The API: int read4(char *buf) reads 4 characters at a time from a file.

The return value is the actual number of characters read. For example, it returns 3 if there is only 3 characters left in the file.

By using the read4 API, implement the function int read(char *buf, int n) that reads n characters from the file.

Note:
The read function may be called multiple times.

 /* The read4 API is defined in the parent class Reader4.
int read4(char[] buf); */ public class Solution extends Reader4 {
/**
* @param buf Destination buffer
* @param n Maximum number of characters to read
* @return The number of characters read
*/
private char[] tmp = new char[4];
private int tmpPoint; //indicate which position we should start reading
private int tmpContain;//indicate how many char in the tmp buff
public int read(char[] buf, int n) {
int cur = 0;
while(cur < n){
if(tmpPoint == 0){
tmpContain = read4(tmp);
}
if(tmpContain == 0){
return cur;
}
while(cur < n && tmpPoint < tmpContain){
buf[cur ++] = tmp[tmpPoint ++];
}
tmpPoint = tmpPoint % tmpContain;
}
return cur;
}
}

Read N Characters Given Read4 II - Call multiple times的更多相关文章

  1. [Locked] Read N Characters Given Read4 & Read N Characters Given Read4 II - Call multiple times

    Read N Characters Given Read4 The API: int read4(char *buf) reads 4 characters at a time from a file ...

  2. [LeetCode] Read N Characters Given Read4 II - Call multiple times 用Read4来读取N个字符之二 - 多次调用

    The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actu ...

  3. LeetCode Read N Characters Given Read4 II - Call multiple times

    原题链接在这里:https://leetcode.com/problems/read-n-characters-given-read4-ii-call-multiple-times/ 题目: The ...

  4. 【LeetCode】158. Read N Characters Given Read4 II - Call multiple times

    Difficulty: Hard  More:[目录]LeetCode Java实现 Description Similar to Question [Read N Characters Given ...

  5. ✡ leetcode 158. Read N Characters Given Read4 II - Call multiple times 对一个文件多次调用read(157题的延伸题) --------- java

    The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actu ...

  6. 158. Read N Characters Given Read4 II - Call multiple times

    题目: The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the ...

  7. [leetcode]158. Read N Characters Given Read4 II - Call multiple times 用Read4读取N个字符2 - 调用多次

    The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actu ...

  8. leetcode[158] Read N Characters Given Read4 II - Call multiple times

    想了好一会才看懂题目意思,应该是: 这里指的可以调用更多次,是指对一个文件多次操作,也就是对于一个case进行多次的readn操作.上一题是只进行一次reandn,所以每次返回的是文件的长度或者是n, ...

  9. Leetcode-Read N Characters Given Read4 II

    The API: int read4(char *buf) reads 4 characters at a time from a file. The return value is the actu ...

随机推荐

  1. Gitlab+Jenkins学习之路(十一)之Jenkins自动触发构建和发布

    思路图: 一.下载gitlab plugin jenkins-->系统管理-->管理插件-->下载并安装gitlab plugin 二.配置gitlab认证 路径:Jenkins-- ...

  2. Quartz可以用来做什么

    废话的前言 以前凭借年轻,凡事都靠脑记.现在工作几年后发现,很多以前看过.用过的东西,再次拿起的时候总觉得记不牢靠."好记性不如烂笔头"应该是某位上了年纪的大叔的切肤之痛(仅次于上 ...

  3. CodeForces 985D Sand Fortress

    Description You are going to the beach with the idea to build the greatest sand castle ever in your ...

  4. 在eclipse中运行spring web application时的异常: java.lang.ClassNotFoundException: org.springframework.web.context.ContextLoaderListener

    严重: Error configuring application listener of class org.springframework.web.context.ContextLoaderLis ...

  5. xaf.domain object new 在属性上的用法

    有如下业务对象定义: using System; using System.Linq; using System.Text; using DevExpress.Xpo; using DevExpres ...

  6. Mac os x 配置maven

    安装Maven 1.压缩包apache-maven-3.3.9-bin.zip 2.解压压缩包到指定文件 3.打开终端,输入以下命令,编辑环境变量文件:bash_proflie open .bash_ ...

  7. Unity优化方向——优化Unity游戏中的图形渲染(译)

    CPU bound:CPU性能边界,是指CPU计算时一直处于占用率很高的情况. GPU bound:GPU性能边界,同样的是指GPU计算时一直处于占用率很高的情况. 原文:https://unity3 ...

  8. OpenFastPath(1):快平面接口是否支持多ip

    1.配置环境 fp0接口上配置两个IP地址: fp0       Link encap:Ethernet  HWaddr 00:0c:29:30:38:db inet addr:192.168.56. ...

  9. AssertionError

    (1)p1 = multiprocessing.Process(test1)p2 = multiprocessing.Process(target=test2) 错误: p1缺少target,应为(t ...

  10. Docker 在Windows上的安装

    1. 软件从Docker官网下载,进行安装,安装后,能看到如下界面. 2. 安装后,查看Docker 版 本信息. 3. 配置加速器 (1)选择setting. (2)依次选择,并填写自己的加速器地址 ...