【hihocoder 1562】⼩Hi的钟表

【链接】点击打开链接

【题意】

在这里写题意

【题解】

时针每过1分钟转0.5°.

(360/(12*60))

分钟每过1分钟转6°

(360/60);

根据这个就能算出时针和分针的角度之差了.

【错的次数】

0

【反思】

在这了写反思

【代码】

#include <cstdio>
#include <iostream>
#include <algorithm>
#include <cstring>
#include <vector>
#include <map>
#include <queue>
#include <iomanip>
#include <set>
#include <cstdlib>
#include <cmath>
using namespace std;
#define lson l,m,rt<<1
#define rson m+1,r,rt<<1|1
#define LL long long
#define rep1(i,a,b) for (int i = a;i <= b;i++)
#define rep2(i,a,b) for (int i = a;i >= b;i--)
#define mp make_pair
#define pb emplace_back
#define fi first
#define se second
#define ld long double
#define ms(x,y) memset(x,y,sizeof x)
#define ri(x) scanf("%d",&x)
#define rl(x) scanf("%lld",&x)
#define rs(x) scanf("%s",x)
#define rf(x) scnaf("%lf",&x)
#define oi(x) printf("%d",x)
#define ol(x) printf("%lld",x)
#define oc putchar(' ')
#define os(x) printf(x)
#define all(x) x.begin(),x.end()
#define Open() freopen("F:\\rush.txt","r",stdin)
#define Close() ios::sync_with_stdio(0)
#define sz(x) ((int) x.size())
#define ld long double

typedef pair<int,int> pii;
typedef pair<LL,LL> pll;

//mt19937 myrand(time(0));
//int get_rand(int n){return myrand()%n + 1;}
const int dx[9] = {0,1,-1,0,0,-1,-1,1,1};
const int dy[9] = {0,0,0,-1,1,-1,1,-1,1};
const double pi = acos(-1.0);
const int N = 110;

int h,m,s,t;

int main(){
    //Open();
    //Close();
    int T;
    ri(T);
    while (T--){
        ri(h),ri(m),ri(s);
        ri(t);
		t = t % 86400;
		s = s + t;
		if (s >= 60) {
			m += s / 60;
			s %= 60;
			if (m >= 60) {
				h += m / 60;
				m %= 60;
				if (h >= 24) {
					h %= 24;
				}
			}
		}

        if (h >= 12) h -= 12;
        double s1 = (s/60.0)*0.5 + 1.0*m*0.5 + h*30;
        double s2 = (s/60.0)*6.0 + m*6.0;
        double temp = abs(s1-s2);
        printf("%.4f\n",min(360-temp,temp));
    }
    return 0;
}