详见:https://leetcode.com/problems/license-key-formatting/description/

C++:

class Solution {
public:
string licenseKeyFormatting(string S, int K)
{
string res = "";
int cnt = 0, n = S.size();
for (int i = n - 1; i >= 0; --i)
{
char c = S[i];
if (c == '-')
{
continue;
}
if (c >= 'a' && c <= 'z')
{
c -= 32;
}
res.push_back(c);
if (++cnt % K == 0)
{
res.push_back('-');
}
}
if (!res.empty() && res.back() == '-')
{
res.pop_back();
}
return string(res.rbegin(), res.rend());
}
};

参考:https://www.cnblogs.com/grandyang/p/6277972.html

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