[LC] 131. Palindrome Partitioning
Given a string s, partition s such that every substring of the partition is a palindrome.
Return all possible palindrome partitioning of s.
Example:
Input: "aab"
Output:
[
["aa","b"],
["a","a","b"]
]
class Solution {
public List<List<String>> partition(String s) {
List<List<String>> res = new ArrayList<>();
List<String> list = new ArrayList<>();
helper(res, list, 0, s);
return res;
}
private void helper(List<List<String>> res, List<String> list, int level, String s) {
if (level == s.length()) {
res.add(new ArrayList<>(list));
return;
}
for (int i = level; i < s.length(); i++) {
if (isPalin(s, level, i)) {
list.add(s.substring(level, i + 1));
helper(res, list, i + 1, s);
list.remove(list.size() - 1);
}
}
}
private boolean isPalin(String s, int start, int end) {
while (start < end) {
if (s.charAt(start) != s.charAt(end)) {
return false;
}
start += 1;
end -= 1;
}
return true;
}
}
[LC] 131. Palindrome Partitioning的更多相关文章
- leetcode 131. Palindrome Partitioning 、132. Palindrome Partitioning II
131. Palindrome Partitioning substr使用的是坐标值,不使用.begin()..end()这种迭代器 使用dfs,类似于subsets的题,每次判断要不要加入这个数 s ...
- Leetcode 22. Generate Parentheses Restore IP Addresses (*) 131. Palindrome Partitioning
backtracking and invariant during generating the parathese righjt > left (open bracket and cloas ...
- Leetcode 131. Palindrome Partitioning
Given a string s, partition s such that every substring of the partition is a palindrome. Return all ...
- 131. Palindrome Partitioning
题目: Given a string s, partition s such that every substring of the partition is a palindrome. Return ...
- 78. Subsets(M) & 90. Subsets II(M) & 131. Palindrome Partitioning
78. Subsets Given a set of distinct integers, nums, return all possible subsets. Note: The solution ...
- [leetcode]131. Palindrome Partitioning字符串分割成回文子串
Given a string s, partition s such that every substring of the partition is a palindrome. Return all ...
- 【LeetCode】131. Palindrome Partitioning
Palindrome Partitioning Given a string s, partition s such that every substring of the partition is ...
- 131. Palindrome Partitioning (Back-Track, DP)
Given a string s, partition s such that every substring of the partition is a palindrome. Return all ...
- 131. Palindrome Partitioning(回文子串划分 深度优先)
Given a string s, partition s such that every substring of the partition is a palindrome. Return all ...
随机推荐
- Sequence Models Week 3 Trigger word detection
Trigger Word Detection Welcome to the final programming assignment of this specialization! In this w ...
- 使用文件流创建File文件和目录以及其他的一些操作
我们创建文件时可以直接通过File f=new File(path)来创建一个文件对象,然后再通过 f.createNewFile() 就创建出来了一个文件.比如设置 path 为 C:\Users\ ...
- 代码review还是需要再仔细点-一次crash异常分析的总结
版本发布之后,外网新增了一些crash, 从mini dump看,的确是有异常的,619行crash了. 代码如下: 奔溃的地方如下 可以看到是Zip add的时候指针空了, 为什么呢? 结合代码,可 ...
- Spring中的控制反转和依赖注入
Spring中的控制反转和依赖注入 原文链接:https://www.cnblogs.com/xxzhuang/p/5948902.html 我们回顾一下计算机的发展史,从最初第一台计算机的占地面积达 ...
- 微信小程序自定义分享封面
onShareAppMessage:function(options){ let thas = this; if (options.from === 'button') { // 来自页面内转发按钮 ...
- 监听home键的广播
public class HomeKeyReceiver extends BroadcastReceiver implements SanbotConstants{ private HomeKeyLi ...
- tomcat用户配置
1.tomcat-user.xml 添加以下内容<role rolename="manager-gui"/> <role rolename="manag ...
- proto3 不支持内建类型的非空判断即 hasXXX
proto3 移除了内建类型的非空判断方法 即代码生成工具不会为 bool int 等类型生成has方法 有使用过proto2 或者其它rpc 框架的人都知道使用has 方法去判断消息里的值是否设置, ...
- 19 docker 多机器通信
1. 本章实验 2. 环境搭建 1.编写 Vagrantfile 并创建虚拟机 并虚拟机node1绑定外部 192.168.205.10:8888 node2绑定外部 192.168.205.10:9 ...
- C++内联函数作用及弊端
为什么要使用内联函数? 因为函数调用时候需要创建时间.参数传入传递等操作,造成了时间和空间的额外开销.C++追求效率所以引入了内联的概念. 通过编译器预处理,在调用内联函数的地方将内联函数内的语句Co ...