto pointer = list.begin();//本来使用find()函数不会重载所以自己定义指针查找
while (!((*pointer).title == temp.title))pointer++;
list.erase(pointer); //删除
}
else if (s == "RETURN")ret.push_back(temp);//记录还书信息
}
}
}
Borrowers UVA - 230的更多相关文章
- uva 230 Borrowers(摘)<vector>"结构体“ 膜拜!
I mean your borrowers of books--those mutilators of collections, spoilers of the symmetry of shelves ...
- UVa 230 Borrowers(map和set)
I mean your borrowers of books - those mutilators of collections, spoilers of the symmetry of shelve ...
- Uva - 230 - Borrowers
AC代码: #include <iostream> #include <cstdio> #include <cstdlib> #include <cctype ...
- UVA 230 Borrowers (STL 行读入的处理 重载小于号)
题意: 输入若干书籍和作者名字,然后先按作者名字升序排列,再按标题升序排列,然后会有3种指令,BORROW,RETURN, SHELVE. BORROW 和 RETURN 都会带有一个书名在后面,如: ...
- 【习题 5-8 UVA - 230】Borrowers
[链接] 我是链接,点我呀:) [题意] 在这里输入题意 [题解] 用map+set写个模拟就好. 3个区域 书架.桌子.别人的手上. 其中前两个区域的书都能借出去. [代码] #include &l ...
- UVa 1640 (计数) The Counting Problem
题意: 统计[a, b]或[b, a]中0~9这些数字各出现多少次. 分析: 这道题可以和UVa 11361比较来看. 同样是利用这样一个“模板”,进行区间的分块,加速运算. 因为这里没有前导0,所以 ...
- UVA 10194 (13.08.05)
:W Problem A: Football (aka Soccer) The Problem Football the most popular sport in the world (ameri ...
- UVa 1640 - The Counting Problem(数论)
链接: https://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&page=show_problem& ...
- Fast Matrix Operations(UVA)11992
UVA 11992 - Fast Matrix Operations 给定一个r*c(r<=20,r*c<=1e6)的矩阵,其元素都是0,现在对其子矩阵进行操作. 1 x1 y1 x2 y ...
随机推荐
- IntelliJ IDEA 还能画思维导图,果然最强 IDE!
最近栈长发现 IntelliJ IDEA 居然还能画思维导图,太牛逼了! 当然这得借助 IDEA 的 UML 插件,因为它本身也是一个 UML 图,所以这篇就从 UML 图开撕,看 IDEA 怎么画思 ...
- C语言柔性数组和动态数组
[前言]经常看到C语言里的两个数组,总结一下. 一.柔性数组 参考:https://www.cnblogs.com/veis/p/7073076.html #include<stdio.h> ...
- tesseract-ocr和tesseract.exe is not installed or it's not in your path问题解决
一.解决方案: 1.http://www.ddooo.com/softdown/94968.htm 打开下载的压缩包,找到"tesseract-ocr-setup-3.02.02.exe ...
- Android - 利用扩展函数为Bitmap添加文字水印
<异空间>项目技术分享系列--扩展函数为Bitmap添加文字水印 对图片Bitmap绘制文字水印还是比较常见的需求,毕竟版权意识都在增强(用户可以给自己图片加上用户名),还可以为用户提供更 ...
- 《C++ Primer》笔记 第3章 字符串、向量和数组
位于头文件的代码一般来说不应该使用using声明. 如果使用等号(=)初始化一个变量,实际上执行的是拷贝初始化,编译器把等号右侧的初始值拷贝到新创建的对象中去.与之相反,如果不使用等号,则执行的是直接 ...
- CodeBlocks的安装配置以及使用教程
CodeBlocks的安装配置以及使用教程 教程写的很啰嗦,本来几句话就能搞定的,但为了照顾到那部分真正的小白还请大家见谅! 一.下载 前往CodeBlocks官网下载带编译器的版本,目前的最新版本为 ...
- Java I/O流 03
I/O流·字符流 字符流FileReader * A:字符流是什么 * 字符流是可以直接读写字符的 IO流 * 字符流读取字符,就要先读取到字节数据,然后转换为字符:如果要写出字符,需要把字符转换为字 ...
- MyBatis(三):自定义持久层框架实现
代码已上传至码云:https://gitee.com/rangers-sun/mybatis 新建Maven工程 架构端MyPersistent.使用端MyPersistentTest,使用端引入架构 ...
- slickgrid ( nsunleo-slickgrid ) 5 增加子件
slickgrid ( nsunleo-slickgrid ) 5 增加子件 上次把单元格切换的问题解决了,这次要最做的事情就是给slickgrid的treegird增加子件,我们先选中某一条记录,然 ...
- python爬虫加定时任务,制作微信提醒备忘录
一.任务的记录与提取 1.1 制作每日任务 为了便于爬取,推荐使用网页版的在线记事本,现在这种工具很多,我选择"石墨文档"进行操作演示.记录内容的 格式可以根据自己的需求和爬虫自行 ...