LeetCode - 1. Two Sum(8ms)

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

class Solution {
public:
    vector<int> twoSum(vector<int>& nums, int target) {
        int n = nums.size();
        map<int, int> m;
        for(int i=; i<n; i++) {
            int temp = target - nums[i];
            map<int, int>::iterator it = m.find(temp);
            if(it != m.end()) {
                return vector<int> {it->second, i};
            }
            m[nums[i]] = i;
        }
    }
};